$a)\frac{9}{11}$ và $\frac{13}{15}$

Ta có :

$1-\frac{9}{11}=\frac{2}{11}$

$1-\frac{13}{15}=\frac{2}{15}$

Mà $\frac{2}{11}>\frac{2}{15}$ nên $\frac{9}{11}<\frac{13}{15}$

$b)\frac{19}{15}$ và $\frac{15}{11}$

Ta có :

$\frac{19}{15}-1=\frac{4}{15}$

$\frac{15}{11}-1=\frac{4}{11}$

Mà $\frac{4}{15}<\frac{4}{11}$ nên $\frac{19}{15}<\frac{15}{11}$

$c)\frac{201}{301}$ và 

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2019/2020 < 3/2  vì 3/2 > 1 và  2019/2020 < 1              197/198 < 1 vì 197 < 198                9/11 > 3/15 vì ta có 9/15 và vì 9/11 > 9/15 > 3/15     201/301 > 199/308 vì ta có 199/301 và vì 201/301 >199/301 >199/308                    19/15  <. 15/11 VÌ 19/15 = 1 VÀ 4/15 .15/11 = 1 và 4/11 vì 4/15 < 4/11                 1212/1313 = 12/13 vì 1212/1313 = 12/13 

\(a,\dfrac{199}{200}=1-\dfrac{1}{200};\dfrac{200}{201}=1-\dfrac{1}{201}\\ Vì:\dfrac{1}{200}>\dfrac{1}{201}\\ \Rightarrow1-\dfrac{1}{200}< 1-\dfrac{1}{201}\\ Vậy:\dfrac{199}{200}< \dfrac{200}{201}\\ b,\dfrac{2001}{2002}=1-\dfrac{1}{2002};\dfrac{2002}{2003}=1-\dfrac{1}{2003}\\ Vì:\dfrac{1}{2002}>\dfrac{1}{2003}\Rightarrow1-\dfrac{1}{2002}< 1-\dfrac{1}{2003}\\ Vậy:\dfrac{2001}{2002}< \dfrac{2002}{2003}\)

\(c,\dfrac{2021}{2020}=1+\dfrac{1}{2020};\dfrac{2020}{2019}=1+\dfrac{1}{2019}\\ Vì:\dfrac{1}{2020}< \dfrac{1}{2019}\\ Nên:1+\dfrac{1}{2020}< 1+\dfrac{1}{2019}\\ Vậy:\dfrac{2021}{2020}< \dfrac{2020}{2019}\\ d,\dfrac{199}{198}=1+\dfrac{1}{198};\dfrac{200}{199}=1+\dfrac{1}{199}\\ Vì:\dfrac{1}{198}>\dfrac{1}{199}\\ Nên:1+\dfrac{1}{198}>1+\dfrac{1}{199}\\ Vậy:\dfrac{199}{198}>\dfrac{200}{199}\)

Bài 2: 

a: Ta có: \(\dfrac{9}{11}=1-\dfrac{2}{11}\)

\(\dfrac{13}{15}=1-\dfrac{2}{15}\)

mà \(-\dfrac{2}{11}< -\dfrac{2}{15}\)

nên \(\dfrac{9}{11}< \dfrac{13}{15}\)

b: Ta có: \(\dfrac{19}{15}=1+\dfrac{4}{15}\)

\(\dfrac{15}{11}=1+\dfrac{4}{11}\)

mà \(\dfrac{4}{15}< \dfrac{4}{11}\)

nên \(\dfrac{19}{15}< \dfrac{15}{11}\)

2 câu kia đâu rùi

Bài 2: 

a: Ta có: 1315=1−2151315=1−215

mà 911<1315911<1315

b: Ta có: 1511=1+4111511=1+411

mà 1915<1511

a: 9/11=1-2/11

11/13=1-2/13

mà -2/11<-2/13

nên 9/11<11/13

b: 19/15=1+4/15

15/11=1+4/11

mà 4/15<4/11

nên 19/15<15/11

a) Ta có:

\(1-\frac{9}{11}=\frac{11-9}{11}=\frac{2}{11}\)

\(1-\frac{13}{15}=\frac{15-13}{15}=\frac{2}{15}\)

Vì \(\frac{2}{15}< \frac{2}{11}\Rightarrow1-\frac{9}{11}< 1-\frac{13}{15}\Rightarrow\frac{9}{11}>\frac{13}{15}\)

b) Ta có

\(\frac{201}{301}>\frac{201}{308}>\frac{199}{308}\Rightarrow\frac{201}{301}>\frac{199}{308}\)