Bài 2:
a: Ta có: \(\dfrac{9}{11}=1-\dfrac{2}{11}\)
\(\dfrac{13}{15}=1-\dfrac{2}{15}\)
mà \(-\dfrac{2}{11}< -\dfrac{2}{15}\)
nên \(\dfrac{9}{11}< \dfrac{13}{15}\)
b: Ta có: \(\dfrac{19}{15}=1+\dfrac{4}{15}\)
\(\dfrac{15}{11}=1+\dfrac{4}{11}\)
mà \(\dfrac{4}{15}< \dfrac{4}{11}\)
nên \(\dfrac{19}{15}< \dfrac{15}{11}\)
Bài 2:
a: Ta có: 1315=1−2151315=1−215
mà 911<1315911<1315
b: Ta có: 1511=1+4111511=1+411
mà 1915<1511