\(a)\)\(\left(\frac{3}{5}\right)^{2x+1}=\frac{81}{625}\)

\(\Leftrightarrow\)\(\left(\frac{3}{5}\right)^{2x+1}=\left(\frac{3}{5}\right)^4\)

\(\Leftrightarrow\)\(2x+1=4\)

\(\Leftrightarrow\)\(x=\frac{3}{2}\)

Vậy \(x=\frac{3}{2}\)

\(b)\)\(\left(\frac{2}{3}\right)^x.\left(\frac{2}{3}\right)^3=\frac{32}{243}\)

\(\Leftrightarrow\)\(\left(\frac{2}{3}\right)^{x+3}=\left(\frac{2}{3}\right)^5\)

\(\Leftrightarrow\)\(x+3=5\)

\(\Leftrightarrow\)\(x=2\)

Vậy \(x=2\)

\(c)\)\(\left(2x-1\right)^2=\left(2x-1\right)^3\)

\(\Leftrightarrow\)\(\left(2x-1\right)^3-\left(2x-1\right)^2=0\)

\(\Leftrightarrow\)\(\left(2x-1\right)^2\left(2x-1-1\right)=0\)

\(\Leftrightarrow\)\(\left(2x-1\right)^2\left(2x-2\right)=0\)

\(\Leftrightarrow\)\(\orbr{\begin{cases}\left(2x-1\right)^2=0\\2x-2=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=1\end{cases}}}\)

Vậy \(x=\frac{1}{2}\) hoặc \(x=1\)

Chúc bạn học tốt ~ 

\(\Rightarrow\left(\dfrac{33}{11}\right)^{2x}=81\Rightarrow3^{2x}=3^4\Rightarrow x=2\)

a) 2³.(20 - 2x) = 4.2⁵

8.(20 - 2x) = 4.32

8.(20 - 2x) = 128

20 - 2x = 128 : 8

20 - 2x = 16

2x = 20 - 16

2x = 4

x = 4 : 2

x = 2

b) 3²⁺ˣ = 81

3²⁺ˣ = 3⁴

2 + x = 4

x = 4 - 2

x = 2

a. (2x-1)⁴=81

=>(2x-1)⁴=3⁴

=>2x-1=3

=>2x=3+1

=>2x=4

=>x=4:2

=>x=2

b.(x-1)⁵=-32

=>(x-1)⁵=(-2)⁵

=>x-1=-2

=>x=-2+1

=>x=-1

c.(2x-1)⁶=(2x-1)⁸

mà chỉ có: (-1)⁶=(-1)⁸; 0⁶=0⁸; 1⁶=1⁸

=> để (2x-1) \(\in\){-1;0;1} thì x \(\in\){0; 1/2; 1}

(2x-1)^4=3^4

=>2x-1=3

=>2x=4

=>x=2

ai h minh minh h lai cho

minh ko bit