Mk làm bài 3 thoy nha :
Ta có : xy+12=x + y
=> xy - x = y -12
=> x(y-1) = y - 1 - 11
=> x ( y -1 ) - y - 1 = -11
=> ( x- 1) ( y - 1 ) = - 11 = 1 . ( -11 ) = (-11 ) . 1
Ta có bảng :

Vậy ta tìm đc ( x ; y ) là : ( 2 ; -10 ) ; ( -10 ; 2 )
=)))

bài 1

a)100+(-520)+1140+(-620)

=[(-520)+(-620)]+1140+100

=(-1140)+1140+100

=0+100

=100

bài 1

b)13-18-(-42)-15

=13+(-18)+42+(-15)

=[(-18)+(-15)]+(42+13)

=(-33)+55

=22

c){[14:(-2)]+7}:2009

={[14.(\(\dfrac{-1}{2}\))]+7}:2009

=[(-7)+7]:2009

=0:2009

=0

a, \(\left(7.4^x+8.4^{x+1}\right).5=3120\)

\(7.4^x+8.4^x.4=3120:5\)

\(4^x\left(7+32\right)=624\)

\(4^x=624:39\)

\(4^x=16=4^2\)

\(\Rightarrow x=2\)

b, \(2018^2.2018^x=2018^6\)

\(2018^x=2018^6:2018^2=2018^4\)

\(\Rightarrow x=4\)

c, \(3^{x-2}-19=62\)

\(3^x:3^2=62+19\)

\(3^x=81.9=729=3^6\)

\(\Rightarrow x=6\)

d, \(5^{x+2}-5^{x+1}=2500\)

\(5^x\left(25-5\right)=2500\)

\(5^x=2500:20=125=5^3\)

\(\Rightarrow x=3\)

e, \(\left[\left(46-32\right)^2-\left(54-42\right)^2\right].2x-1872=0\)

\(\left[14^2-12^2\right].2x=1872\)

\(\left[196-144\right].2x=1872\)

\(52.2x=1872\)

\(2x=1872:52=36\)

\(\Rightarrow x=36:2=18\)

:)))

HỌC TỐT !

a) ( 7. 4^x + 8 . 4^x+1 ) . 5 = 3120

=> 7 . 4^x + 8 . 4^x . 4¹ = 624

=> 4^x ( 7 + 8 . 4 ) = 624

=> 4^x . 39 = 624

=> 4^x = 16

=> 4^x = 4²

=> x = 2

b) 2018² . 2018^x = 2018⁶

=> 2018^x = 2018⁴

=> x = 4

c) 3^x-2 - 19 = 62

=> 3^x-2 = 81

=> 3^x-2 = 3⁴

=> x - 2 = 4

=> x = 6

d) 5^x+2 - 5^x+1 = 2500

=> 5^x . 5² - 5^x . 5 = 2500

=> 5^x ( 5² - 5 ) = 2500

=> 5^x . 20 = 2500

=> 5^x = 125

=> 5^x = 5³

=> x = 3

e) [ ( 46 - 32 )² - ( 54 - 42 )² ] . 2x - 1872 = 0

=> [ 14²  - 12² ] . 2x = 1872

=> [ 196 - 144 ] . 2x = 1872

=> 52 . 2x = 1872

=> 2x = 36

=> x = 18

a. 580:(x-24)=329-150.2

    580:(x-24)=329-300

    580:(x-24)=29

            x-24=580:29

            x-24=20

                x=20+24

                x=44

b.43-(24-x)=20

         24-x= 43-20

         24-x=23

              x=24-23

              x=1

c.5.(x-30)+25=100

   5.(x-30)      =100-25

   5.(x-30)      =75 

       x-30        =75:5 

       x-30        =15

           x         =15+30 

           x         =45

e.x-140:35=270

   x-4=270

       x=270+4

       x=274

Câu d hình như đề bài sai rồi bạn

Mọi người ơi, giúp em với ạ

a) \(\left(9^4.8+9^4.5\right):\left(9^2.\left(10-1\right)\right)\)

=\(9^4.13:9^3=13.9=117\)

b) 100-(75-25)=100-50=50

\(a,\left(2^3\cdot9^4+9^3\cdot45\right):\left(9^2\cdot10-9^2\right)\)

\(< =>\left(8\cdot6561+729\cdot45\right):\left(81\cdot10-81\right)\)

\(< =>\left(52488+32805\right):\left(810-81\right)\)

\(< =>85293:729\)

\(< =>117\)

\(b,100-\left[75-\left(7-2\right)^2\right]\)

\(< =>100-\left[75-\left(5\right)^2\right]\)

\(< =>100-\left[75-25\right]\)

\(< =>100-50\)

\(< =>50\)

\(c,\left(20\cdot2^4+12\cdot2^4\right)-\left(48\cdot2^2\right):8^2\)

\(< =>\left[2^4\cdot\left(20+12\right)\right]-\cdot\left(48\cdot4\right):8^2\)

\(< =>\left[2^4\cdot32\right]-192:8^2\)

\(< =>\left[16\cdot32\right]-192:64\)

\(< =>512-3\)

\(< =>509\)

Do \(\left|x\right|,\left|x^2+x\right|\ge0\forall x\)

\(\Rightarrow\left\{{}\begin{matrix}x=0\\x^2+x=0\end{matrix}\right.\)

\(\Rightarrow x=0\)

x = 0

Vì bất cứ số nào nhân hay chia với o đều = 0