A)X(x+3)=0
B)(x+1)+(x+2)+....+(x+100)=5750
tìm x biết:
a, (x+1).(x+2).(x+3)+.....+(x+100)=5750
Đề sai rồi! Đề đúng là : (x+1)+(x+2)+......+(x+100)=5750
=> (x+x+x+.....+x) + (1+2+3+......+100) = 5750
=> 100x + 5050 = 5750
=> 100x = 700
=> x = 7 (tm)
Vậy...................
Tìm X
A. (X +1)+(X+2)+(X+3)+…+(X+ 100)=5750
B. X+(1+2+3+4+…+50)=2000
C. (X-1)+(X-2)+…+(X-100)=50
\(c,\)\(\left(x-1\right)+\left(x-2\right)+....+\left(x-100\right)=50\)
\(\left(x+x+...+x\right)-\left(1+2+...+100\right)=50\)
\(100x-5050=50\)
\(100x=50+5050\)
\(100x=5100\)
\(\Rightarrow x=\frac{5100}{100}=51\)
\(a,\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+....+\left(x+100\right)=5750\)
\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)
\(100x+5050=5750\)
\(100x=5750-5050\)
\(100x=700\)
\(\Rightarrow x=7\)
\(b,x+\left(1+2+3+...+50\right)=2000\)
\(x+\frac{\left[1+50\right]\cdot\left[\left(50-1\right)\div1+1\right]}{2}=2000\)
\(x+1275=2000\)
\(\Rightarrow x=2000-1275=725\)
c , ( x - 1 ) + ( x - 2 ) + ...... + ( x - 100 ) = 50
( x + x + ........ + ) - ( 1 + 2 + ..... + 100 ) = 50
100x - 5050 = 50
100x = 50 + 5050
100x = 5100
=> x = 5100/100 = 51
(x+1)+(x+2)+(x+3)+...+(x+100)=5750
Ta có: \(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)
\(\Leftrightarrow100x+5050=5750\)
\(\Leftrightarrow100x=700\)
hay x=7
tham kharo : https://olm.vn/hoi-dap/detail/89184552036.html
(x+1)+(x+2)+...+(x+100)=5750
(x+x+...+x)+(1+2+3+...+100)=5750
100x+5050=5750
100x=5750-5050
100x=700
x=700/100
x=7
(x+1) + (x+2) + (x+3) +....+ (x+100) = 5750
\(\Leftrightarrow100x+5050=5750\)
hay x=7
(x+1) + (x+2) + (x+3) +....+ (x+100) = 5750
x + 1 + x + 2 + x + 3 +...+ x + 100 = 5750
(x + x + x +...+ x) + (1 + 2 + 3 +...+ 100) = 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 700 : 100
x = 7
x+1+x+2+x+3+.......x+100=5750
=>100x+5050=5750
=>100x=700
=>x=7
x(x+1)+(x+2)+(x+3)+...+(x+100)=5750
x(x+1)+(x+2)+(x+3)+...+(x+100)=5750
=> (x+x+x+x+...+x)+(1+2+3+...+100)=5750
=> 101x+5050=5750
101x = 5750-5050
101x = 700
x = 700 : 101
x = 700/101
Tìm x biết: (x+1)+(x+2)+(x+3)+...+(x+100)=5750
x+x+x+...x+ 1+2+3+...100 = 5750
100.x + 101.50 = 5750
100.x = 5757-5050
100.x = 700
x = 700: 100
x = 7
A.(x+1)+(x+2)+(x+3)+......(x+100)=5750
B. x+(1+2+3+4+5+..........+100)=2000
C.(x-1)+(x-2)-(x-3)+(x-4)+........(x-100)=50
Giúp mình với ạ mai mình phải nộp bài rồi
A. \(\left(x+1\right)+\left(x+2\right)+......+\left(x+100\right)=5750\)
\(x+1+x+2+....+x+100=5750\)
\(100x+\left(1+2+3+.......+100\right)=5750\)
\(100x+5050=5750\)
\(100x=700\)
\(x=700:100=7\)
B. x+(1+2+......+100) = 2000
x + 5050 = 2000
x = 2000 - 5050
x= -3050
C. ( x-1 )+(x-2)+......+( x - 100 ) = 50
x-1+x-2+.........+x-100 = 50
100x + ( -1-2-........-100 ) = 50
100x + ( - 5050 ) = 50
100x = 50 + 5050
100 x = 5100
x = 5100 : 100
x = 51
A . \(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)
\(\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)
\(100x+5050=5750\)
\(100x=5750-5050\)
\(100x=700\)
\(\Rightarrow x=\frac{700}{100}=7\)
B. \(x+\left(1+2+3+4+5+....+100\right)=2000\)
\(x+\frac{\left(100+1\right).100}{2}=2000\)
\(x+5050=2000\)
\(\Rightarrow x=2000-5050=-3050\)
C. \(\left(x-1\right)+\left(x-2\right)+\left(x-3\right)+....+\left(x-100\right)=50\)
\(\left(x+x+x+...+x\right)-\left(1+2+3+...+100\right)=50\)
\(100x-5050=50\)
\(100x=5100\)
\(\Rightarrow x=\frac{5100}{100}=51\)