Question

(x+1)+(x+2)+(x+3)+...+(x+100)=5750

Answer 1

Ta có: \(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)

\(\Leftrightarrow100x+5050=5750\)

\(\Leftrightarrow100x=700\)

hay x=7

Answer 2

x=7

Answer 3

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Answer 4

\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\Leftrightarrow\left(x+x+x+...+x\right)+\left(1+2+3+...+100\right)=5750\)(100 số x)\(\Leftrightarrow100x+\dfrac{\left(100+1\right).\left(\dfrac{100-1}{1}+1\right)}{2}=100x+5050=5750\)

\(\Leftrightarrow100x=700\Leftrightarrow x=7\)

Answer 5

x=7

Answer 6

x = 7 hoặc x = 700

Answer 7

(x+1)+(x+2)+(x+3)+...+(x+100)=5750

( x + x + x + ... + x ) + ( 1 + 2 + 3 + ... + 100 ) = 5750

x * 100 + ( 1 + 100 ) *100 : 2 = 5750

x * 100 + 101 * 50 = 5750

x * 100 + 5050 = 5750

x * 100 = 5750 - 5050

x * 100 = 700

x = 700 : 100

x = 1