( x- 17 ) + 52 = 158
( x: 23 + 45 ) : 67 =8911
Tìm số tự nhiên x biết:
a) 504 : (16 – 3x) = 72
b) 272 – (4x+15) = 45
c) (x : 23 + 45).67 = 8911
d) [(x+32) – 17].2 = 42
tìm x:{x:23+45}:67=8911
(x:23+45):67=8911
x:23+45=8911x67
x:23+45=597037
x:23=597037-45
x:23=596992
x=596992x23
=13730816
(x:23+45).67=8911
( x : 23 + 45 ) . 67 = 8911
=> x : 23 + 45 = 133
=> x : 23 = 88
=> x = 2024
( x : 23 + 45 ) . 67 = 8911
=> x : 23 + 45 = 133
=> x : 23 = 88
=> x = 2024
# ~Hok tốt~
(x/ 23+45).67=8911
=> x/23 + 45 = 133
=> x/23 = 88
=> x = 23 x 88 = 2024
( \(\frac{x}{23}\) + 45 ) .67 = 8911
x : 23 + 45 = 8911:67
x : 23 + 45 = 133
x : 23 = 133 - 45
x : 23 = 88
x = 88 . 23
x = 2024
vậy x = 2024
a) (x:23+45).67=8911
\(\left(x:23+45\right).67=8911\)
\(\Rightarrow x:23+45=8911:67\)
\(\Rightarrow x:23+45=133\)
\(\Rightarrow x:23=133-45\)
\(\Rightarrow x:23=88\)
\(\Rightarrow x=23.88\)
\(\Rightarrow x=2024\)
Vậy \(x=2024\)
\(\left(x:23+45\right)\cdot67=8911\)
\(x:23+45=\frac{8911}{67}=133\)
\(x:23=133-34\)
\(x:23=99\)
\(\Rightarrow x=99\cdot23\)
\(\Rightarrow x=2277\)
(x:23+45).67=8911
x:23+45=133
x:23=88
x=2024
Vậy x=2024
Tìm x
(x / 23 +45 ) *67 = 8911
(x:23+45)x67=8911
x:23+45=8911:67
x:23+45=133
x:23=133-45
x:23=88
x=88x23
x=2024
vậy x=2024
\(\left(\frac{x}{23}+45\right).67=8911\)
\(\frac{x}{23}+45=133\)
\(\frac{x}{23}=133-45\)
\(\frac{x}{23}=88\)
\(x=88.23\)
\(x=2024\)
Vậy x = 2024
(x:23+45)*67=8911
x:23+45 =8911:67
x:23+45 =133
x =133-(45+23)
x =111
3636:(12x -91)=36
( x:23+45 ) ×67= 8911
a/ \(3636\div\left(12x-91\right)=36\)
\(12x-91=3636\div36\)
\(12x-91=101\)
\(12x=101+91\)
\(12x=192\)
\(x=192\div12\)
\(x=16\)
b/ \(\left(x\div23+45\right)\times67=8911\)
\(x\div23+45=8911\div67\)
\(x\div23+45=133\)
\(x\div23=133+45\)
\(x\div23=178\)
\(x=178\times23\)
\(x=4094\)
(x÷23+45)×67=8911
( x : 23 + 45 ) . 67 = 8911
=> ( x : 23 + 45 ) = 8911 : 67
=> (x : 23 + 45 ) = 133
=> x : 23 + 45 = 133
x : 23 = 133 - 45
x : 23 = 88
x = 88 . 23
x = 2024
\(\left(x:23+45\right).67=8911\)
\(\Leftrightarrow\left(x:23+45\right)=8911:67\)
\(\Leftrightarrow\left(x:23+45\right)=133\)
\(\Leftrightarrow x:23=133-45\)
\(\Leftrightarrow x:23=88\)
\(\Leftrightarrow x=88.23\)
\(\Leftrightarrow x=2024\)
Vậy : \(x=2024\)
b1: 5x(x-3)-18=2
b2: (x :23+45):67=8911
5 . ( x-3 ) -18 = 2
5x - 15 = 2 + 18
5x - 15 = 20
5x = 20 + 15
5x = 35
x= 7
Vậy x= 7
\(5x^2-15x-18=2\)
\(5x^2-15x-20=0\)
\(5\left(x^2-3x-4\right)\)\(=0\)
\(5\left(x^2-2xX\frac{3}{2}+\frac{9}{4}-\frac{9}{4}-4\right)=0\)
\(5\) {\(\left(x-\frac{3}{2}\right)^2-\frac{25}{4}\)} \(=0\)
\(\left(x-\frac{3}{2}\right)^2\) \(=\frac{25}{4}\)
\(x=\frac{\sqrt{25}}{2}+\frac{3}{2}\) hoặc \(x=\frac{-\sqrt{25}}{2}+\frac{3}{2}\)
\(\frac{x}{23}+45=597037\)
\(\frac{x}{23}=596992\)
\(x=13730816\)
Bài 1 :
\(5\cdot\left(x-3\right)-18=2\)
\(5x-15-18=2\)
\(5x-15=2+18\)
\(5x-15=20\)
\(5x=20+15\)
\(5x=35\)
\(x=35:5\)
\(x=7\)
Bài 2 :
\(\left(x:23+45\right):67=8911\)
\(x:23+45=8911:67\)
\(x:23+45=133\)
\(x:23=133-45\)
\(x:23=88\)
\(x=88\cdot23\)
\(x=2024\)