Tính
1212 / 1515 : 2727 / 2525
1212/1515 :2727/2525=4/5:27/25=4/5.25/27=20/27
Học tốt!
Tính
1212/1515 : 2727/2525
\(\frac{1212}{1515}:\frac{2727}{2525}\)
\(=\frac{1212}{1515}x\frac{2525}{2727}\)
\(=\frac{20}{27}\)
Chúc Học tốt
\(\frac{1212}{1515}:\frac{2727}{2525}=\frac{1212}{1515}x\frac{2525}{2727}=\frac{12x101}{15x101}x\frac{25x101}{27x101}=\frac{12x25}{15x27}=\frac{3x4x5x5}{3x5x27}=\frac{4x5}{27}=\frac{20}{27}.\)
1212/1515 :2727/2525
giúp mik với cần gấp lắm trong hôm nay nha
(mik quên cách làm)
bước 1: rút về số tối giản
bước 2: tìm MSC
bước 3: tính...
\(\frac{1212}{1515}:\frac{2727}{2525}\)
Rút gọn : \(\frac{1212}{1515}=\frac{4}{5}\)
\(\frac{2727}{2525}=\frac{27}{25}\)
\(=>\frac{4}{25}.\frac{25}{27}=\frac{20}{27}\)
~ chúc bn hok tốt ~
bài 1: tính phân số
a)\(\frac{1212}{1515}:\frac{2727}{2525}=?\) b)\(\frac{14}{27}:\frac{7}{18}x\frac{6}{5}+\frac{3}{10}=?\)
a) \(\frac{1212}{1515}\):\(\frac{2727}{2525}\)
= \(\frac{1212}{1515}\)* \(\frac{2525}{2727}\)
= \(\frac{101.12}{101.15}\)* \(\frac{101.25}{101.27}\)
= \(\frac{12}{15}\). \(\frac{25}{27}\)
= \(\frac{20}{27}\)
b) ban co the viet ro hon de bai dc ko?
Tính nhanh:
a) 4,25x58,47-125+41,53x4,25
b)1212/1515+1212/3535+1212/6363+1212/9999
Giả hộ mik nha (=
a)=4.25x(58.47+41.53)-125
=4.25x100-125
=425-100
=325
tính nhanh : 1515/2323 x 696969/545454 x 2727/1515
=15/23.(69/54./27/15)
=15/23.23/10
=3/2
\(=\dfrac{15}{23}\times\dfrac{69}{54}\times\dfrac{27}{15}\\ =\dfrac{3}{2}\)
=15/23 x (69/54 x /27/15)
=15/23 x 23/10
=3/2
Tính :
A ) 169 / 64 - 2
B ) 8 / 5 + 7 / 6 + 5 / 9 - 2
C) 3 - 5 / 6 - 4 / 9 + 32 / 24
D ) 1212 / 1515 : 2727 / 2525
E ) 15 : 25 / 4
G ) 5 / 7 + 4 / 9
H ) 9 / 11 + 3 / 8
K ) 10 - 9 / 16
I ) 2 / 3 - ( 1 / 6 + 1 / 8 )
Ai giúp mk giải thì mk cảm ơn rất nhìu , hứa sẽ tích nhưng phải giải rõ ràng và bằng cách cấp 1 nha . Trước 5 giờ 20 nha , ko cô mk cho lên thớt thì tèo .
Bài 3. Tính nhanh:
\(\dfrac{1212}{1515}\) + \(\dfrac{1212}{3535}\) + \(\dfrac{1212}{6363}\) + \(\dfrac{1212}{9999}\)
\(\dfrac{1212}{1515}+\dfrac{1212}{3535}+\dfrac{1212}{6363}+\dfrac{1212}{9999}\)
=\(\dfrac{12}{15}+\dfrac{12}{35}+\dfrac{12}{63}+\dfrac{12}{99}\)
=\(\dfrac{16}{11}\)
Giải:
\(\dfrac{1212}{1515}+\dfrac{1212}{3535}+\dfrac{1212}{6363}+\dfrac{1212}{9999}\)
\(=\dfrac{12}{15}+\dfrac{12}{35}+\dfrac{12}{63}+\dfrac{12}{99}\)
\(=12.\left(\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+\dfrac{1}{9.11}\right)\)
\(=12.\dfrac{1}{2}.\left(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}\right)\)
\(=6.\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\right)\)
\(=6.\left(\dfrac{1}{3}-\dfrac{1}{11}\right)\)
\(=6.\dfrac{8}{33}\)
\(=\dfrac{16}{11}\)
\(=\dfrac{12}{15}+\dfrac{12}{35}+\dfrac{12}{63}+\dfrac{12}{99}=12\cdot\left[\dfrac{1}{15}+\dfrac{1}{35}+\dfrac{1}{63}+\dfrac{1}{99}\right]=12\cdot\left[\dfrac{1}{3\cdot5}+\dfrac{1}{5\cdot7}+\dfrac{1}{7\cdot9}+\dfrac{1}{9\cdot11}\right]=12\cdot\dfrac{1}{2}\cdot\left[\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\right]=6\cdot\left[\dfrac{1}{3}-\dfrac{1}{11}\right]=6\cdot\dfrac{8}{33}=\dfrac{48}{33}=\dfrac{16}{11}\)
12/27+a=25/50
4/9+a=5/10
a=5/10-4/9
a=5/90