do hơi bận nên mk ghi đáp án nha, ko hiểu đâu ib mk 

a)  \(3xy^2-2xy+12x=x\left(3y^2-2y+12\right)\)

b)  \(x^3-10x^2+25x-16xy^2=x\left(x-4y-5\right)\left(x+4y-5\right)\)

c)  \(5y^3-10xy^2+5x^2y-20y=5y\left(y-x-2\right)\left(y-x+2\right)\)

d)  \(x^2+2xy+y^2-xz-yz=\left(x+y\right)\left(x+y-z\right)\) 

e)  \(9x^2+y^2+6xy=\left(3x+y\right)^2\)

f)  \(8-12x+6x^2-x^3=\left(2-x\right)^3\)

g)  \(125x^3-75x^2+15x-1=\left(5x-1\right)^3\)

h)  \(x^2-xz-9y^2+3yz=\left(x-3y\right)\left(x+3y-z\right)\)

\(-25x^2\sqrt{2}+10x+4\sqrt{2}=-\sqrt{2}\left(25x^2-\dfrac{10}{\sqrt{2}}-4\right)=-\sqrt{2}.\left(\left(25x\right)^2-2.5.\dfrac{1}{\sqrt{2}}+\dfrac{1}{2}-\dfrac{5}{2}\right)=-\sqrt{2}\left[\left(5x-\dfrac{1}{\sqrt{2}}\right)^2-\dfrac{5}{2}\right]=-\sqrt{2}.\left(5x-\dfrac{1}{\sqrt{2}}-\dfrac{\sqrt{5}}{\sqrt{2}}\right).\left(5x-\dfrac{1}{\sqrt{2}}+\dfrac{\sqrt{5}}{\sqrt{2}}\right)=-\sqrt{2}.\left(5x-\dfrac{1+\sqrt{5}}{\sqrt{2}}\right)\left(5x-\dfrac{1-\sqrt{5}}{\sqrt{2}}\right)\)

a: \(=x^2\left(x-y\right)+2014\left(x-y\right)=\left(x-y\right)\left(x^2+2014\right)\)

Answer:

\(25x^2-10x+4y-4y^2\)

\(=25x^2-10x+1-4x^2+4y-1\)

\(=\left(25x^2-10x+1\right)-\left(4y^2-2y+1\right)\)

\(=[\left(5x\right)^2-2.5x.1+1]-[\left(2y\right)^2-2.2y.1+1]\)

\(=\left(5x-1\right)^2-\left(2y-1\right)^2\)

\(=\left(5x-1-2y+1\right).\left(5x-1+2y-1\right)\)

\(=\left(5x-2y\right).\left(5x+2y-2\right)\)

Viết liền thế ai mà đọc được

a) 6xy-18y

= 6y(x-3)

b) x³-10x²+25x

= x³-5x^2-5x²+25x

= x²(x-5) - 5x(x-5)

= (x-5)(x²-5x)

c) xy + y²-x-y 

= x(y-1)+y(y-1)

= (y-1)(x+y)

K nhé ~~~

\(x^2-2xy+y^2-16\)

\(=\left(x-y\right)^2-16\)

\(=\left(x-y-4\right)\left(x-y+4\right)\)

p/s: chúc bạn học tốt

\(x^2-2xy+y^2-16\)

\(\Rightarrow\left(x-y\right)^2-16\)

\(\Rightarrow\left(x-y-4\right)\left(x-y+4\right)\)

Code : Breacker