96-3(x+1)=42
96-3(x+1)=42
\(96-3\left(x+1\right)=42\)
\(=>3\left(x+1\right)=96-42\)
\(=>3\left(x+1\right)=54\)
\(=>x+1=54:3\)
\(=>x+1=18\)
\(=>x=18-1\)
\(=>x=17\)
\(96-3\left(x+1\right)=42\)
\(\Rightarrow3\left(x+1\right)=96-42\)
\(\Rightarrow3\left(x+1\right)=54\)
\(\Rightarrow x+1=54:3\)
\(\Rightarrow x+1=18\)
\(\Rightarrow x=18-1\)
\(\Rightarrow x=17\)
96 - 3 ( x + 1) = 42. Tìm x
96 - 3(x+1)= 42
3(x+1) = 96 - 42 = 54
x + 1 = 54 : 3 = 18
x = 18 - 1 = 17
96-3.(x+1)=42
96-3.(x+1)=16
93 .(x+1)=16
(x+1)= 93-16
(x+1)=77
x = 77-1
x = 76
Tìm x biết
c)96 - 3.(x + 1) = 42
c)96 - 3.(x + 1) = 42
3.(x + 1)= 96 - 42
3.(x + 1) = 54
x + 1= 54:3
x + 1= 18
x = 18 - 1
x = 17
96-3.(x+1)=42
96-3.(x+1)=42
=> 3.(x+1)=96-42
=> 3.(x+1)=54
=> x+1=54:3
=> x+1=18
=> x=18-1
=> x=17
96-3[x+1] =42
17
giúp tớ nhé tớ bị trừ 1090 điểm cảm ơn trước
96-3(x+1)=42
3(x+1)=96-42
3(x+1)=54
x+1=54-1
x+1=53
x=52
nha bn
96 - 3.(x+1) = 42
=> 3.(x+1) = 96 - 42
=> 3.(x+1) = 54
=> x+1 = 54 : 3
=> x+1 = 18
=> x = 18 - 1
=> x = 17
Vậy x = 17
96-3 (x+1)=42
\(96-3\left(x+1\right)=42\)
\(96-\left(3x+3\right)=42\)
\(96-3-3x=42\)
\(93-3x=42\)
\(3x=51\Rightarrow x=17\)
tik mik nha !!!
96 - 3 ( x+1 ) = 42
=>3( x + 1 )= 96 - 42
=> 3( x + 1) = 54
=> x+1 = 54 : 3
=> x + 1 = 18
96-3(x+1)=42
3(x+1)=96-42
3(x+1)=54
x+1=54:3
x+1=18
x=18-1
x=17
96 - 3 (x + 1) = 42
96 - 3(x + 1) = 42
3(x + 1) = 96 - 42 = 54
x + 1 = 54 : 3 = 18
x = 18 - 1
x = 17
96-3(x+1)=42
96-3(x+1)=42
Giải:
\(96-3\left(x+1\right)=42\)
\(\Leftrightarrow3\left(x+1\right)=96-42\)
\(\Leftrightarrow3\left(x+1\right)=54\)
\(\Leftrightarrow x+1=\dfrac{54}{3}\)
\(\Leftrightarrow x+1=18\)
\(\Leftrightarrow x=18-1\)
\(\Leftrightarrow x=17\)
Vậy \(x=17\).
Chúc bạn học tốt!
96 - 3( x + 1 ) =42
3( x+1 ) = 96 - 42 = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 - 1 = 17
Vậy...
96-3(x+1)=42
3(x+1)=96-42
3(x+1)=54
x+1=54:3
x+1=18
x=18-1
x=17