Tim x de gia tri cua cac bieu thuc sau =0
a. x^3-x^2-4x-4
b. x^3-x^2+2x-2
c. x^3+6x^2+11x+6
Tim cac gia tri nguyen cua x de cac gia tri bieu thuc sau la so nguyen
a, 9-2x/x-3
b,3x-5/x-2
c,-3/4-x
tim cac gia tri cua x de bieu thuc sau nhan gia tri duong
a) x mu 2 + 4x b)2x mu 2 - 4x c)(x-3)(x+7) d)5(3x +1 )(4x-3) e)(1/2-x)(1/3-x)
tim cac gia tri nguyen cua x de cac gia tri bieu thuc sau la so nguyen
a,9-2x/x-3
b,3x-5/x-2
c,-3/4-x
tim cac gia tri cua x de bieu thuc sau nhan gia tri am
a)x mu 2 + 5x b)x mu 2 - 5/2x c)3(2x+3)(3x-5) d)x - 2/x-6 e) x mu 2 -1/x mu 2
cho bieu thuc C = x^3 / x^2-4 -x/x-2 -2/x+2 cau a : tim gia tri cua x de bieu thuc C xac dinh cau b : tim x de C bang 0 cac c : tim gia tri nguyen cua x de C nhan gia tri duong
bai1 :P=x+2/x+3-5/(x+3)(x-2)+1/2-x
a,Tim dkxd cua P
b,Rut gon bieu thuc P
c,tim x de P=-3/4
d,tim gia tri nguyen cua x de P cung co gia tri nguyen
e,tinh gia tri bieu thuc P khi x^2-9=0
1. gia tri cua x thoa man (2x+3)(x+1)2-(2x+3)(2x-3)
2. so nghiem cua da thuc x3+6x2+11x+6 la ?
3. bieu thuc C = 8-5x-2x2 dat gia tri lon nhat tai x = ?
1) Cho bieu thuc A=\(3+\frac{2}{x-1}\). Tinh gia tri cua bieu thuc A khi |2x-3|=1
2) Rut gon bieu thuc B=\(\frac{x}{x-1}\)-\(\frac{x-5}{x+1}\)-\(\frac{3-x}{1-x^2}\)
3) Tim cac gia tri nguyen cua x de bieu thuc \(\frac{B}{A}\)co gia tri nguyen duong
cho 2 bieu thuc A=x+x^2/2-x va B=2x/x+1+3/x-2-2x^2+1/x^2-x-2 a, tinh gia tri cua A khi /2x-3/=1 b,tim dieu kien xac dinh va rut gon bieu thuc B c,tim so nguyen x de P=A.B dat gia tri lon nhat
mk dang can gap
a:
ĐKXĐ: x<>2
|2x-3|=1
=>\(\left[{}\begin{matrix}2x-3=1\\2x-3=-1\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=2\left(loại\right)\\x=1\left(nhận\right)\end{matrix}\right.\)
Thay x=1 vào A, ta được:
\(A=\dfrac{1+1^2}{2-1}=\dfrac{2}{1}=2\)
b: ĐKXĐ: \(x\notin\left\{-1;2\right\}\)
\(B=\dfrac{2x}{x+1}+\dfrac{3}{x-2}-\dfrac{2x^2+1}{x^2-x-2}\)
\(=\dfrac{2x}{x+1}+\dfrac{3}{x-2}-\dfrac{2x^2+1}{\left(x-2\right)\left(x+1\right)}\)
\(=\dfrac{2x\left(x-2\right)+3\left(x+1\right)-2x^2-1}{\left(x+1\right)\left(x-2\right)}\)
\(=\dfrac{2x^2-4x+3x+3-2x^2-1}{\left(x+1\right)\left(x-2\right)}\)
\(=\dfrac{-x+2}{\left(x+1\right)\left(x-2\right)}=-\dfrac{1}{x+1}\)
c: \(P=A\cdot B=\dfrac{-1}{x+1}\cdot\dfrac{x\left(x+1\right)}{2-x}=\dfrac{x}{x-2}\)
\(=\dfrac{x-2+2}{x-2}=1+\dfrac{2}{x-2}\)
Để P lớn nhất thì \(\dfrac{2}{x-2}\) max
=>x-2=1
=>x=3(nhận)