Cmr
1.3.5. ... .19=11/2.12/2. ... .20/2
CMR 1.3.5...19=11/2.12/2.13/2...20/2
CMR
1.3.5. ... .19 = 11/2.12/2. ... .20/2
CMR
1.3.5. ... .19 = 11/2.12/2. ... .20/2
CMR
1.3.5. ... .19 = 11/2.12/2. ... .20/2
CMR
1.3.5. ... .19 = 11/2.12/2. ... .20/2
Cmr
1.3.5. ... .19=11/2.12/2. ... .20/2
chứng minh rằng:1.3.5.....19=11/2.12/2.13/2.....20/2
Ta thấy
1.3.5.....19 = 1.2.3.4.5.6.....19.20/2.4.6.....20
= 1.2.3.4.5.6.....19.20/1.2.2.2.3.2.....10.2
= 1.2.3.4.5.6.....19.20/(1.2.3.....10).(2.2.2.....2)
= (1.2.3.4.5.6.....10).(11.12.13.....19.10)/(1.2.3.....10).(2.2.2.....2)
= 11.12.13.....19.20/2.2.2.....2
= 11/2 . 12/2 . 13/2 . ... . 19/2 . 20/2
=> Đpcm
chứng minh rằng :
1.3.5.....19=11/2.12/2....20/2
ta có : 1.3.5.....19. (2.4.6...20/2.4.6....20)=1.2.3....19.20/(1.2.3....10)(2.2.2.2.2.2.2.2.2.2)=11/2 .12/2 ......20/2
10 chữ số 2
hứng minh rằng :
1.3.5....19=11/2.12/2.13/2....20/2
Ta có:
1.3.5...19 = 1.2.3.4.5.6...19.20/2.4.6...20
= 1.2.3.4.5.6...19.20/2^10.(1.2.3...10)
= 11.12.13....20/2^10
= 11/2 . 12/2 . 13/2 ... 20/2 ( đpcm)