`(3x - 1)^3 = 125`

`(3x - 1)^3 = 5^3`

`=> 3x - 1 = 5`

`3x = 5 + 1`

`3x = 6`

`x = 6 : 3`

`x = 3`

Vậy `x = 3`

`@btran`

\(\left(2600-6400\right)-3x=1200\\ -3800-3x=1200\\ 3x=-3800-1200\\ 3x=-5000\\ x=-5000:3\\ x=\dfrac{-5000}{3}\)

\(\left(3x-1\right)^3=125\\ \left(3x-1\right)^3=5^3\\ 3x-1=5\\ 3x=6\\ x=6:3\\ x=2\)

4:

=>(2x+3,5)=7/12*3/14=21/168=1/8

=>2x=1/8-7/2=1/8-28/8=-27/8

=>x=-27/16

5: =>1/3:3x=-21/4

=>3x=-1/3:21/4=-1/3*4/21=-4/63

=>x=-4/189

6: =>2+7/9-3/4(x+1)=7/9

=>2-3/4(x+1)=0

=>3/4(x+1)=2

=>x+1=2:3/4=2*4/3=8/3

=>x=5/3

\(a,\frac{1}{3}x+0.25=\frac{5}{7}\)

\(\Leftrightarrow\frac{1}{3}x=\frac{13}{28}\)

\(\Leftrightarrow x=\frac{39}{28}\)

vậy...

\(b,\frac{11}{12}x+0,25=\frac{5}{6}\)

\(\Leftrightarrow\frac{11}{12}x=\frac{7}{12}\)

\(\Leftrightarrow x=\frac{7}{11}\)

vậy.....

\(c,\left(\frac{-1}{3}\right)^2+\frac{2}{3}x=\frac{1}{4}\)

\(\Leftrightarrow\frac{1}{9}+\frac{2}{3}x=\frac{1}{4}\)

\(\Leftrightarrow\frac{2}{3}x=\frac{5}{36}\)

\(\Leftrightarrow x=\frac{5}{24}\)

vậy......

\(d,\left(3x+2\right)^3=-\frac{8}{125}\)

\(\Leftrightarrow3x+2=-\frac{2}{5}\)

\(\Leftrightarrow3x=-\frac{12}{5}\)

\(\Leftrightarrow x=-\frac{4}{5}\)

vậy.......

\(\frac{1}{3x}+0,25=\frac{5}{7}\)

\(\frac{1}{3x}+\frac{1}{4}=\frac{5}{7}\)

\(\frac{1}{3x}=\frac{13}{28}\)

\(3x=\frac{28}{13}\)

\(x=\frac{28}{39}\)

\(\frac{11}{12x}+0,25=\frac{5}{6}\)

\(\frac{11}{12x}+\frac{1}{4}=\frac{5}{6}\)

\(\frac{11}{12x}=\frac{7}{12}\)

\(x=\frac{11}{12}:\frac{7}{12}\)

\(x=\frac{7}{11}\)

\(\left(-\frac{1}{3}\right)^2+\frac{2}{3x}=\frac{1}{4}\)

\(\frac{1}{9}+\frac{2}{3x}=\frac{1}{4}\)

\(\frac{2}{3x}=\frac{5}{36}\)

\(x=\frac{2}{3}:\frac{5}{36}\)

\(x=\frac{5}{24}\)

\(\left(3x+2\right)^3=\left(-\frac{8}{125}\right)\)

\(\left(3x+2\right)^3=\left(-\frac{2}{5}\right)^3\)

\(\Rightarrow3x+2=-\frac{2}{3}\)

\(3x=-\frac{8}{3}\)

\(x=-\frac{9}{8}\)

**1/3x + 0.25= 5/7
1/3x= 5/7 - 0.25
1/3x= 13/28
x= 13/28: 1/3
x= 39/28

**11/12x+ 0.25= 5/6
11/12x= 5/6- 0.25
11/12x= 7/12
x= 7/12:11/12
x= 7/11
**(-1/3)^2+ 2/3x=1/4
1/9+ 2/3x= 1/4
2/3x= 1/4- 1/9

2/3x= 5/36
x= 5/35: 2/3
x= 5/24
**(3x+2)^3= -8/125

(3x+2)^3= -0.064
(3x+2)^3= -0.4^3
=> 3x+2= -0.4
3x= -0.4- 2
3x= -2.4
x= -2.4: 3
x= -0.8
x= -4/5 
!!!Mình giải all cho bạn rồi nhaa. Chúc bạn học tốt nhé!!!

a) 3⁵= 243

b)5³=125

tiếp theo bn tự tính nhé

a) \(\left(2x-1\right)^5=243\)

\(\left(2x-1\right)^5=3^5\)

\(\Rightarrow2x-1=3\)

\(2x=3+1\)

\(2x=4\)

\(x=\frac{4}{2}\)

\(x=2\)

Vậy .......

b) \(\left(3x+2\right)^3=125\)

\(\left(3x+2\right)^3=5^3\)

\(\Rightarrow3x+2=5\)

\(3x=5-2\)

\(3x=3\)

\(x=\frac{3}{3}=1\)

Vậy ..........

a) \(\left(2x+1\right)^3=125\)

\(\left(2x+1\right)^3=5^3\)

\(2x+1=5\)

\(2x=4\)

\(x=2\)

b) \(3^x+25=26\times2^2+2\times3^0\)

\(3^x+25=26\times4+2\times1\)

\(3^x+25=106\)

\(3^x=106-25\)

\(3^x=81\)

\(3^x=3^4\)

\(x=4\)

(2x+1)3 = 125 

a)<=> (2x+1)3 = 53

<=> 2x+1 = 5

<=> 2x = 4

<=> x = 2

3^x+25=26 . 2^2 + 2. 3^0

b)3^x+25=104 +2

3^x+25=106

3^x=106+25

3^x=81=3^4

=> x=4                                                                      

ta có : \(\left(3x-1\right)^3=125\Leftrightarrow\left(3x-1\right)^3=5^3\Rightarrow3x-1=5\)

\(\Leftrightarrow3x=5+1=6\Leftrightarrow x=\dfrac{6}{3}=2\) vậy \(x=2\)

ta có : \(x^{2010}=x\Leftrightarrow x^{2010}-x=0\Leftrightarrow x\left(x^{2009}-1\right)=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x^{2009}-1=0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x^{2009}=1\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=1\end{matrix}\right.\) vậy \(x=0;x=1\)

Biểu thức B y đâu bn????