Tìm x biết 2x-1 =128
Tìm x, biết
a) 17 2 − 2 x − 3 4 = − 7 4
b) 3 x 7 + 1 : − 4 = − 1 28
Tìm X ∈ N biết:
a,2x . 2x + 1=128
b,3x+1 . 3x=243
a)2x.2x+1=128
\(4x^2+1=128\)
\(\Rightarrow4x^2=127\)
\(\Rightarrow x^2=127\div4\)
\(\Rightarrow x^2=3.175\)
mà \(x\in N\) hay\(x^2\in N\)
\(\Rightarrow\)Không có x
b) 3x+1.3x=243
\(\Rightarrow\)3x+3x=243
\(\Rightarrow\)6x=243
\(\Rightarrow\)x=40,5
Mà \(x\in N\)
\(\Rightarrow\)Không có x
Câu 4 : Tìm x, biết.
a) 2^x.4 = 128 b) (2x + 1)^3 = 125 c) 2x – 2^6 = 6 d) 49.7^x = 2401\(a,2^x.4=128\\2^x.2^2=2^7\\ 2^x=\dfrac{2^7}{2^2}=2^{7-2}=2^5\\ Vậy:x=5\\ ----\\ b,\left(2x+1\right)^3=125=5^3\\ \Rightarrow 2x+1=5\\ 2x=5-1=4\\ x=\dfrac{4}{2}=2\\ ----\\ c,2x-2^6=6\\ 2x=6+2^6=6+64\\ 2x=70\\ x=\dfrac{70}{2}=35\\ ----\\ d,49.7^x=2401\\ 7^x=\dfrac{2401}{49}=49=7^2\\ Vậy:x=2\)
Tìm x ∈ N , biết.
a) 3 x + 1 : 3 4 = 81
b) 3 x + 3 . 3 x + 1 = 729
c) 2 x + 3 . 2 x = 128
d) 23 + 3 x = 5 6 : 5 3
e) 2 x + 2 x + 4 = 272
Tìm x ∈ N, biết.
a, 3 x + 1 : 3 4 = 81
b, 3 x + 3 . 3 x + 1 = 729
c, 2 x + 3 . 2 x = 128
d, 23 + 3 x = 5 6 : 5 3
e, 2 x + 2 x + 4 = 272
a, 3 x + 1 : 3 4 = 81
3 x - 3 = 3 4
x – 3 = 4
x = 7
Vậy x = 7
b, 3 x + 3 . 3 x + 1 = 729
3 2 x + 4 = 3 6
2x + 4 = 6
x = 1
Vậy x = 1
c, 2 x + 3 . 2 x = 128
2 2 x + 3 = 2 7
2x + 3 = 7
x = 2
Vậy x = 2
d, 23 + 3 x = 5 6 : 5 3
23 + 3 x = 5 3
23 + 3x = 125
3x = 102
x = 34
Vậy x = 34
e, 2 x + 2 x + 4 = 272
2 x + 2 x . 2 4 = 272
2 x ( 1 + 2 4 ) = 272
2 x . 17 = 272
2 x = 16
2 x = 2 4
x = 4
Vậy x = 4
Câu 3: Tìm x ∈ N, biết:
a) 3 x . 3 = 243 b) 2 x . 162 = 1024 c) 64.4x = 168 d) 2 x = 16Câu 4 : Tìm x, biết. a) 2 x .4 = 128 b) (2x + 1)3 = 125 c) 2x – 2 6 = 6 d) 49.7x = 24013:
a: 3^x*3=243
=>3^x=81
=>x=4
b; 2^x*16^2=1024
=>2^x=4
=>x=2
c: 64*4^x=16^8
=>4^x=4^16/4^3=4^13
=>x=13
d: 2^x=16
=>2^x=2^4
=>x=4
tìm X biết : 128 x (3/2X - 1/4)3= -250
mình đag cần gấp nhé
\(128\times\left(\frac{3}{2x}-\frac{1}{4}\right)^3=-250.\)
\(\left(\frac{3}{2x}-\frac{1}{4}\right)^3=-250\div128\)
\(\left(\frac{3}{2x}-\frac{1}{4}\right)^3=\frac{125}{64}\)
\(\left(\frac{3}{2x}-\frac{1}{4}\right)^3=\left(\frac{5}{4}\right)^3\)
\(\Rightarrow\frac{3}{2x}-\frac{1}{4}=\frac{5}{4}\)
\(\Rightarrow\frac{3}{2x}=\frac{5}{4}+\frac{1}{4}\)
\(\Rightarrow\frac{3}{2x}=\frac{3}{2}\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
\(128x\left(\frac{3}{2}X-\frac{1}{4}\right)^3=-250\)
\(\left(=\right)\left(\frac{3}{2}X-\frac{1}{4}\right)^3=-250:128\)
\(\left(=\right)\left(\frac{3}{2}X-\frac{1}{4}\right)^3=-\frac{125}{64}\)
\(\left(=\right)\left(\frac{3}{2}X-\frac{1}{4}\right)^3=\left(-\frac{5}{4}\right)^3\)
\(\left(=\right)\frac{3}{2}X-\frac{1}{4}=-\frac{5}{4}\)
\(\left(=\right)\frac{3}{2}X=-\frac{5}{4}+\frac{1}{4}\)
\(\left(=\right)\frac{3}{2}X=-\frac{4}{4}\)
\(\left(=\right)\frac{3}{2}X=-1\)
\(\left(=\right)X=-1:\frac{3}{2}\)
\(\left(=\right)X=-\frac{2}{3}\)
Vậy \(X=-\frac{2}{3}\)
Tìm x biết :
a) 19992x - 6 = 1
b) 2x x 4 = 128
c) ( 2x + 1 ) 3 = 125
a) 19992x - 6 = 1
19992x - 6 = 19990
=>2x-6=0
2x=0+6
2x=6
x=6:2
x=3
b) 2x x 4 = 128
2x=128:4
2x=32
2x=25
=>x=5
c) ( 2x + 1 ) 3 = 125
( 2x + 1 ) 3 = 53
2x+1=5
2x=5-1
2x=4
x=4:2
x=2
a)19992x-6=1
19992x-6=19990
=>2x-6=0
2x=0+6
2x=6
x=6:2
x=3
b)2x.4=128
2x=128:4
2x=32
x=32:2
x=5
c)(2x+1)3=125
(2x+1)3=53
2x+1=5
2x=5-1
2x=4
x=4:2
x=2
Bài 2: Tìm số tự nhiên x biết:
a) 12(x−1)∶3=43+23 c) (7x−11)3=23.52+200
b) 128−3(x+4)=23 d) 2x+2−2x=96
tìm x thuộcN biết
3 x: 3=81
22x :8=128
7x-1 .49=343
3x : 3 = 81
=> 3x = 81 . 3 = 243 = 35
=> x = 5
22x : 8 = 128
=> 22x = 128 . 8 = 1024 = 210
=> 2x = 10
=> x = 10 : 2
=> x = 5
7x-1 . 49 = 343
7x-1 = 343 : 49 = 7 = 71
=> x - 1 = 1
=> x = 1+1
=> x = 2
3x : 3 = 81
3x-1 = 81
3x-1 = 34
=> x - 1 = 4
x = 4 + 1
x = 5