[102+(28-2.x)]:20-5=1
[102+(28-2.x)]20:5=1
[102+(28-2x)]20=1*5
[102+(28-2x)]20=5
102+(28-2x)=5:20
102+(28-2x)=0.25
28-2x=0.25-102
28-2x=-101.75
2x=28+101.75
2x=129.75
x=129.75:2
x=64.875
1) Tìm x biết:
a) 8x : 2x = 4
b) [ 102 + (28 - 2x)] : 20 - 5 = 1
123-5.(x+4)=38
10+2x=2.(32-1)
2.x-138=23.32
[102+(28-2x)]:20-5=1
231-(x-6)=1339:13
123-5.(x+4)=38
5(x+4)=123-38
5(x+4)=85
x+4=85:5
x+4=17
x=17-4
x=13
10+2x=2.(32-1)
10+2x=2.(9-1)
10+2x=2.8
2x=16-10
2x=6
x=6:2
x=3
2.x-138=23.32
2.x-138=72
2.x=72+138
2.x=210
x=210:2
x=105
[102+(28-2x)]:20-5=1
(102+28-2x):20=6
130-2x=120
2x=130-120
2x=10
x=10:2
x=5
231-(x-6)=1339:13
231-(x-6)=103
x-6=231-103
x-6=128
x=128+6
x=134
123-5.(x+4)=38
5.(x+4)=123-38
5.(x+4)=85
(x+4)=85/5
x+4=17
x=17-4
x=13
10 + 2x = 2(32 - 1)
=> 10 + 2x = 2(9 - 1)
=> 10 + 2x = 2.8
=> 10 + 2x = 16
=> 2x = 16 - 10
=> 2x = 6
=> x = 6/2
=> x = 3
1. tính nhẩm :
53 x 201
=???
2. tìm x , biết :
a) 4 nhân x - 15 nhân 4 = 6 nhân 15 + x
b) (102 + 28 - 2 nhân x ) : 20 - 5 = 1
c) x nhân 1999 - x = 1999 + 1997 +1999
d) 105 - 5 nhân x = 150:15
e) ( x + 1 ) + ( x+2 ) + ( x + 3 ) + .... + ( x + 6 ) = 78
1.53x201=10653
2.
a)4 xX-15x4=6x15+X
<=>4x-60=90+x
<=>4x-x=60+90
<=>3x=150
<=>x=50
b(102+28-2x):20-5=1
<=>(130-2x):20=6
<=>130-2x=120
<=>2x=10
<=>x=5
c)1999x-x=1999+1997+1999
<=>1998x=5995
<=>\(x\approx3\)
d)105-5x=150:15
<=>105-5x=10
<=>5x=95
<=>x=19
e)(x+1)+(x+2)+(x+3)+...+(x+6)=78
<=>6x+21=78
<=>6x=57
<=>x=9,5
1) 53x201=53x200+53=10600+53=10653
2a)
4x-15x4=6x15+x
4x-60=90+x
4x-x=90+60
3x=150
x=50
b) x=5
c) x=3
d)x=19
e) x=9,5
a)1032 : ( x: 4) = 6
b)123-5.(x+4)=38
c)10+2x=2.(32-1)
d)2.x-138=23.32
e)[102+(28-2x)]:20-5=1
f)231-(x-6)=1339:13
g)|x-2|=4+-6-(-5)
h)|x-155|=-223+456
c) 10 + 2x = 2(32 - 1)
10 + 2x = 16
2x = 6
x = 3
d) 2x - 138 = 23.32
2x - 138 = 72
2x = 72 + 138
2x = 210
x = 210/2 = 105
a) 1032 : (x : 4) = 6
x : 4 = 1032 : 6 = 172
X = 172 x 4 = 688
b) 123 - 5(x + 4) = 38
5(x + 4) = 123 - 38 = 85
x + 4 = 85/5 = 17
x = 17 - 4 = 13
f.x=134
g.x=5 ;x=-1
h. x=388 ; x=-78
1 x 3 x 5 + 2 x6 x10 + 4 x 12 x 20
1 x 5 x 7 + 2 x 10 x 14 + 4 x 20 x 28
1 x 3 x 5 + 2 x 6 x 10 + 4 x 12 x 20
=15 + 120 + 960
= 135 + 960
=1095
1 x5 x 7 + 2 x 10 x 14 + 4 x 20 x 28
=35 + 280 + 2240
= 2555
k nha
????????????????????????????????????????????
Tính hợp lý nếu có thể:
a) -52 x (-2)2 + (-3)3
b) (-19 - 46) : (-13) - (-52) x (-22)
c) (135 - 35) x (-47) + 53 x (-48 - 52)
d) [(-3)13 : 95 - 73] : (-52) - |-14|
e) -105 : (-15) - 21 - 9 x (-2)3
g) (-51) x (-29) - 131 x 51 + |-102|
h) (83 - 107 - 854) - (107 - 554) + 117
k) (-5)2 x 32 x 53 x (-17) x (-1)2n, n thuộc N
n) -28 x (-19) - (-64) x 28 x 17 x |-28|
m) 73 x (28 - 56) - 28 x (73 + 56)
a: \(=-25\cdot4-27=-100-27=-127\)
b: \(=-65:\left(-13\right)-25\cdot4=5-100=-95\)
c: \(=100\cdot\left(-47\right)+53\cdot\left(-100\right)=100\cdot\left(-100\right)=-10000\)
d: \(=\left[\left(-3\right)^{13}:3^{10}-73\right]:\left(-5\right)^2-14\)
\(=\left(-100\right):25-14=-4-14=-18\)
bài 7:tính nhanh
a (145 x 99+145)-(143 x 102-143) b,54 x 47 - 47 x 53 - 20 -27
c, 10000 - 47 x 72 - 47 x 28 d, 3457 - 27 x 48 - 48 x 73 + 6543
a) \(\left(145\times99+145\right)-\left(143\times102-143\right)\)
\(=\left[145\times\left(99+1\right)\right]-\left[143\times\left(102-1\right)\right]\)
\(=\left(145\times100\right)-\left(143\times101\right)\)
\(=14500-14443\)
\(=57\)
b) \(54\times47-47\times53-20-27\)
\(=47\times\left(54-53\right)-20-27\)
\(=47-20-27\)
\(=0\)
c) \(10000-47\times72-47\times28\)
\(=10000-47\times\left(72+28\right)\)
\(=10000-47\times100\)
\(=10000-4700\)
\(=5300\)
d) \(3457-27\times48-48\times73+6543\)
\(=\left(3457+6543\right)-48\times\left(27+73\right)\)
\(=10000-48\times100\)
\(=10000-4800\)
\(=5200\)
Tìm x
a) -x/27 -1 = 2/3
b) x - 4 = -14/35 : 20/-21
c) x + 2/3 = -1/12 . -4/5
d) 1/5 - 3/5x = -15/14 :20/-21
e) -3/7x = 3/5 . 28/9
f)1/2x + 3/5x = -2/3
a: =>x/27+1=-2/3
=>x/27=-5/3
=>x=-45
b: \(\Leftrightarrow x-4=\dfrac{2}{5}:\dfrac{20}{21}=\dfrac{2}{5}\cdot\dfrac{21}{20}=\dfrac{42}{100}=\dfrac{21}{50}\)
=>x=221/50
c: \(\Leftrightarrow x+\dfrac{2}{3}=\dfrac{4}{60}=\dfrac{1}{15}\)
=>x=1/15-2/3=1/15-10/15=-9/15=-3/5
d: \(\Leftrightarrow x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{15}{14}\cdot\dfrac{21}{20}\)
=>\(x\cdot\dfrac{3}{5}=\dfrac{1}{5}-\dfrac{3}{2}\cdot\dfrac{3}{4}=\dfrac{1}{5}-\dfrac{9}{8}=\dfrac{-37}{40}\)
=>x=-37/24
e: =>-3/7x=84/45
=>x=-196/45
f: =>11/10x=-2/3
=>x=-20/33