0,5+0,(3)-0,1(6)/2,5+1,(6)-0,8(3)
0,5+0,(3)-0,1(6)/2,5+1(6)-0,8(3)
G = \(\dfrac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
Bài 1 : Viết dưới dạng phân số tối giản :
a, 0,(24)
b, 0,2(45)
c, 2,5(324)
d, 0,5(3)
Bài 2:
Rút gọn M = 0,5 + 0,(3) - 0,1(6)/ 2,5 + 1,(6) - 0,8(3)
Bài 1:
a) 0,24 = 6/25
b) 0,245 = 49/200
c) 2,5324 = 5/2
d) 0,5 = 1/2
a) \(0,\left(24\right)=\frac{24}{99}=\frac{8}{33}\)
b)\(0,2\left(45\right)=\frac{245-2}{990}=\frac{243}{990}=\frac{27}{110}\)
c)\(2,5\left(324\right)=2+0,5\left(324\right)=2+\frac{5324-5}{9990}=2+\frac{197}{370}=\frac{937}{370}\)
d) \(0,5\left(3\right)=\frac{53-5}{90}=\frac{48}{90}=\frac{8}{15}\)
Bài 2 : \(M=\frac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
\(M=\frac{\frac{1}{2}+\frac{1}{3}-\frac{16-1}{90}}{\frac{5}{2}+\frac{5}{3}-\frac{83-8}{90}}\)
\(M=\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{6}}{\frac{5}{2}+\frac{5}{3}-\frac{5}{6}}=\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{6}}{5\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{6}\right)}=\frac{1}{5}\)
tính
\(\frac{0,5+0,\left(3\right)+0,1\left(6\right)}{2,5+1,\left(6\right)+0,8\left(3\right)}\)
0,5+0,(3)+0,1(6)/2,5+0,1(6)+0,8(3)
=0,5+1/3+1/6/2,5+1/6+5/6
=1/3,5=2/7
k mk nha
tính \(\dfrac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
\(\frac{0,5+\frac{1}{3}-\frac{1}{6}}{2,5+\frac{5}{3}-\frac{5}{6}}\)
= \(\frac{\frac{3}{6}+\frac{2}{6}-\frac{1}{6}}{\frac{15}{6}+\frac{10}{6}-\frac{5}{6}}\)
= \(\frac{\frac{4}{6}}{\frac{20}{6}}\)
= \(\frac{4}{6}:\frac{20}{6}\)
= \(\frac{2}{3}.\frac{3}{10}\)
= \(\frac{1}{5}\)
Tính
\(\frac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
Đặt GTBT là A, ta có:
\(A=\frac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
\(A=\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{6}}{\frac{5}{2}+\frac{5}{3}-\frac{5}{6}}\)
\(A=\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{6}}{5\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{6}\right)}=\frac{1}{5}\)
\(\frac{1}{5}\)nhé
hok tốt
\(\frac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)= ?
Thực hiện phép tính
\(\frac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
tính giá trị biểu thức
\(\frac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)