\(m=\dfrac{8^{10}+4^{10}}{8^4+4^{11}}=\dfrac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\dfrac{2^{30}+2^{20}}{2^{12}+2^{22}}=\dfrac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}=\dfrac{2^{20}}{2^{12}}=2^8=256\)Vậy \(m=256\)

= ( 2.4)¹⁰ + 4¹¹ / (2.4)⁴ + 4⁸

= 2¹⁰ . 4¹⁰ + 4¹¹ / 2⁴ . 4⁴ + 4⁸

= 2⁶ . 4²¹/ 2 . 4¹²

= 2⁷ . 4⁹ / 2 . 4 

= 2⁶ . 4⁸

= 2⁶ . ( 2 . 2) ⁸

= 2⁶ . 2⁸ . 2⁸ 

= 2 . 2² . 2⁸

= 2¹¹

= 2048

=256                      

\(M=\sqrt{\dfrac{2^{30}-2^{20}}{2^{22}-2^{12}}}=\sqrt{\dfrac{2^{20}\left(2^{10}-1\right)}{2^{12}\left(2^{10}-1\right)}}=\sqrt{2^8}=\sqrt{16^2}=16\)

M= (2x4)^10 + 4^11 / (2x4)^4 + 4^8

M= 2^10 x 4^10 + 4^11 / 2^4 x 4^4 + 4^8

M= 2^6 x 4^21 / 2 x 4^12

M=2^7 x 4^9 / 2 x 4

M=2^6 x 4^8

M=2^6 x (2x2)^8

M=2^6 x 2^8 x 2^8 = 2 x 2^2 X 2^8 = 2^11 = 2048

nguyển như quỳnh bạn Nguyễn Đình Phương  làm đúng rồi bạn **** bạn ấy đi nhé 

=(2^3)^10+(2^2)10/(2^2)^4+(2^4)^11

=2^30+2^20/2^12+2^22

=2^20(2^10+1)/2^12(2^10+1)

=2^8

=256

1: =72/90+65/90=137/90

2: =24/56-77/56=-53/56

3: =-7/10+4/5=1/10

4: =15/100-4/100=11/100

5: =4/6-5/6=-1/6

6: =10/40-15/40-76/40=-81/40

7: =-9/10+7/18

=-81/90+35/90=-46/90=-23/45

8: =27/90-55/90=-28/90=-14/45

9: =36/60-50/60-35/60=-49/60

10: =-4/9+5/6-3/8

=-32/72+60/72-27/72

=1/72

\(1,\dfrac{4}{5}+\dfrac{13}{18}=\dfrac{72}{90}+\dfrac{65}{90}=\dfrac{137}{90}\)

\(2,\dfrac{3}{7}-\dfrac{11}{8}=\dfrac{24}{56}-\dfrac{77}{56}=\dfrac{-53}{56}\)

\(3,-\dfrac{7}{10}-\left(-\dfrac{4}{5}\right)=-\dfrac{7}{10}-\left(-\dfrac{8}{10}\right)=\dfrac{1}{10}\)

\(4,\dfrac{3}{20}-\dfrac{1}{25}=\dfrac{75}{500}-\dfrac{20}{500}=\dfrac{55}{500}=\dfrac{11}{100}\)

\(5,\dfrac{2}{3}-\dfrac{5}{6}=\dfrac{12}{18}-\dfrac{15}{18}=-\dfrac{3}{18}=-\dfrac{1}{6}\)

\(6,\dfrac{1}{4}+\left(-\dfrac{3}{8}\right)-\dfrac{19}{10}=\dfrac{8}{32}+\left(-\dfrac{12}{32}\right)-\dfrac{19}{10}=-\dfrac{4}{32}-\dfrac{19}{10}\)

\(=-\dfrac{1}{8}-\dfrac{19}{10}=-\dfrac{10}{80}-\dfrac{152}{80}=-\dfrac{162}{80}=-\dfrac{81}{40}\)

\(7,-\dfrac{9}{10}-\left(-\dfrac{7}{18}\right)=-\dfrac{162}{180}-\left(-\dfrac{70}{180}\right)=-\dfrac{92}{180}=-\dfrac{23}{45}\)

\(8,\dfrac{3}{10}-\dfrac{11}{18}=\dfrac{54}{180}-\dfrac{110}{180}=-\dfrac{56}{180}=-\dfrac{14}{45}\)

\(9,\dfrac{3}{5}-\dfrac{5}{6}+\left(-\dfrac{7}{12}\right)=\dfrac{18}{30}-\dfrac{25}{30}+\left(-\dfrac{7}{12}\right)=-\dfrac{7}{30}+\left(-\dfrac{7}{12}\right)\)

\(=-\dfrac{84}{360}+\left(-\dfrac{210}{360}\right)=-\dfrac{294}{360}=-\dfrac{49}{60}\)

\(10,-\dfrac{4}{9}-\dfrac{-5}{6}-\dfrac{3}{8}=-\dfrac{24}{54}-\dfrac{-45}{54}-\dfrac{3}{8}\)

\(=\dfrac{21}{54}-\dfrac{3}{8}=\dfrac{7}{18}-\dfrac{3}{8}=\dfrac{56}{144}-\dfrac{54}{144}=\dfrac{2}{144}=\dfrac{1}{72}\)

`@mt`

a: Dấu hiệu là thời gian giải bài

Số các giá trị là 10

b: 

Mốt là 7 và 8

c: Phần lớn làm xong trong 7 hoặc 8 phút

\(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}.\left(2^{10}+1\right)}{2^{12}.\left(2^{10}+1\right)}=\frac{2^{20}}{2^{12}}=2^8=256\)

\(\frac{\left(8^{10}+4^{10}\right)}{\left(8^4+4^{11}\right)}\\ =\frac{\left(2^{30}+2^{20}\right)}{\left(2^{12}+2^{22}\right)}\\ =\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(1+2^{10}\right)}\\ =\frac{2^{10}}{2^{12}}=2^2=4\)

Ta có : 8^10 + 4^10 / 8^4 + 4^11 
= (2^3)^10 + (2^2)^10 / (2^3)^4 + (2^2)^11 
=2^30 + 2^20 / 2^12 +2^22 
= 2^20(2^10 +1) / 2^12( 2^10 +1) 
= 2^8 = 256