Thực hiện phép tính một cách hợp lí
(3.4.2^16)^2.(11.2^13.4^11-169)
Thực hiện phép tính:(3.4.2^16)^2/11.2^13.4^11-\(16^9\)
Tính bằng cách hợp lí
(3.4.2^16)/11.2^13.4^11-16^9 các bạn ơn giúp minh với minh đang gấp nhớ ghi cách giải cho minh với nhé
Thực hiện các phép tính;
a, A=1+2+2^2+2^3+...+2^2018
b,B=1.2.3...9-1.2.3...8-1.2.3...7.8^2
c,C=(3.4.2^16)^2/11.2^13.4^11-16^9
thôi minh giai duoc roi .thanks ban nhieu
\(\text{Thực hiện các phép tính sau một cách hợp lý:}\)
\(a\)) \(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)
\(b\)) \(1.2.3...9-1.2.3...8-1.2.3...7.8^2\)
\(c\)) \(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(d\)) \(1152-\left(374+1152\right)+\left(-65+374\right)\)
\(e\)) \(13-12+11+10-9+8-7-6+5-4+3+2-1\)
Tính bằng cách hợp lí
\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot9}=2\)
Tính:
A= ( 3.4.2^16)^2 / 11.2^13.4^11-16^9
bạn sai rồi
Oh
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.3^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2}{9}=2\)
\(A=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(A=\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)
\(A=\frac{3^2.2^4.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(A=\frac{3^2.2^{36}}{11.2^{13}.2^{22}-2^{36}}\)
\(A=\frac{3^2.2^{36}}{11.2^{35}-2.2^{35}}\)
\(A=\frac{3^2.2^{36}}{\left(11-2\right).2^{35}}\)
\(A=\frac{3^2.2}{9}=\frac{18}{9}=2\)
Tính :
A=(3.4.2^16)^2 / 11.2^13.4^11-16^9
\(A=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.\left(2^2\right)^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2}{2}=2\)
Tính theo cách hợp lý
a) (10^2+11^2+12^2):(13^2+14^2)
b)1.2.3....9 -1.2.3...8-1.2.3...7.8^2
c)(3.4.2^16)^2 /11.2^13.4^11-16^9
a: \(\dfrac{10^2+11^2+12^2}{13^2+14^2}=\dfrac{100+121+144}{169+196}=\dfrac{365}{365}=1\)
c: \(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot\left(11-2\right)}=2\)
(3.4.2^16)^2 . (11.2^13.4^11-16^9)=?
giúp mik cách giải nha