(12x-5)(4x-1)+(3x-7)(1-16x)=81
Giúp mk vs
13. tìm x biết:
(12x - 5) (4x - 1) + (3x - 7) (1 - 16x) = 81
giúp mk nhé!!
(12x - 5) (4x - 1) + (3x - 7) (1 - 16x) = 81
=> 48x2 - 12x - 20x + 5 + 3x - 48x2 - 7 + 112x = 81
=> 83x = 83
=> x = 1
(12x-5)(4x-1)+(3x-7)(1-16x)=81
tim x do ....giup minh vs
(12x-5).(4x-1).(3x-7).(1-16x)=81
\(\left(12x-5\right)\left(4x-1\right)\left(3x-7\right)\left(1-16x\right)=81\)
\(\Rightarrow\left(48x^2-12x-20x+5\right)\left(3x-7\right)\left(1-16x\right)=81\)
\(\Rightarrow\left(48x^2-32x+5\right)\left(3x-7\right)\left(1-16x\right)=81\)
\(\Rightarrow\left(144x^3-336x^2-96x^2+224x+15x-35\right)\left(1-16x\right)=81\)
\(\Rightarrow\left(144x^3-432x^2+239x-35\right)\left(1-16x\right)=81\)
\(\Rightarrow144x^3-2304x^4-432x^2+6912x^3+239x-3824x^2-35+560x=81\)
\(\Rightarrow-2304x^4+7056x^3-4256x^2+799x-116=0\)
\(\Rightarrow\left[{}\begin{matrix}x_1\approx2,3\\x_2\approx0,5\end{matrix}\right.\)
tìm x
(12x-5)(4x-1)+(3x-7)(1-16x)=81
xin mk với đang vội
(12x-5)(4x-1)+(3x-7)(1-16x)=81
48x^2-12x-20x+5+3x-48x^2-7+112x=81
83x-2=81
83x=83
x=1
(12x-5)(4x-1)+(3x-7)(1-16x)=81
12x ( 4x- 1) - 5(4x-1) + 3x(1-16x) -7(1-16x) =81
12x . 4x -12x - 20x + 5 + 3x - 3x. 16x - 7 + 7.16x = 81
48x^2 -12x - 20x + 5 + 3x - 48x^2 - 7 + 112x = 81
(48x^2 - 48x^2) + (112x - 12x - 20x +3x) - ( 7 - 5) =81
83x = 81 + 2
83x =83
x=1
ht nha bạn
Rút gọn vế trái:
VT = (12x – 5)(4x – 1) + (3x – 7)(1 – 16x)
= 12x.(4x – 1) + (–5).(4x – 1) + 3x.(1 – 16x) + (–7).(1 – 16x)
= 12x.4x+ 12x.(–1) + (–5).4x + (–5).(–1) + 3x.1 + 3x.(–16x) + (–7).1 + (–7).(–16x)
= 48x2 – 12x – 20x + 5 + 3x – 48x2 – 7 + 112x
= (48x2 – 48x2) + (– 12x – 20x + 3x + 112x) + (5 – 7)
= 83x – 2
Vậy ta có:
83x – 2 = 81
83x = 81 + 2
83x = 83
x = 83 : 83
x = 1.
(12x-5)(4x-1)+ (3x-7)(1-16x)=81
(12x - 5)(4x - 1) + (3x - 7)(1 - 16x) = 81
48x2 - 32x + 5 - 48x + 115x - 7 = 81
83x - 2 = 81
83x = 83
=> x = 1
Sửa lại dòng 2 : 48x2 - 32x + 5 - 48x2 + 115x - 7 = 81
( 12x - 5 ) ( 4x - 1 ) + ( 3x - 7 ) (1 - 16x ) = 81
(12x - 5)(4x - 1) + (3x - 7)(1 - 16x) = 81
(12x-5).(4x-1)+(3x-7).(1-16x) = 81
=> 48x2-12x-20x+5+3x-48x2-7+112x = 81
=> 83x-2 = 81
=> 83x = 81+2
=> 83x = 83
=> x = 83:83
=> x = 1
(12x-5)×(4x-1)+(3x-7)×(1-16x)=81
( 12x - 5 ) ( 4x -1 ) + ( 3x - 7 ) ( 1 - 16x ) = 81
48x2 - 12x - 20x + 5 + 3x - 48x2 - 7 + 112x = 81
83x = 81 - 5 + 7
83x = 83
x = 83/83
x = 1
Chúc bn hok tốt nha
Tìm x, biết:
( 12x-5 )( 4x-1 ) + ( 3x-7 )( 1-16x ) = 81
\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\text{⇔}48x^2-32x+5-48x^2-7+115x=81\)
\(\text{⇔}83x-2=81\)
\(\text{⇔}83x=83\)
\(\text{⇔}x=1\)
Vậy: x=1
Ta có: \(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
\(\Leftrightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\)
\(\Leftrightarrow83x=83\)
hay x=1