1 She failed to do everything she was supposed to do

2 There is no likelihood that anyone will apply for this post

3 He succeeded in finishing the English test in time

4 There is no likelihood that the situation will improve in the near future

5 There is a chance that you will get what you want there

6 Don't check your answers before answering all the questions

7 I won't give an opinion before thinking this through

8 The judge will decide after hearing all the evidence

9  I won't be able to have a holiday until I save enough money

10 There is little likelihood that my sister will win the first prize in the singing contest

11 He made no reference of his new job when I last spoke to him

1 She failed to do everything she was supposed to do

2 There is no likelihood that anyone will apply for this post

3 He succeeded in finishing the English test in time

4 There is no likelihood that the situation will improve in the near future

5 There is a chance that you will get what you want there

6 Don't check your answers before answering all the questions

7 I won't give an opinion before thinking this through

8 The judge will decide after hearing all the evidence

9  I won't be able to have a holiday until I save enough money

10 There is little likelihood that my sister will win the first prize in the singing contest

11 He made no reference of his new job when I last spoke to him

Câu 2: 

a) Ta có: \(-7x+21< 0\)

\(\Leftrightarrow-7x< -21\)

hay x>3

Vậy: S={x|x>3}

Câu 2: 

b) Ta có: x<y

nên -x>-y

\(\Leftrightarrow-x+2021>-y+2021\)

mà \(-y+2021>-y+2020\)

nên -x+2021>-y+2020

hay 2021-x>2020-y

C1

A. baseball - football - volleyball - basketball - ice hockey

B. judo - gymnastics

C. skiing - ice-skating - horse-riding

A-PLAY

B=DO

C-GO

1) Vì x=25 thỏa mãn ĐKXĐ nên Thay x=25 vào biểu thức \(A=\dfrac{\sqrt{x}-2}{x+1}\), ta được:

\(A=\dfrac{\sqrt{25}-2}{25+1}=\dfrac{5-2}{25+1}=\dfrac{3}{26}\)

Vậy: Khi x=25 thì \(A=\dfrac{3}{26}\)

2) Ta có: \(B=\dfrac{\sqrt{x}-3}{\sqrt{x}+1}+\dfrac{2x+8\sqrt{x}-6}{x-\sqrt{x}-2}\)

\(=\dfrac{\left(\sqrt{x}-3\right)\left(\sqrt{x}-2\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}+\dfrac{2x+8\sqrt{x}-6}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{x-5\sqrt{x}+6+2x+8\sqrt{x}-6}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{3x+3\sqrt{x}}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{3\sqrt{x}\left(\sqrt{x}+1\right)}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{3\sqrt{x}}{\sqrt{x}-2}\)

câu 3 chứ

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làm hộ gì vậy bạn,ko có đề sao làm

ko có pài sao giúp