phan tich da thuc thanh nhan tu 1-3x-x^3+3x^2
phan tich da thuc thanh nhan tu
x3-3x2-3x+1
x3-3x2-3x+1=x3+1-3x2-3x
=(x+1)(x2-x+1)-3x(x+1)
=(x+1)(x2-x+1-3x)
=(x+1)(x2-4x+1)
phan tich da thuc thanh nhan tu :x^5+2x^4+3x^3+2x^2+2x+1
x^5+2x^4+2x^3+2x^2+2x+1
=(x^5+x^4)+(x^4+x^3)+(x^3+x^2)+(x^2+x)+(x+1)
=x^4(x+1)+x^3(x+1)+x^2(x+1)+x(x+1)+(x+1)
=(x+1)(x^4+x^3+x^2+x+1)
phan tich da thuc thanh nhan tu :
2x(x-1)-3x+3
2x(x-1)-3x+3
=2x(x-1)-(3x-3)
=2x(x-1)-3(x-1)
=(x-1)(2x-3)
tim x bang cach phan tich da thuc thanh nhan tu
x3-3x2+3x-1=0
\(x^3-3x^2+3x-1\) =0
=>\(\left(x-1\right)^3\)=0
=>x-1=0
=>x=1
vậy x =1
\(x^3-3x^2+3x-1=0\)
\(\Leftrightarrow\left(x-1\right)^3\)
\(\Leftrightarrow x-1=0\)
\(\Leftrightarrow x=1\)
phan tich da thuc thanh nhan tu x2-3x+18
phan tich da thuc x^3+3x-4 thanh nhan tu
x^3 + 3x -4 = x^3 - 1 + 3x - 3 = (x-1)(x^2-x+1) + 3(x-1) = (x-1)(x^2-x+1+3) = (x-1)(x^2-x+4)
nhớ cho mik nha
minh h cho 1 cai nhung o cho x^3-1 phai bang (x-1)(x^2+x+1)
Phan tich da thuc thanh nhan tu (x²+3x)^2+7x²+21x+10
phan tich da thuc thanh nhan tu
x^2-3x+3y-y^2
x2 - 3x + 3y - y2
= (x2 - y2) - (3x - 3y)
= (x - y)(x + y) - 3(x - y)
= (x - y)(x + y - 3)
= x2 - y2 - 3x+3y = (x-y)(x+y) -3(x-y)
= (x+y+3)(x-y)
nhớ chọn cho mk nha!!!!!!
phan tich da thuc thanh nhan tu
3x^3 +12x^2 +12x
tu de bai suy ra: 3x(x^3+4x+4)=3x(x+2)^2