Tính :
a) \(237.\left(-26\right)+26.137\)
b) \(63.\left(-25\right)+25.\left(-23\right)\)
Tính:
a)237.(-26)+26.137
b)63.(-25)+25.(-23)
a) 237 . ( -26 ) + 26 . 137
= ( - 237 ) . 26 + 26 . 137
= 26 . [ ( -237 ) + 137 ]
= 26 . ( -100 )
= -2600
b) 63 . ( -25 ) + 25 . ( -23 )
= ( -63 ) . 25 + 25 . ( -23 )
= 25 . [ ( -63 ) + ( -23 ) ]
= 25 . ( -86 )
= -2150
Tính:
a) 237.(-26) + 26.137 b) 63.(-25) + 25.(-23)
= -237. 26 + 26. 137
26.( - 237 + 137 )
=26. (-100)
= -2600
a) 237.(-26) + 26.137
= -237.26 + 26.137
= 26.(-237 + 137)
= 26.(-100)
= -2600
b) 63.(-25) + 25.(-23)
= -63.25 + 25.(-23)
= 25.(-63 - 23)
= 25.(-86)
= -2150
=63 . (-25 ) + (-25).23
-25 .(63+ 23)
-25 . 86
= -2150
Tính B = \(\left(28^2+26^2+24^2+...+4^2+2^2\right)-\left(27^2+25^2+23^2+...+3^2+1^2\right).\)
Trả lời :
Sử dụng tổng xích ma nha ( k biết bấm thì bảo tui )
B = -10
Study well
\(=\left(28^2-27^2\right)+\left(26^2-25^2\right)+....+\left(2^2-1^2\right)\)
\(=\left(28-27\right)\left(28+21\right)+\left(26-25\right)\left(26+25\right)+...+\left(2-1\right)\left(2+1\right)\)
\(=55+51+...+3\)
\(=\frac{\left[\left(55-3\right):4+1\right]\left(55+3\right)}{2}\)
\(=406\)
Lê Tài Bảo Châu làm đúng rồi nha em !!!
237 . (-26)+26.137
63 .(-25)+25.(-23)
các bạn làm nhanh hộ mình và đúng trong hôm nay nha thank
237 . ( -26 ) + 26 . 137
= ( -237 ) . 26 + 26 . 137
= 26 . [ ( -237 ) + 137 ]
= 26 . ( -100 )
= -2600
63 . ( -25 ) + 25 . ( -23 )
= ( -63 ) . 25 + 25 . ( -23 )
= 25 . [ ( -63 ) + ( -23 ) ]
= 25 . ( -86 )
= -2150
237.(-26)+26.137
= -237.26+26.137
= 26.(-237+137)
= 26.-100
= -2600
63.(-25)+25.(-23)
= -63.25+25.(-23)
= 25.[-63+(-23)]
= 25.(-86)
= -2150
237 . (-26)+26.137
=-6162 + 3562
=-2600
*63 .(-25)+25.(-23)
=-1575 + -575
=-2150
Giải các phương trình sau bằng cách đưa về dạng ax + b = 0:
\(a,\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(b,\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)=\left(\frac{x+4}{96}+1\right)+\left(\frac{x+5}{95}+1\right)\)
Tính tổng :
a) \(\left(-24\right)+6+10+24\)
b) \(15+23+\left(-25\right)+\left(-23\right)\)
c) \(\left(-3\right)+\left(-350\right)+\left(-7\right)+350\)
d) \(\left(-9\right)+\left(-11\right)+21+\left(-1\right)\)
a) (-24) + 6 + 10 + 24
= [(-24) + 24] + 6 + 10
= 0 + 6 + 10
= 16
b) 15 + 23 + (-25) + (-23)
= [15+ (-25)] + [23 +(-23)]
= -10 + 0
= -10
c) (-3) + (-350) + (-7) + 350
=[-350 + 350] + [-3+(-7)]
= 0 + (-10)
= -10
d) (-9) + (-11) +21 + (-1)
= [ (-9) + (-11) ] + [ 21 + (-1)]
= -20 + 20
= 0
a) \(\left(-24\right)+6+10+24\)
\(=16\)
b) \(15+23+\left(-25\right)+\left(-23\right)\)
\(=-10\)
c) \(\left(-3\right)+\left(-350\right)+\left(-7\right)+350\)
\(=-10\)
d) \(\left(-9\right)+\left(-11\right)+21+\left(-1\right)\)
\(=0\)
\(a,\left(-24\right)+6+10+24\)
=\(\left[\left(-24\right)+24\right]+6+10\)
\(=0+16=16\)
b, \(15+23+\left(-25\right)+23\)
\(=\left[15+\left(-25\right)\right]+\left[\left(-23\right)+23\right]\)
\(=-10+0=-10\)
c, \(\left(-3\right)+\left(-350\right)+\left(-7\right)+350\)
\(=\left[\left(-3\right)+\left(-7\right)\right]+\left\{\left(-350\right)+350\right\}\)
\(=-10+0=-10\)
d, \(\left(-9\right)+\left(-11\right)+21+\left(-1\right)\)
\(=\left\{\left(-9\right)+\left(-11\right)\right\}+\left[21+\left(-1\right)\right]\)
\(=-20+20=0\)
Tính:
a)\(A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\left( { - 4,6} \right);\) b) \(B = \left( {\frac{{ - 7}}{9}} \right).\frac{{13}}{{25}} - \frac{{13}}{{25}}.\frac{2}{9}\)
a)
\(\begin{array}{l}A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\left( { - 4,6} \right)\\A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\frac{{ - 23}}{5}\\A = \frac{{5.\left( { - 3} \right).11.\left( { - 23} \right)}}{{11.23.5.5}}\\A = \frac{3}{5}\end{array}\)
b)
\(\begin{array}{l}B = \left( {\frac{{ - 7}}{9}} \right).\frac{{13}}{{25}} - \frac{{13}}{{25}}.\frac{2}{9}\\B = \frac{{13}}{{25}}.\left( {\frac{{ - 7}}{9} - \frac{2}{9}} \right)\\B = \frac{{13}}{{25}}.(-1)\\B = \frac{{-13}}{{25}}.\end{array}\)
1. = 13
2. = 346
3.= -69
4. = -2600
5. -2150
Giải các phương trình sau bằng cách đưa về dạng ax + b = 0:
\(a,\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(b,\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)=\left(\frac{x+4}{96}+1\right)+\left(\frac{x+5}{95}+1\right)\)
a. \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(\Leftrightarrow\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\)
\(\Leftrightarrow x=23\) (Vì \(\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)\ne0\) )
b. \(\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)=\left(\frac{x+4}{96}+1\right)+\left(\frac{x+5}{95}+1\right)\)
\(\Leftrightarrow\frac{x+100}{98}+\frac{x+100}{97}-\frac{x+100}{96}-\frac{x+100}{95}=0\)
\(\Leftrightarrow\left(x+100\right)\left(\frac{1}{98}+\frac{1}{97}-\frac{1}{96}-\frac{1}{95}\right)=0\)
\(\Leftrightarrow x=-100\) (Vì \(\left(\frac{1}{98}+\frac{1}{97}-\frac{1}{96}-\frac{1}{95}\right)\ne0\) )