20 :22-59:58
20 : 22 - 59 : 58
20 : 22 - 59 : 58
= 20 : 4 - 5
= 5 - 5
= 0
20: 22- 59: 58= 20 : 4 - 5=5 - 5= 0
20 : 22+ 59 : 58
=20:4+51
=20 : 4 +1
=5+1
=6 (đúng ko ạ )
sai rồi bạn:
20: 22 + 59 : 58
= 20 : 4 + 51
= 20 : 4 + 5
= 5 + 5
= 10
(bởi vì a1 = a đó)
ghi lộn rồi như này mới đúng nè
= 20 : 4+51
= 20 : 4 + 5
= 5+5
=10 ''tôi ghi tôi cũng ko biết đúng hay sai đâu hihi''
Thực hiện phép tính (Tính nhanh nếu có thể)
a) 20 : 2 2 − 5 9 : 5 8
b) ( 5 19 : 5 17 − 4 ) : 7 0
c) 295 − ( 31 − 2 2 .5 ) 2
a) 20 : 2 2 − 5 9 : 5 8 = 5 − 5 = 0
b) ( 5 19 : 5 17 − 4 ) : 7 0 = ( 5 2 − 4 ) : 1 = 21
c) 295 − ( 31 − 2 2 .5 ) 2 = 295 − 11 2 = 174
a 20:2^2 -5^9:5^8
= 20:4 - 5^1
=5-5
=0
a) 20 : 2 2 − 5 9 : 5 8 = 5 − 5 = 0.
b) ( 5 19 : 5 17 − 4 ) : 7 0 = ( 5 2 − 4 ) : 1 = 21.
c) 295 − ( 31 − 2 2 .5 ) 2 = 295 − 11 2 = 174.
;)
Thực hiện phép tính rồi phân tích kết quả ra thừa số nguyên tố:
a) 75 + 58 . 50 - 58 . 25
b) 20 : 2 2 - 5 9 : 5 8
c) 5 19 : 5 17 - 4 : 7
Thực hiện phép tính (tính nhanh nếu có thể)
a)3 . 52 + 15 . 22 - 26 : 2
b)53. 2 - 100 : 4 + 23. 5
c)62 : 9 + 50 . 2 - 33 . 33
d)32 . 5 + 23 . 10 - 81 : 3
e)513 : 510 - 25 . 22
f)20 : 22 + 59 : 58
a) \(3.5^2+15.2^2-26\div2\)
= 3.25 + 15.4 - 13
= 75 + 60 - 13
= 135 - 13
= 122
b) \(5^3.2-100\div4+2^3.5\)
= 125.2 - 25 + 8.5
= 250 - 25 + 40
= 225 + 40
= 265
c)\(6^2\div9+50.2-3^3.33\)
= 36 : 9 + 100 - 9.33
= 4 + 100 - 297
= 104 - 297
= -193
d)\(3^2.5+2^3.10-81\div3\)
= 9.5 + 8.10 - 27
= 45 + 80 - 27
= 125 - 27
= 98
e) \(5^{13}\div5^{10}-25.2^2\)
= 53 - 25.4
= 125 - 100
= 25
f) \(20\div2^2+5^9\div5^8\)
= 20 : 4 + 5
= 5 + 5
= 10
Cho A=\(\frac{1}{20}+\frac{1}{21}+\frac{1}{22}+...+\frac{1}{58}+\frac{1}{59}.Chứngtỏ\)rằng A<\(\frac{3}{2}\)
ta có
A=1/20 + 1/21+1/22+....+1/59
=(1/20+1/21+...+1/39)+(1/40+1//41+....+1/59)<1/20.20+1/40.20=1 + 1/2=3/2
vậy A<3/2
Chúc bạn học tốt nha ^-^
cho A = \(\frac{1}{20}+\frac{1}{21}+\frac{1}{22}+...+\frac{1}{58}+\frac{1}{59}\)chứng minh A <\(\frac{3}{2}\)
Ta có \(A=\left(\frac{1}{20}+\frac{1}{21}+\frac{1}{22}+...+\frac{1}{39}\right)+\left(\frac{1}{40}+\frac{1}{41}+...+\frac{1}{59}\right)\)
\(A< \left(\frac{1}{20}+\frac{1}{20}+\frac{1}{20}+...+\frac{1}{20}\right)+\left(\frac{1}{40}+\frac{1}{40}+...+\frac{1}{40}\right)\)
\(A< \frac{20}{20}+\frac{20}{40}\)
\(A< \frac{3}{2}\)
Chứng minh rằng:
11/15 < 1/21 + 1/22 + 1/23+.....+1/58 + 1/59 + 1/60 < 3/2
Đặt A=1/21+1/22+...+1/60=(1/21+1/22+...+1/40)+(1/41+1/42+...+1/60)
Ta có:1/21>1/40, 1/22>1/40,..., 1/39>1/40
=>1/21+1/226+...+1/40>1/40+1/40+...+1/40=1/40.20=1/2
1/41>1/60, 1/42>1/60,...,1/59>1/60
=>1/41+1/42+...+1/60>1/60+1/60+...+1/60=1/60.20=1/3
=>1/21+1/22+...+1/60>1/2+1/3=5/6>11/15
=>A>11/15 (1)
Lại có: 1/21<1/20, 1/22<1/20,...,1/40<1/20
=>1/21+1/22+...+1/40<1/20+1/20+...+1/20=1/20.20=1
1/41<1/40, 1/42<1/40,...,1/60<1/40
=>1/41+1/42+...+1/60<1/40+1/40+...+1/40=1/40.20=1/2
=>1/21+1/22+...+1/60<1+1/2=3/2
=>A<3/2 (2)
Từ (1) và (2)
=>11/15<A<3/2
=>11/15<1/21+1/22+...+1/60<3/2 (đpcm)
Tính nhẩm:
a) 66 - 60 = 98 - 90 = 72 - 70 =
78 - 50 = 59 - 30 = 43 - 20 =
b) 58 - 4 = 67 - 7 = 99 - 1 =
58 - 8 = 67 - 5 = 99 - 9 =
a) 66 - 60 = 6 98 - 90 = 8 72 - 70 = 2
78 - 50 = 28 59 - 30 = 29 43 - 20 = 23
b) 58 - 4 = 54 67 - 7 = 60 99 - 1 = 98
58 - 8 = 50 67 - 5 = 62 99 - 9 = 90
a) 66 - 60 = 6 98 - 90 = 8 72 - 70 = 2
78 - 50 = 28 59 - 30 = 29 43 - 20 = 23
b) 58 - 4 = 54 67 - 7 = 60 99 - 1 = 98
58 - 8 = 50 67 - 5 = 62 99 - 9 = 90
Thực hiện phép tính rồi phân tích kết quả ra thừa số nguyên tố:
a, 75 + 58.50 – 58.25
b, 20: 2 2 – 5 9 : 5 8
c, 5 19 : 5 17 - 4 : 7
d, 47 - 45 . 2 4 - 5 2 . 12 : 14
e, 10 2 : 60 : 5 6 : 5 4 - 3 . 5
f, 2345 - 1000 : 19 - 2 21 - 18 2
g, 500 – {5.[409 – 2 3 . 3 - 21 2 ]+ 10 3 }:15
h, 967 – [8 + 2 . 3 2 – 24:6 + 9 - 7 3 ].5
a, 75 + 58.50 – 58.25 = 3.25 + 58.(50 – 25) = 3.25 + 58.25 = 25.(3+58) = 25.61 = 1525
Ta có: 1525 = 5 2 . 61
b, 20: 2 2 – 5 9 : 5 8 = 20:4 – 5 = 5 – 5 = 0
c, 5 19 : 5 17 - 4 : 7 = 5 2 - 4 : 7 = (25 – 4):7 = 3
d, 47 - 45 . 2 4 - 5 2 . 12 : 14 = 47 – (45.16 – 25.12):14 = 47 – (720 – 300):14 = 47 – 420:14 = 47 – 30 = 17
e, 10 2 : 60 : 5 6 : 5 4 - 3 . 5 = 100 – 60: 5 2 - 15 = 100 – 60:(25 – 15) = 100 – 60:10 = 100 – 6 = 94
Ta có: 94 = 2.47
f, 2345 - 1000 : 19 - 2 21 - 18 2 = 2345 – 1000:(19 – 2. 3 2 ) = 2345 – 1000:(19 – 2.9) = 2345 – 1000:(19 – 18) = 2345 – 1000:1 = 2345 – 1000 = 1345
Ta có: 1345 = 3.269
g, 500 – {5.[409 – 2 3 . 3 - 21 2 ]+ 10 3 }:15 = 500 – {5.[409 – 8 . 3 - 21 2 ]+1000}:15 = 500 – {5.[409 – 3 2 ]+1000}:15 = 500 – {5.(409 – 9)+1000}:15 = 500 – {5.400+1000}:15 = 500 – (2000+1000):15 = 500 – 3000:15 = 500 – 200 = 300
Ta có: 300 = 2 2 . 3 . 5 2
h, 967 – [8 + 2 . 3 2 – 24:6 + 9 - 7 3 ].5 = 967 – [8+2.9 – 4+8].5 = 967 – 30.5 = 967 – 150 = 817
Ta có: 817 = 19.43