bài 1
a,(x+7) :x=4:5
b,(x-20):(x+40)=(x+70):(x-10)
bài 1
a,(x+7) :x=4:5
b,(x-20):(x+40)=(x+70):(x-10)
bài 1
a,(x+7) :x=4:5
b,(x-20):(x+40)=(x+70):(x-10)
a)\(\frac{x+7}{x}=\frac{4}{5}\)
=>5(x+7)=4x
5x+35=4x
5x-4x=-35
x=-35
Vậy x=-35
b)(x-20)/(x+40)=(x+70)/(x-10)
(x-20)*(x-10)=(x+40)*(x+70)
x(x-10)-20(x-10)=x(x+70)+40(x+70)
x2-10x-20x+200=x2+70x+40x+2800
x2-x2-10x-20x-70x-40x=2800-200
0-(10x+20x+70x+40x)=2600
-140x=2600
x=2600/(-140)
x=\(-\frac{130}{7}\)
Vậy x=-130/7
Tính nhẩm:
a) 10 x 7 20 x 4 40 x 2 30 x 3
b) 60 : 2 90 : 3 70 : 7 40 : 2
a) 10 x 7 = ? Nhẩm: 1 chục x 7 = 7 chục 10 x 7 = 70 20 x 4 = ? Nhẩm: 2 chục x 4 = 8 chục 20 x 4 = 80 40 x 2 = ? Nhẩm: 4 chục x 2 = 8 chục 40 x 2 = 80 30 x 3 = ? Nhẩm: 3 chục x 3 = 9 chục 30 x 3 = 90 | b) 60 : 2 = ? Nhẩm: 6 chục : 2 = 3 chục 60 : 2 = 30 90 : 3 = ? Nhẩm: 9 chục : 3 = 3 chục 90 : 3 = 30 70 : 7 = ? Nhẩm: 7 chục : 7 = 1 chục 70 : 7 = 10 40 : 2 = ? Nhẩm: 4 chục : 2 = 2 chục 40 : 2 = 20 |
Tìm x, biết:
a) (x+15) : x = 4:3
b) (x-20) : (x-10) = (x+40) : (x+70)
a) (x + 15) : x = 4 : 3
=> x : x + 15 : x = \(\frac{4}{3}\)
=> 1 + 15 : x = \(\frac{4}{3}\)
=> 15 : x = \(\frac{4}{3}\)- 1 = \(\frac{1}{3}\)
=> x = 15 : \(\frac{1}{3}\)
=> x = 45
phượng quyên là otaku sa( hình đại diện so cute)
(x+20):(x-10)=(x+40):(x+70)
\(\frac{x+20}{x-10}=\frac{x+40}{x+70}\)
\(\Rightarrow\left(x+20\right)\left(x+70\right)=\left(x+40\right)\left(x-10\right)\)
\(x^2+20x+70x+1400=x^2+40x-10x-400\)
\(90x+1400=30x-400\)
\(60x=-1800\)
\(x=-30\)
Tìm x (x-20):(x-10)=(x+40):(x+70)
ĐKXĐ: \(\hept{\begin{cases}x\ne10\\x\ne-70\end{cases}}\)
\(\frac{x-20}{x-10}=\frac{x+40}{x+70}\)
\(\Rightarrow\left(x-20\right)\left(x+70\right)=\left(x+40\right)\left(x-10\right)\)
\(\Rightarrow x^2+70x-20x-1400=x^2-10x+40x-400\)
\(\Rightarrow20x=1000\Rightarrow x=50\)
Vậy x = 50
Tìm x, biết: (x-20):(x-10)=(x+40):(x+70)
\(\frac{x-20}{x-10}=\frac{x+40}{x+70}=\frac{-20-40}{-10-70}=\frac{6}{8}=\frac{3}{4}.\)
\(\Rightarrow4\cdot\left(x-20\right)=3\cdot\left(x-10\right)\Leftrightarrow4x-80=3x-30\Leftrightarrow x=50.\)
bn dinh thuy linh gioi that, toàn dung ngôn ngữ toán hoc nên bai lam rat ấn tuong
Tìm x, biết :
a) (x + 15) : x = 4:3
b) (7,5 - x) : (3,5 + x) = 5:6
c) (x - 20) : (x - 10) = (x + 40) : (x + 70)
\(a,\frac{x+15}{x}=\frac{4}{3}\Rightarrow4x=3x+45\Leftrightarrow x=45\)
\(b,\frac{7,5-x}{3,5+x}=\frac{5}{6}\Rightarrow17,5+5x=45-6x\Leftrightarrow11x=27,5\Rightarrow x=2,5\)
\(c,\frac{x-20}{x-10}=\frac{x+40}{x+70}\Rightarrow\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)
\(\Leftrightarrow x^2+50x-1400=x^2+30x-400\)
\(\Leftrightarrow20x=1000\)
\(\Rightarrow x=50\)
Tìm x biết:
a, (x+15):x =4:3
b, (7,5-x) :(3,5+x)= 5:6
c, (x+20):(x-10)=(x+40):(x+70)
a. \(\frac{\left(x+15\right)}{x}=\frac{4}{3}\Leftrightarrow4x=3\left(x+15\right)\Leftrightarrow4x=3x+45\Leftrightarrow x=45\)
Vậy x=45
b. \(\frac{7,5-x}{3,5+x}=\frac{5}{6}\Leftrightarrow5\left(3,5+x\right)=6\left(7,5-x\right)\Leftrightarrow17,5+5x=45-6x\Leftrightarrow11x=27,5\Leftrightarrow x=2,5\)
Vậy x=2,5
c. \(\frac{x+20}{x-10}=\frac{x+40}{x+70}\Leftrightarrow\left(x+40\right)\left(x-10\right)=\left(x+20\right)\left(x+70\right)\)
\(\Leftrightarrow x^2+30x-400=x^2+90x+1400\Leftrightarrow-60x=-30\Leftrightarrow x=-30\)
Vậy x=-30