Bạn nào có thể nói cho mình biết mấu thân ở lá là ở đâu không ? cảm ơn nhiều nha
Giúp mình đi làm ơn
Please Please
help me
help me
help help help me me
please.............please
Help me, please Đứa bạn có giúp mà mình chả hiểu tại nó làm sai. Giúp mình đi mn! Cảm ơn trước ạ
tham khảo tại:https://hoc24.vn/hoi-dap/tim-kiem?q=Cho+%C4%91a+th%E1%BB%A9c+f+(x)+=+ax3+bx2+cx+dax%5E3+bx%5E2+cx+d++v%E1%BB%9Bi++a+l%C3%A0+s%E1%BB%91+nguy%C3%AAn+d%C6%B0%C6%A1ng+.+Bi%E1%BA%BFt+f+(5)+-+f+(+4+)+=2012+.++Ch%E1%BB%A9ng+minh+f+(7)+-+f+(2)+l%C3%A0+h%E1%BB%A3p+s%E1%BB%91+.&id=249516
Bạn nào có thể nói cho mình biết mấu thân ở lá là ở đâu không ? cảm ơn nhiều nha
Viết văn bản thông báo về kế hoạch sơ kết thi đua chào mừng ngày thành lập Đội
Mình cần gấp, please help me. Mình cần văn bản cụ thể nhé. Cảm ơn nhiều
Ba lớp 7A 7B 7C có 94 học sinh tham gia trồng cây. Mỗi học sinh lớp 7A trồng được 3 cây, Mỗi học sinh lớp 7B trồng được 4 cây,Mỗi học sinh lớp 7C trồng được 5 cây. Hỏi mỗi lớp có bao nhiêu học sinh. Biết rằng mỗi lớp trồng được số cây như nhau.
HELP ME PLEASE !!!
HELP ME PLEASE !!!
HELP ME PLEASE !!!
HELP ME PLEASE !!!
HELP ME PLEASE !!!
HELP ME PLEASE !!!
HELP ME PLEASE !!!
HELP ME PLEASE !!!
HELP ME PLEASE !!!
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ak nhầm
Các bạn giúp mình bài toán này với ah
đây là bài toán nâng cao
3/5 số học sinh giỏi của lớp 5A là 6 em. Hỏi lớp 5A có bao nhiêu học sinh giỏi?
các bạn giải giúp mình với!!!!!!!!!!!!!!!!!!
Please help me! Help me! Help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Gọi \(x\) là số học sinh giỏi lớp 5A. Theo đề bài ta có:
\(x\) x \(\dfrac{3}{5}\) = 6 ⇒ \(x\) = 6 x \(\dfrac{5}{3}\) = 10 (học sinh)
Vậy lớp 5A có 10 học sinh giỏi
Số học sinh lớp 5A là:
6 : \(\dfrac{3}{5}\)
= 10 ( em)
Đ/S: 10 em
Số học sinh giỏi của lớp 5A:
6:3/5=10(HS)
ĐS: 10HS
Viết thư gửi cho 1 người bạn của mình nói về dự định sắp tới mình làm
Can you help me???? Please!!!!
Hi Mia,
thanks for the letter, that is a great idea to do this summer.... But I got another idea....
This summer I will make a project about the Planets in the space!! I love space, in the future I want to be an austronaut!! I will use the telescope to look for them and watch their move around us! and more more exciting things to do for my project!
great, isn't it?
Sabrina
Các bạn ơi ! có thể tìm cho mình biết các câu ca dao có từ thân em ở đâu được không ạ
10 bạn trả lời đúng đầu tiên mình sẽ like cho bạn ấy.
please help me .
THAM KHẢO:
Những câu ca dao có từ thân emThân em như cánh hoa hồng. Lấy phải thằng chồng như đống cỏ khô.Thân em như thể cánh bèo. ...Thân em như cỏ ngoài đồng. ...Thân em như miếng cau khô ...Thân em như giếng giữa đàng. ...Thân em như tấm lụa đào. ...Thân em như quế giữa rừng. ...Thân em như chẽn lúa đòng đòng.
Thân em như thể cánh bèo
Ngược xuôi xuôi ngược theo chiều nước trôi.
Những câu ca dao có từ thân em
Thân em như cánh hoa hồng. Lấy phải thằng chồng như đống cỏ khô.
Thân em như thể cánh bèo.
...Thân em như cỏ ngoài đồng. ...
Thân em như miếng cau khô ...
Thân em như giếng giữa đàng. ...
Thân em như tấm lụa đào. ...
Thân em như quế giữa rừng. ...
Thân em như chẽn lúa đòng đòng.
help me please mai mình đi học rùi
\(\dfrac{2^8\cdot9^3}{6^4\cdot4^3}=\dfrac{2^8\cdot3^6}{2^4\cdot3^4\cdot2^6}=\dfrac{2^8\cdot3^6}{2^{10}\cdot3^4}=\dfrac{3^2}{2^2}=\dfrac{9}{4}\)
\(12^5\div\left(2^6\cdot3^8\right)=2^{10}\cdot3^5\div\left(2^6\cdot3^8\right)=\dfrac{2^{10}\cdot3^5}{2^6\cdot3^8}=\dfrac{2^4}{3^3}=\dfrac{16}{27}\)
\(\dfrac{3^{12}\cdot2^{14}\cdot5^5}{10^5\cdot6^8\cdot12^4}=\)\(\dfrac{3^{12}\cdot2^{14}\cdot5^5}{5^5\cdot2^5\cdot2^8\cdot3^8\cdot2^8\cdot3^4}=\)\(\dfrac{3^{12}\cdot2^{14}\cdot5^5}{5^5\cdot2^{21}\cdot3^{12}}=\dfrac{1}{2^7}=\dfrac{1}{128}\)
1) \(\dfrac{2^8\cdot9^3}{6^4\cdot4^3}=\dfrac{2^8\cdot3^6}{2^4\cdot2^6\cdot3^4}=\dfrac{3^2}{2^2}=\dfrac{9}{4}\)
2) \(12^5:\left(2^6\cdot3^8\right)=\dfrac{2^{10}\cdot3^5}{2^6\cdot3^8}=\dfrac{2^4}{3^3}=\dfrac{16}{27}\)
\(\dfrac{3^{12}\cdot2^{14}\cdot5^5}{10^5\cdot6^8\cdot12^4}=\dfrac{3^{12}\cdot2^{14}\cdot5^5}{5^5\cdot2^{21}\cdot3^{12}}=\dfrac{1}{128}\)
. Help Me ! Please :)) Mik đang gấp lắm nhé nên nếu các bạn biết thì giải giúp mik nhé :3 Cảm ơn nhiều nhiều lắm nek ~~~ Bạn nào làm đúng mik sẽ tik nhé =))
~ ĐỀ BÀI: Tìm x
x^3 + x^2 - 4x = 4
Ta có:
\(x^3+x^2-4x=4\)
\(\Rightarrow x^3+x^2-4x-4=0\)
\(\Rightarrow\left(x^3+x^2\right)-\left(4x+4\right)=0\)
\(\Rightarrow x^2\left(x+1\right)-4\left(x+1\right)=0\)
\(\Rightarrow\left(x^2-4\right)\left(x+1\right)=0\)
\(\Rightarrow\left(x-2\right)\left(x+2\right)\left(x+1\right)=0\)
\(\Rightarrow x-2=0;x+2=0;x+1=0\)
\(\Rightarrow x\in\left\{2;-2;-1\right\}\)
a)\(2.\left(x+5\right)-x^2-5x=0\)
\(\Leftrightarrow2\left(x+5\right)-x\left(x+5\right)=0\)
\(\Leftrightarrow\left(x+5\right).\left(2-x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x+5=0\\2-x=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-5\\x=2\end{cases}}\)
b)\(3x^3-48x=0\)
\(\Leftrightarrow3x\left(x^2-16\right)=0\)
\(\Leftrightarrow3x.\left(x-4\right).\left(x+4\right)=0\)
\(\Leftrightarrow\orbr{\frac{x=4}{\frac{x=0}{x=-4}}}\)
c)\(x^3+x^2-4x=4\)
\(\Leftrightarrow x^2\left(x+1\right)-4\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x^2-4\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x-2\right)\left(x+2\right)\)
\(\Leftrightarrow\orbr{\begin{cases}\frac{x=0}{x=2}\\\overline{x=-2}\end{cases}}\)
a)2.(x+5)-x^2-5x=0 \(\Leftrightarrow\) 2.(x+5)- (x^2+5x)=0 \(\Leftrightarrow\) 2.(x+5)-x.(x+5)=0 \(\Leftrightarrow\) (x+5).(2-x)=0 \(\Rightarrow\) x+5=0 hoặc 2-x=0 TH1:x+5=0\(\Leftrightarrow\) x=-5 Th2:2-x=0\(\Leftrightarrow\) x=2 vậy x=2 và x=-5 b)3x^3-48x=0 \(\Leftrightarrow\) 3x.(x^2-16)=0 \(\Leftrightarrow\)3x=0 hoặc x^2-16=0 \(\Leftrightarrow\) th1:3x=0\(\Leftrightarrow\) x=0 th2:x^2-16=0\(\Leftrightarrow\) x^2=16\(\Leftrightarrow\) x=16 và x=-16 vậy x=0 , x=16 và x=-16 c)x^3+x^2-4x=4\(\Leftrightarrow\) x^3+x^2-4x-4=0 \(\Leftrightarrow\)(x^3-4x)+(x^2-4)=0 \(\Leftrightarrow\) x.(x^2-4)+(x^2-4)=0\(\Leftrightarrow\) (x^2-4).(x+1) =0 \(\Rightarrow\) x^2-4=0 hoặc x+1=0 th1:x^2-4=0 th2 x+1=0 \(\Leftrightarrow\) x^2=4 \(\Leftrightarrow\) x=-1 \(\Leftrightarrow\) x=2 và x=-2 Vậy x=2 , x=-2 và x=-1