a: =9^8:9^3:9^2=9^3

b: =4x^2*4x*4*4x*16

=x^4*4^5

`a, 9^8 : 9^3 : 3^4`

`= 9^8 : 9^3 : 9^2`

`= 9^(8-3-2)= 9^3`.

`b, x . 4x . 16x . 64x`

`= x. 4x . 4^2x . 4^3x`

`= 4^6x^4`

\(9^8:3^2\)

\(=\left(3^2\right)^8:3^2\)

\(=3^{16}:3^2\)

\(=3^{16-2}\)

\(=3^{14}\)

\(9^8:3^2=2187^2\)

Mình ko chắc có đúng ko.Nếu đúng thì tk cho mình nhé.

Nghĩa Đoan

9⁸ : 3²

= ( 3² )⁸ . 3²

= 3¹⁶ : 3²

= 3^{16 - 2}

= 3¹⁴

9⁸ : 3² = ( 3²)⁸ : 3² = 3¹⁶ : 3² = 3¹⁴

Hk tốt

\(9^8:3^2=\left(3^2\right)^8:3^2=3^{16}:3^2=3^{14}\)

=.= hok tốt!!

ta có : 

\(9^8:3^2=3^{16}:3^2=3^{14}\)

chúc bạn học tốt

9^8:3^2=(3^2)^8:3^2=3^16:3^2=3^16-2=3^14

9^8:3^2=9^8:9=9^7 

9^8=43046721

3^2=9

k mk nha!

9⁸:3²

=9⁸:9

=9⁷

^{tk nha~~~~~~~~~~~~~~~~~}

thanks

9⁸ : 3² = 9⁸ : 9¹ = 9^8-1= 9⁷

~HT~

9⁸= 9.9.9.9.9.9.9.9= 43046721

3²= 3.3= 9

43046721 : 9 = 4782969

Bài 6: 

a: \(2^{27}=8^9\)

\(3^{18}=9^9\)

b: Vì \(8^9< 9^9\)

nên \(2^{27}< 3^{18}\)

\(9^8:3^2\)

\(=\left(3^2\right)^8:3^2\)

\(=3^{16}:3^2\)

\(=3^{14}\)

9^8:3^2

= (3^2)^8 : 3^2

= 3^16 : 3^2

=3^14

\(9^8:3^2=\left(3^2\right)^8:3^2=3^{16}:3^2=3^{\left(16-2\right)}\)

---Học tốt---