\(x+\dfrac{1}{2}=\dfrac{33}{4}\\ \Rightarrow x=\dfrac{33}{4}-\dfrac{1}{2}\\ \Rightarrow x=\dfrac{31}{4}\\ \dfrac{5}{6}-x=\dfrac{1}{3}\\ \Rightarrow x=\dfrac{5}{6}-\dfrac{1}{3}\\ \Rightarrow x=\dfrac{1}{2}\\ x+\dfrac{4}{5}=\dfrac{-2}{3}\\ \Rightarrow x=\dfrac{-2}{3}-\dfrac{4}{5}\\ \Rightarrow x=\dfrac{-22}{15}\)

a: =>5(x+2)=170

=>x+2=34

=>x=32

b: =>x+2=5 hoặc x+2=-5

=>x=-7 hoặc x=3

c: =>x-2=1 hoặc x-2=-1

=>x=1 hoặc x=3

Giúp em đi ạ:(

\(\frac{1}{2}.x+\frac{3}{5}.x=-\frac{33}{25}\)

\(\Leftrightarrow x.\left(\frac{1}{2}+\frac{3}{5}\right)=-\frac{33}{25}\)

\(\Leftrightarrow x.\frac{11}{10}=-\frac{33}{25}\)

\(\Leftrightarrow x=-\frac{33}{25}:\frac{11}{10}\)

\(\Leftrightarrow x=-\frac{6}{5}\)

Vậy \(x=\frac{6}{5}\)

\(\frac{1}{2}.x+\frac{3}{5}.x=-\frac{33}{25}\)

\(x.\left(\frac{1}{2}+\frac{3}{5}\right)=-\frac{33}{25}\)

\(x.\left(\frac{5}{10}+\frac{6}{10}\right)=-\frac{33}{25}\)

\(x.\frac{11}{10}=-\frac{33}{25}\)

         \(x=-\frac{33}{25}:\frac{11}{10}\)

              \(x=-\frac{33}{25}.\frac{10}{11}\)

            \(x=-\frac{6}{5}\)

Vậy \(x=-\frac{6}{5}\)

Chúc bạn học tốt !!!

\(\frac{1}{2}\).x+\(\frac{3}{5}\).x=\(\frac{33}{25}\)

x.\((\frac{1}{2}\)+\(\frac{3}{5})\)=\(\frac{33}{25}\)

x.\((\frac{5}{10}+\frac{6}{10})=\frac{33}{25}\)

\(x.\frac{11}{10}=\frac{33}{25}\)

\(x=\frac{33}{25}:\frac{11}{10}\)

x=\(\frac{6}{5}\)

3/2+5/4+9/8/+17/16+33/32-6+x-1/x+1=31/32-2/2015

=(1+1/2)+(1+1/4)+(1+1/8)+(1+1/16)+(1+1/32-6+x-1/x+1=31/32-2/2015

=(1/2+1/4+1/8+1/16+1/32)+(1+1+1+1+1)-6+x-1/x+1=31/32-2/2015

=31/32+5-6+x-1/x+1=31/32-2/2015

=5-6+x-1/x+1=31/32-2/2015-31/32

=-1+x-1/x+1=-2/2015

=x-1/x+1=-2/2015- -1

=x-1/x+1=2013/2015

=>x=2014

câu a 25-5.(x-13) bằng mấy bạn

b, 2³.(x-7)=3.2⁵

=>2³.(x-7)=96

=>8.(x-7)=96

=>x-7=96:8

=>x-7=12

=>x=12+7

=>x=19

c,33+3.|x-1| =7²-2019⁰

=>33+3.|x-1| =48

=>3.|x-1| =48-33

=>3.|x-1| =15

=>|x-1| =15:3

=>|x-1| =5

=>x-1= ± 5

=>x-1=5    =>x=5-1  =>x=4

    x-1= -5  =>x=-5-1  =>x=-6

1: =>x^2+4x+3-x^2-2x=7

=>2x=4

hay x=2

\(a.x\left(x-5\right)\left(x+5\right)-\left(x+2\right)\left(x^2-2x+4\right)=3\)

\(\Leftrightarrow x\left(x^2-5^2\right)-\left(x^3+2^3\right)=3\)

\(\Leftrightarrow x^3-25x-x^3-8=3\)

\(\Leftrightarrow x^3-x^3-25x=8+3\)

\(\Leftrightarrow x=\frac{11}{-25}\)

Vậy x có nghiệm là \(\frac{-11}{25}.\)

\(\)

a) \(\left(x+1\right)\left(x+3\right)-x\left(x+2\right)=7\)

\(\Leftrightarrow x^2+4x+3-x^2-2x=0\)

\(\Leftrightarrow2x+3=0\Leftrightarrow x=-\frac{3}{2}\)

\(2x\left(3x+5\right)-x\left(6x-1\right)=33\)

\(\Leftrightarrow6x^2+10x-6x^2+x=33\)

\(\Leftrightarrow11x=33\Leftrightarrow x=3\)

\(\left(3x^2-x+1\right)\left(x-1\right)+x^2\left(4-3x\right)=\frac{5}{2}\)

\(\Leftrightarrow3x^3-x^2+x-3x^2+x-1+4x^2-3x^3=\frac{5}{2}\)

\(\Leftrightarrow2x-1=\frac{5}{2}\)

\(\Leftrightarrow2x=\frac{7}{2}\)

\(\Leftrightarrow x=\frac{7}{4}\)