a, Tim cac so tu nhien x,y sao cho \(\left(2x+1\right)\times\left(y-5\right)=12\)
b, Tim so tu nhien n sao cho \(4n-5\) chia het cho \(2n-1\)
a , tim cac so tu nhien x y sao cho (2x + 1 ) (y - 5)= 12
b , tim so tu nhien tu nhien sao cho 4n - 5 chia het cho 2n - 1
tim x dua vao quan he uoc boi:
tim so tu nhien x sao cho x-1 la uoc cua 12
tim so tu nhien x sao cho 2x+1 la uoc cua 28
tim so tu nhien x sao cho x+15 la boi cua x+3
tim cac so nguyen x,y sao cho (x+1)(y-2)=3
tim so nguyen x sao cho(x+2).(y-1)=2
tim so nguyen to x vua la uoc cua 275 vua la uoc cua 180
tim so nguyen to x,y biet x+y=12 va UCLL (x:y)=5
tim so tu nhien x,y biet x+y=32 va UCLL (x:y)=8
tim so tu nhien x biet x chia het cho10; xchia het cho12; x chia het cho15 va 100<x<150
tim so x nho nhat khac 0b biet x chia het cho 24 va 30
40 chia het cho x . 56 chia het cho x va x>6
Tim so tu nhien n sao cho :
4n-5 chia het cho 2n-1
tim so tu nhien sao cho 4n-5 chia het cho 2n-1
tim so tu nhien sao cho 4n -5 chia het cho 2n-1
ta co 4n-5:2n-1
=>4n-2-3:2n-1
=>2(2n-1)-3:2n-1
=>3:2n-1 (vi 2(2n-2):2n-1)
=>2n-1 thuoc Ư(3)= 1 ,-1,3.-3
CÓ 2n-1=1 =>2n=2=>n=1 (tm)
2n-1=-1=>2n=0=>n=0(tm)
2n-1=3=>2n=4=>n=2(tm)
2n-1=-3=>2n=-2=>n=-1(loại)
vây x thuoc ( 1;0;2)
kich nhe
tim so tu nhien sao cho 4n-5 chia het cho 2n-1
4n-5 chia hết cho 2n-1
=>2(2n-1)-3 chia hết cho 2n-1
mà 2(2n-1) chia hết cho 2n-1
=>3 chia hết cho 2n-1
=>2n-1 E Ư(3)={-3;-1;1;3}
=>2n E {-2;0;2;4}
=>n E {-1;0;1;2}
mà n E N
=>n E {0;1;2}
BAI 1 : TIM TAT CA CAC SO TU NHIEN x , y SAO CHO : ( 2x + 1 ) . ( y - 5 ) = 12
BAI 2: a ) TIM SO NGUYEN x VA y, BIET : xy - x + 2y = 3
b) CO SO TU NHIEN NAO MA CHIA CHO 18 DU 12 , CON CHIA CHO 6 THI DU 2 KHONG ?
Tim so tu nhien n sao cho:
a) 4n-5 chia het cho 2n-1
b) 6n+9 chia het cho 3n+1
\(4n-5⋮2n-1\)
\(\Leftrightarrow4n-2-3⋮2n-1\)
\(\Leftrightarrow2\left(2n-1\right)-3⋮2n-1\)
\(\Leftrightarrow-3⋮2n-1\)
\(\Leftrightarrow2n-1\in\text{Ư}\left(-3\right)=\left\{-3;-1;1;3\right\}\)
\(\Leftrightarrow2n\in\left\{-2;0;2;4\right\}\)
\(\Leftrightarrow n\in\left\{-1;0;1;2\right\}\)
mà \(n\in N\)
\(\Rightarrow n\in\left\{0;1;2\right\}\)
\(6n+9⋮3n+1\)
\(\Leftrightarrow6n+2+7⋮3n+1\)
\(\Leftrightarrow2\left(3n+1\right)+7⋮3n+1\)
\(\Leftrightarrow7⋮3n+1\)
\(\Leftrightarrow3n+1\in\text{Ư}\left(7\right)=\left\{-7;-1;1;7\right\}\)
\(\Leftrightarrow3n\in\left\{-8;-2;0;6\right\}\)
\(\Leftrightarrow n\in\left\{-\frac{8}{3};-\frac{2}{3};0;2\right\}\)
mà \(n\in N\)
=> \(n\in\left\{0;2\right\}\)
Tim so tu nhien n sao cho 4n+3 chia het cho 2n+1
Ta có: \(\frac{4n+3}{2n+1}=\frac{4n+2+1}{2n+1}=2+\frac{1}{2n+1}\)
Để \(\left(4n+3\right)⋮\left(2n+1\right)\)thì \(1⋮\left(2n+1\right)\)
Hay:\(2n+1\inƯ\left(1\right)\)
\(\Leftrightarrow2n+1\in\left(\pm1\right)\)
\(\Leftrightarrow2n\in\left(-2;0\right)\)
\(\Leftrightarrow n\in\left(-1;0\right)\)
Vì n là số tự nhiên \(\left(n\in N\right)\)nên giá trị của n cần tìm là: \(n=0\)