x+9x+7x+5x=2244
Những câu hỏi liên quan
x + 9x + 7x + 5x = 2244
x + 9x + 7x + 5x = 2244
1x + 9x + 7x + 5x = 2244
x(1+9+7+5) = 2244
x.22 = 2244
=> x = 102
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Tìm x, biết:
x+ 9x + 7x + 5x= 2244
x + 9x + 7x + 5x = 2244
<=> 1x + 9x + 7x + 5x = 2244
x ( 1 + 9 + 7 + 5 ) = 2244
22x = 2244
x = 2244 : 22
x = 1122
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x + 9x + 7x + 5x = 2244
<=> 22x = 2244
<=> x = 2244 : 22
=> x = 102
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Xem thêm câu trả lời
Các bạn giải giúp mình:
5^2x-3-2x5^2=5^2x3 (^ là mũ)
x+9x+7x+5x=2244
a. (2x⁵-5x³+x²+3x-1):(x²-1) b. (5x⁵-2x⁴-9x³+7x²-18x-3):(x²-3)
a: \(=\dfrac{2x^5-2x^3-3x^3+3x+x^2-1}{x^2-1}\)
\(=2x^3-3x+1\)
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Tìm x:
x + 9x + 7x + 5x =8844
1*x+9*x+7*x+5*x =8844
(1+9+7+5)*x=8844
22*x=8844
x=8844/22
x=402
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Ta có :
\(x+9x+7x+5x=22x=8844\Rightarrow x=402\)
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Phân tích thành nhân tử( dùng pp tách hạng tử) A)x²+5x+6; B)x²+6x+8; C)x²-5x-14; D)x²-9x+18; E)x²-7x+12; F)3x²+9x-30.giúp mk vs.Tks
a) x2 + 5x + 6
= x2 + 2x + 3x + 6
= (x2 + 2x) + (3x + 6)
= x(x + 2) + 3 (x + 2)
= (x + 2) (x + 3)
b) x2 + 6x + 8
= x2 + 2x + 4x + 8
= (x2 + 2x) + (4x + 8)
= x(x + 2) + 4(x + 2)
= (x + 2)(x + 4)
c) x2 - 5x - 14
= x2 + 2x - 7x - 14
= (x2 + 2x) - (7x + 14)
= x(x + 2) - 7(x + 2)
= (x + 2)(x - 7)
d) x2 - 9x + 18
= x2 - 3x - 6x + 18
= (x2 - 3x) - (6x + 18)
= x(x - 3) - 6 (x - 3)
= (x - 3)(x - 6)
e) x2 - 7x + 12
= x2 -3x - 4x + 12
= (x2 - 3x) - (4x + 12)
= x(x - 3) - 4(x - 3)
= (x - 3)(x - 4)
f) 3x2 + 9x - 30
= 3(x2 + 3x - 10)
= 3\(\left[\left(x^2+5x-2x-10\right)\right]\)
= 3\(\left[\left(x^2+5x\right)-\left(2x-10\right)\right]\)
= 3\(\left[x\left(x+5\right)-2\left(x+5\right)\right]\)
= 3(x + 5)(x - 2)
Chuc ban hoc tot
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a) \(x^2+5x+6=\left(x+2\right)\left(x+3\right)\)
b) \(x^2+6x+8=\left(x+2\right)\left(x+4\right)\)
c) \(x^2-5x-14=\left(x-7\right)\left(x+2\right)\)
d) \(x^2-9x+18=\left(x-3\right)\left(x-6\right)\)
e) \(x^2-7x+12=\left(x-3\right)\left(x-4\right)\)
f) \(3x^2+9x-30=3\left(x^2+3x-10\right)=3\left(x+5\right)\left(x-2\right)\)
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x^2-5x+6
x^2-7x+12
x^2+x-12
x^2-9x+20
2x^2-3x-2
4x^2-7x-2
4x^2+15x+9
\(x^2-5x+6=\left(x-2\right)\left(x-3\right)\)
\(x^2-7x+12=\left(x-2\right)\left(x-5\right)\)
\(x^2+x-12=\left(x-5\right)\left(x+6\right)\)
\(x^2-9x+20=\left(x-4\right)\left(x-5\right)\)
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\(2x^2-3x+2=2\left(x+\dfrac{1}{2}\right)\left(x-2\right)\)
\(4x^2-7x-2=4\left(x-2\right)\left(x+\dfrac{1}{4}\right)\)
\(4x^2+15x+9=4\left(x+\dfrac{3}{4}\right)\left(x+3\right)\)
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Tính: a,x²-5x+6/ x²+7x+12 : x²-4x+4/ x²+3x b,x²+2x-3/ x²+3x-10 : x²+7x+12/ x²-9x+14
a: \(\dfrac{x^2-5x+6}{x^2+7x+12}:\dfrac{x^2-4x+4}{x^2+3x}\)
\(=\dfrac{\left(x-2\right)\left(x-3\right)}{\left(x+3\right)\left(x+4\right)}\cdot\dfrac{x\left(x+3\right)}{\left(x-2\right)^2}\)
\(=\dfrac{x\left(x-3\right)}{\left(x-2\right)\left(x+4\right)}\)
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b: \(\dfrac{x^2+2x-3}{x^2+3x-10}:\dfrac{x^2+7x+12}{x^2-9x+14}\)
\(=\dfrac{\left(x+3\right)\left(x-1\right)}{\left(x+5\right)\left(x-2\right)}\cdot\dfrac{\left(x-2\right)\left(x-7\right)}{\left(x+3\right)\left(x+4\right)}\)
\(=\dfrac{\left(x-1\right)\left(x-7\right)}{\left(x+5\right)\left(x+4\right)}\)
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20 tháng 5 2022 lúc 19:48
Bài 4: Cho hai đa thức:
P(x)= \(x^5-2x^2+7x^4-9x^3-x+2x^2-5x^4\)
Q(x)= \(5x^4-x^5+4x^2-6+9x^3-8+x^5\)
Tính M(\(\dfrac{1}{2}\))
