đây là lớp mấy?

\(\dfrac{3x-2y}{4}=\dfrac{4y-3z}{2}=\dfrac{2z-4x}{3}=\dfrac{12x-8y}{16}=\dfrac{6z-12x}{9}=\dfrac{8y-6z}{4}=\dfrac{12x-8y+6z-12x+8y-6z}{16+9+4}=\dfrac{0}{29}=0\\ \Leftrightarrow\left\{{}\begin{matrix}3x-2y=0\\2z-4x=0\\4y-3z=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\dfrac{x}{2}=\dfrac{y}{3}\\\dfrac{y}{3}=\dfrac{z}{4}\\\dfrac{z}{4}=\dfrac{x}{2}\end{matrix}\right.\\ \Leftrightarrow\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}=\dfrac{x-2y+3z}{2-6+12}=\dfrac{8}{8}=1\\ \Leftrightarrow\left\{{}\begin{matrix}x=2\\y=3\\z=4\end{matrix}\right.\)

vào chtt tick nha bạn hiền

Tham khảo nhá

(3x-2y)/4 = (2z-4x)/3 = (4y-3z)/2 =

= (12x-8y)/16 = (6z-12x)/9 = (8y-6z)/4 = (12x-8y + 6z-12x + 8y-6z)/(16+9+4) = 0
<=>
{12x - 8y = 0
{6z - 12x = 0
{8y - 6z = 0
<=>
{x/2 = y/3
{z/4 = x/2
{y/3 = z/4

<=> x/2 = y/3 = z/4

Học tốt!

Vì \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)

\(\Rightarrow\frac{4\left(3x-2y\right)}{16}=\frac{3\left(2z-4x\right)}{9}=\frac{2\left(4y-3z\right)}{4}\)

\(\Rightarrow\frac{12x-8y}{16}=\frac{6z-12x}{9}=\frac{8y-6z}{4}\)

Áp dụng tính chất của dãy tỉ số bằng nhau:

\(\Rightarrow\frac{12x-8y}{16}=\frac{6z-12x}{9}=\frac{8y-6z}{4}\)

\(=\frac{12x-8y+6z-12x+8y-6z}{16+9+4}\)

\(=\frac{\left(12x-12x\right)+\left(8y-8y\right)+\left(6z-6z\right)}{16+9+4}\)

\(=\frac{0}{16+9+4}=0\)

\(\Leftrightarrow\left\{{}\begin{matrix}3x-2y=0\\2z-4x=0\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}3x=2y\\2z=4x\end{matrix}\right.\)\(\Leftrightarrow\left\{{}\begin{matrix}\frac{x}{2}=\frac{y}{3}\\\frac{x}{2}=\frac{z}{4}\end{matrix}\right.\)

\(\Leftrightarrow\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\left(đpcm\right)\)