A) \(\frac{252}{X}\) = \(\frac{84}{97}\) B) \(\frac{x}{17}\) + \(\frac{19}{34}\) = \(\frac{1}{2}\)
Những câu hỏi liên quan
a frac{252}{x}frac{84}{97}b frac{4}{5}-frac{7}{5}:xfrac{1}{6}c frac{50}{19}cdotfrac{38}{25} x frac{69}{17}+frac{33}{17}
Đọc tiếp
a \(\frac{252}{x}\)\(=\)\(\frac{84}{97}\)
b \(\frac{4}{5}\)\(-\)\(\frac{7}{5}\)\(:\)\(x\)\(=\)\(\frac{1}{6}\)
c \(\frac{50}{19}\)\(\cdot\)\(\frac{38}{25}\)\(< \)\(x\)\(< \)\(\frac{69}{17}\)\(+\)\(\frac{33}{17}\)
a. Vì 252/x=84/97 nên => 252.97=84.x hay 84.x =24444 => x= 24444: 84= 291
b 7/5 :x = 4/5-1/6
7/5 :x =19/30
x=7/5:19/30
x=42/19
c Tự làm đi dễ mà
tính ra rồi tìm
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tim x biet
\(\frac{252}{x}\)= \(\frac{84}{97}\)
Ta có :
252/x = 84/97
=> x = 252/84/97
=> x = 291
Vậy nhé, nhớ k cho mk đó
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tim x biet:
\(\frac{252}{x}\) = \(\frac{84}{97}\)
\(\frac{9}{24}\)= \(\frac{x}{56}\)
x.84=252.97
x=24444:84
x=291
x.24=9.56
x=504:24
x=21
k nha
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Xem thêm câu trả lời
Giải phương trình sau:
1) \(\frac{x+14}{86}+\frac{x+15}{85}+\frac{x+6}{84}+\frac{x+17}{83}+\frac{x+116}{4}=0\)
2) \(\frac{x-241}{17}+\frac{x-220}{19}+\frac{x-195}{21}+\frac{x-166}{23}=0\)
3) \(\frac{x+2}{13}+\frac{2x-45}{15}=\frac{3x+8}{37}+\frac{4x+69}{9}\)
\(\Leftrightarrow\left(\frac{x+14}{86}+1\right)+\left(\frac{x+15}{85}+1\right)+\left(\frac{x+16}{84}+1\right)+\left(\frac{x+17}{83}+1\right)+\left(\frac{166}{4}-4\right)=0\)
\(\Leftrightarrow\frac{x+100}{86}+\frac{x+100}{85}+\frac{x+100}{84}+\frac{x+100}{83}+\frac{x+100}{4}=0\)
\(\Leftrightarrow\left(x+100\right).\left(\frac{1}{86}+\frac{1}{85}+\frac{1}{84}+\frac{1}{83}+\frac{1}{4}\right)=0\)
\(\Leftrightarrow\left(x+100\right)=0\Rightarrow x=-100\left(\text{vì }\frac{1}{86}+\frac{1}{85}+\frac{1}{84}+\frac{1}{83}+\frac{1}{4}\right)\ne0\)
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Tính
A) \(\frac{15}{34}+\frac{7}{21}+\frac{19}{34}-1\frac{15}{17}+\frac{2}{3}\)
B) \(\left(-2\right)^3\times\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
Tìm x
A) \(4\frac{1}{3}:\frac{\chi}{4}=6:0,3\)
B) \(\left(2^3:4\right)\times2^{\left(\chi+1\right)}=64\)
Tính:
b) \(\left(-2\right)^3.\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
\(=\left(-2\right)^3.\left(\frac{3}{4}-\frac{1}{4}\right):\left(\frac{9}{4}-\frac{7}{6}\right)\)
\(=\left(-8\right).\frac{1}{2}:\frac{13}{12}\)
\(=\left(-4\right):\frac{13}{12}\)
\(=-\frac{48}{13}.\)
Tìm x
a) \(4\frac{1}{3}:\frac{x}{4}=6:0,3\)
⇒ \(\frac{13}{3}:\frac{x}{4}=20\)
⇒ \(\frac{x}{4}=\frac{13}{3}:20\)
⇒ \(\frac{x}{4}=\frac{13}{60}\)
⇒ \(x.60=4.13\)
⇒ \(x.60=52\)
⇒ \(x=52:60\)
⇒ \(x=\frac{13}{15}\)
Vậy \(x=\frac{13}{15}.\)
b) \(\left(2^3:4\right).2^{x+1}=64\)
⇒ \(\left(8:4\right).2^{x+1}=64\)
⇒ \(2.2^{x+1}=64\)
⇒ \(2^{x+1}=64:2\)
⇒ \(2^{x+1}=32\)
⇒ \(2^{x+1}=2^5\)
⇒ \(x+1=5\)
⇒ \(x=5-1\)
⇒ \(x=4\)
Vậy \(x=4.\)
Chúc bạn học tốt!
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Giải phương trình:
a)\(\frac{x+81}{19}+\frac{x+82}{18}=\frac{x+84}{16}+\frac{x+85}{15}\)
b)\(\frac{x-22}{8}+\frac{x-21}{9}+\frac{x-20}{10}+\frac{x-19}{11}=4\)
c)\(\frac{x+19}{3}+\frac{x+13}{5}=\frac{x+7}{7}+\frac{x+1}{9}\)
d)\(\frac{2-x}{2018}-1=\frac{1-x}{2019}-\frac{x}{2020}\)
https://i.imgur.com/s9QrL5D.jpg
https://i.imgur.com/7p0hoi8.jpg
tính A=\(8\frac{3}{19}.5\frac{1}{4}+3\frac{16}{19}.5\frac{1}{4}\)phần \(\left[2\frac{14}{17}-2\frac{1}{34}\right]-34\)
\(\frac{\left(1+17\right)\left(1+\frac{17}{2}\right)\left(1+\frac{17}{3}\right).....\left(1+\frac{17}{19}\right)}{\left(1+19\right)\left(1+\frac{19}{2}\right)\left(1+\frac{19}{3}\right).....\left(1+\frac{19}{17}\right)}\)
\(A=\frac{5-\left(\frac{2}{3}\right)-x}{ }\)
B=/3x+1/-2
C= 7/4x-3/
Tính \(A=\frac{8\frac{3}{9}.5\frac{1}{4}+3\frac{16}{19}.5\frac{1}{4}}{\left(2\frac{14}{17}-2\frac{1}{34}\right)34};\frac{7}{24}\)