\(\frac{72^2}{24^2}=\frac{3^2.24^2}{24^2}=3^2=9\)

\(\frac{\left(-7,5\right)^2}{2,5^2}=\frac{\left(7,5\right)^2}{\left(2,5\right)^2}=\frac{\left(2,5\right)^2.3^2}{\left(2,5\right)^2}=9\)

\(\frac{15^2}{27}=\frac{3^2.5^2}{27}=\frac{9.25}{27}=\frac{25}{3}\)

\(\frac{72^2}{24^2}=\left(\frac{72}{24}\right)^2=3^2=9\)

\(\frac{\left(-7,5\right)^3}{\left(2,5\right)^3}=\left(\frac{-7,5}{2,5}\right)^3=\left(-3\right)^3=-27\)

\(\frac{15^3}{27}=\frac{15^3}{3^3}=\left(\frac{15}{3}\right)^3=5^3=125\)

Chúc bạn hok tốt 

Silver bullet bn bị sai đề kìa \(\frac{\left(-7,5\right)^3}{\left(2,5\right)^3}\) chứ ko phải \(\frac{\left(-7,5\right)^2}{\left(2,5\right)^2}\)

\(\frac{72^2}{24^2}=\frac{72}{24}=3\)

\(\frac{\left(-7,5\right)^3}{\left(2,5\right)^3}=\frac{-7,5}{2,5}=-3\)

\(\frac{15^3}{27}=\frac{\left(3.5\right)^3}{\left(3.9\right)}=\frac{3^3.5^3}{3.9}=\frac{3^2.5^3}{9}=\frac{9.5^3}{9}=5^3=125\)

a)

\(7,5.\left(\frac{-2}{5}\right).\left(-2,5\right)\)

\(=7,5.\left[\left(\frac{-2}{5}\right).\left(-2,5\right)\right]\)

\(=7,5.1\)

\(=7,5\)

b) 

\(\left(-50,5\right).8.\left(-0,25\right)\)

\(=\left(-50,5\right).\left[8.\left(-0,25\right)\right]\)

\(=\left(-50,5\right).\left(-2\right)\)

\(=101\)

c)

\(\left(0,125\right).\left(-3,7\right).\left(-2\right)^3\)

\(=\left(0,125\right).\left(-3,7\right).\left(-8\right)\)

\(=\left[\left(-8\right).\left(0,125\right)\right].\left(-3,7\right)\)

\(=\left(-1\right).\left(-3,7\right)\)

\(=3,7\)

Chúc cậu học tốt !!!

72²/24 = 216

(-7,5)³/(2,5)³ = 27

15³/27 = 125

\(A=\left|4x-3\right|+\left|5y+7,5\right|+10\)

Mà \(\left|4x-3\right|\ge0\)với mọi x

\(\left|5y+7,5\right|\ge0\)với mọi y

\(\Rightarrow A\)có GTNN là 10

Để A có GTNN thì :

\(4x-3=0\)                           \(5y+7,5=0\)

\(4x=3\)                                                  \(5y=-7,5\)

\(x=\frac{3}{4}\)                                                     \(y=-1,5\)

\(B=\frac{5,8}{\left|2,5-x\right|+5,8}\)

Mà \(\left|2,5-x\right|\ge0\)

\(\Rightarrow\)GTNN \(\left|2,5-x\right|+5,8=5,8\)

Để B có GTLN \(\Rightarrow2,5-x=0\)

\(\Rightarrow x=2,5\)

a) (4,1 - 2,5 ) - ( -2,5 + 3,1 ) = 1,6 - 0,6 = 1

b) ( 5,3 - 2,8) - ( 4+ 5,3) = 2,5 - 9,3 = -6.8

c) -( 251,3 + 281) + 3,251 - (1 - 981) = -532,3 + 3,251 + 980 = 450,951

d) -(3/5 + 3/4) - ( -3/4 +2/5) = -3/5 - 3/4 + 3/4 - 2/5 = -1

a) \(\left(\frac{11}{12}:\frac{44}{16}\right).\left(\frac{-1}{3}+\frac{1}{2}\right)\) \(=\left(\frac{11}{12}.\frac{16}{44}\right).\left(\frac{-2}{6}+\frac{3}{6}\right)\) \(=\frac{1}{3}.\frac{1}{6}\) \(=\frac{1}{18}\)

b) \(\frac{\left(-5\right)^2.\left(-5\right)^3.16}{5^4.\left(-2\right)^4}\) \(=\frac{\left(-5\right)^5.2^4}{5^4.\left(-2\right)^4}\) \(=5\) ^{_{(Có sửa đề lại, nếu có sai thì ib mình sửa lại nhé!)}}

c) \(7,5:\left(\frac{-5}{3}\right)+2\frac{1}{2}:\left(\frac{-5}{3}\right)\) \(=\frac{15}{2}.\left(\frac{-3}{5}\right)+\frac{5}{2}.\left(\frac{-3}{5}\right)\) \(=\frac{-3}{5}.\left(\frac{15}{2}+\frac{5}{2}\right)\)

\(=\frac{-3}{5}.10\) \(=-6\)

d) \(\left(\frac{-1}{2}+\frac{1}{3}\right).\frac{4}{5}+\left(\frac{2}{3}+\frac{1}{2}\right):\frac{5}{4}\) \(=\left(\frac{-1}{2}+\frac{1}{3}\right).\frac{4}{5}+\left(\frac{2}{3}+\frac{1}{2}\right).\frac{4}{5}\)

\(=\frac{4}{5}.\left(\frac{-1}{2}+\frac{1}{3}+\frac{2}{3}+\frac{1}{2}\right)\) \(=\frac{4}{5}.\left(\frac{0}{2}+1\right)\) \(=\frac{4}{5}.1=\frac{4}{5}\)

a)    

b)   

c)   

d)  

\(\left|2x\right|-\left|-2,5\right|=\left|-7,5\right|\forall x>0\)

\(\Rightarrow2x-2,5=7,5\)

\(\Rightarrow2x=10\)

\(\Rightarrow x=5\)

\(|2x|-|-2,5|=|-7,5|\)

\(\Rightarrow|2x|-2=7,5\)

\(\Rightarrow|2x|=10\)

\(\Rightarrow\orbr{\begin{cases}2x=10\\2x=-10\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-5\end{cases}}}\)

\(KL:x\in\left\{\pm5\right\}\)

\(\left|2x\right|-\left|-2,5\right|=\left|-7,5\right|\)

\(\Rightarrow\left|2x\right|-2,5=7,5\)

\(\Rightarrow2x=10\)

\(\Rightarrow x=5\)