B.
A.
D

1 d

2

3d

câu 2 bạn nên coi lại nha

đề sai hay sao í

a)Ta có:

 \(2^{94}\)

\(1024^9=\left(2^5\right)^9=2^{45}\)

\(2^{45}< 2^{94}\)

⇒\(2^{94}>1024^9\)

b) Ta có:

\(6^2+8^2=36+64=100\)

\(\left(6+8\right)^2=14^2=196\)

196>100

⇒\(6^2+8^2< \left(6+8\right)^2\)

\(2^6;8^2=2^6;2^6\Leftrightarrow2^6=8^2\)

\(2^6=\left(2^3\right)^2=8^2\)

\(\left(\sqrt{2}+\sqrt{3}\right)^2=5+2\sqrt{6}>2^2=4\left(5>4\right)\\ \Leftrightarrow\sqrt{2}+\sqrt{3}>2\)

\(\left(\sqrt{8}+\sqrt{5}\right)^2=13+2\sqrt{40};\left(\sqrt{7}-\sqrt{6}\right)^2=13-2\sqrt{42}\\ 2\sqrt{40}>0>-2\sqrt{42}\\ \Leftrightarrow13+2\sqrt{40}>13-2\sqrt{42}\\ \Leftrightarrow\left(\sqrt{8}+\sqrt{5}\right)^2>\left(\sqrt{7}-\sqrt{6}\right)^2\\ \Leftrightarrow\sqrt{8}+\sqrt{5}>\sqrt{7}-\sqrt{6}\)

\(\sqrt{2}\) + \(\sqrt{3}\)  > 2

8^5<6^6

32.....<46.......

Câu 1:

\(8^6=\left(2^3\right)^6=2^{18}=2.2^{17}\)

\(6.4^8=2.3.\left(2^2\right)^8=3.2^{17}\)

\(2.2^{17}8^{19}\) => \(27.9^{19}>4.8^{19}\Rightarrow3^{41}>2^{59}\)