2134/2135 > 1439/1440

>

Có :

`2134/2135=1-1/2135`

`1439/1440=1-1/1440`

Vì `1/1440>1/2135`

`->1-1/1440<1-1/2135`

`->1439/1440<2134/2135`

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Ai trả lời nhanh nhất tui k cho

Ta có:\(\frac{97}{198}< \frac{97}{197}< \frac{98}{197}\)

Ta có : \(\frac{97}{198}\) và \(\frac{98}{197}\)

Chọn phân số trung gian là :\(\frac{97}{197}\)

Vì \(\frac{97}{198}< \frac{97}{197};\frac{97}{197}< \frac{98}{197}\)

Nên \(\frac{97}{198}< \frac{98}{197}\)

97/198+1                  98/197+1

295/198                    295/197

=> 97/197 > 98/197

\(\dfrac{19}{19}\) = 1 < \(\dfrac{2005}{2004}\) vậy \(\dfrac{19}{19}\) < \(\dfrac{2005}{2004}\)

\(\dfrac{72}{73}\) = 1 - \(\dfrac{1}{73}\) 

\(\dfrac{98}{99}\) = 1 - \(\dfrac{1}{99}\)

Vì \(\dfrac{1}{73}\) > \(\dfrac{1}{99}\) nên \(\dfrac{72}{73}\) < \(\dfrac{98}{99}\) 

1) 19/19 < 2005/2004

2)72/73 > 98/99

\(\dfrac{72}{-73}=-0,98\)

\(\dfrac{98}{-99}=-0,98\)

\(\Rightarrow\dfrac{72}{-73}=\dfrac{98}{-99}\)

\(\dfrac{72}{-73}=\dfrac{-72}{73}=1-\dfrac{1}{73}\)

\(\dfrac{98}{-99}=\dfrac{-98}{99}=1-\dfrac{1}{99}\)

mà \(-\dfrac{1}{73}< -\dfrac{1}{99}\)

nên \(\dfrac{72}{-73}>\dfrac{98}{-99}\)

\(\frac{10^8+2}{10^8-1}=\frac{10^8-1+3}{10^8-1}=1+\frac{3}{10^8-1}\)

\(\frac{10^8}{10^8-3}=\frac{10^8-3+3}{10^8-3}=1+\frac{3}{10^8-3}\)

Ta có: \(\frac{3}{10^8-1}< \frac{3}{10^8-3}\)

\(\Rightarrow1+\frac{3}{10^8-1}< 1+\frac{3}{10^8-3}\)

\(\Rightarrow\frac{10^8+2}{10^8-1}< \frac{10^8}{10^8-3}\)

Ta có:\(\frac{196}{197}+\frac{197}{198}=\left(1-\frac{1}{197}\right)+\left(1-\frac{1}{198}\right)=2-\frac{1}{197}-\frac{1}{198}>2-1=1\)

Mà \(\frac{196+197}{197+198}< \frac{197+198}{197+198}=1\)

\(\Rightarrow\frac{196}{197}+\frac{197}{198}>\frac{196+197}{197+198}\)

c) tương tự câu a

Tham khảo nhé~