\(\frac{21}{25}=\frac{49329}{58725}\)

\(\frac{60}{81}=\frac{43500}{58725}\)

\(\frac{19}{29}=\frac{38475}{58725}\)

\(\)vì \(\frac{49329}{58725}>\frac{43500}{58725}>\frac{38475}{58725}\)nên\(\frac{21}{25}>\frac{60}{81}>\frac{19}{29}\)

\(\frac{21}{25};\frac{60}{81};\frac{19}{29}\)

Ta có : \(\frac{60}{81}=\frac{60:3}{81:3}=\frac{20}{27}\); giữ nguyên \(\frac{21}{25};\frac{19}{29}\).

Vì \(\frac{21}{25}>\frac{20}{25}>\frac{20}{27}\)nên \(\frac{21}{25}>\frac{20}{27}\)

Vì  \(\frac{20}{27}>\frac{20}{29}>\frac{19}{29}\)nên \(\frac{20}{27}>\frac{19}{29}\). Vậy :

\(\frac{21}{25}>\frac{20}{27}>\frac{19}{29}\)hay  \(\frac{21}{25}>\frac{60}{81}>\frac{19}{29}\)

ta có: \(1-\frac{17}{20}=\frac{3}{20};1-\frac{22}{25}=\frac{3}{25}\)

\(\Rightarrow\frac{3}{20}>\frac{3}{25}\Rightarrow1-\frac{17}{20}>1-\frac{22}{25}\)

\(\Rightarrow\frac{17}{20}< \frac{22}{25}\)

25/29 và 21/33

25/29=25X33/29x33=825/957

21/33=21x29/33x29=609/957

825/957>609/957

nên 25/29>21/33

các bạn giúp mình nha

​

ko biết

Ta có 23/45>8/25

Nên 23/45>8/19

Ta có 123/25<233/25

Nên 123/25<233/237

a)

\(\frac{64}{85}< \frac{64}{81}< \frac{73}{81}\)

=>\(\frac{64}{85}< \frac{73}{81}\)

b)

\(\frac{25}{26}=\frac{25.1010}{26.1010}=\frac{25250}{26260}\)

Ta có: \(1-\frac{25250}{26260}=\frac{1010}{26260}\)

         \(1-\frac{25251}{26261}=\frac{1010}{26261}\)

Vì \(\frac{1010}{26260}>\frac{1010}{26261}\) nên \(\frac{25}{26}< \frac{25251}{26261}\)

a)\(\frac{64}{85}\)<\(\frac{64}{81}\)<\(\frac{73}{81}\)

b)\(\frac{25}{26}\)=\(\frac{25250}{26260}\)=\(1\)- \(\frac{1010}{26260}\)< \(1\)- \(\frac{1010}{26261}\)= \(\frac{25251}{26261}\)

A.4/25 < 25/4

B. 2/9 và  < 9/2

A.4/25 < 25/4

 B. 2/9  <9/2

Ta thấy : \(1-\frac{12}{13}=\frac{1}{13}\)

\(1-\frac{13}{14}=\frac{1}{14}\)

Mà \(\frac{1}{13}>\frac{1}{14}\) nên \(\Rightarrow\frac{12}{13}< \frac{13}{14}\)

câu này nhiều lắm nên ko muốn trả lời

A.4/3 > 95/96

B.25/68 > 20/99

C. 9/50 <11/42

> 

> 

 <

A.4/3 > 95/96

B.25/68 >20/99

C. 9/50  <11/42