\(\left(x-2013\right)^{2014}=1\)

\(\Rightarrow\orbr{\begin{cases}x-2013=1\\x-2013=-1\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=2013+1\\x=-1+2013\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=2014\\x=2012\end{cases}}\)

Vậy x=2014 hoặc x=2012

hok tốt

(x - 2013)²⁰¹⁴ = 1

=> x - 2013 = 1 hoặc -1

TH1: x - 2013 = 1

         x            = 1 + 2013

         x            = 2014

TH2: x - 2013 = -1

         x            = -1 + 2013

         x            = 2012

Vậy x = 2014 hoặc 2012

Học tốt nhé ! ^^

#Lạnh

( x - 2013 ) ²⁰¹⁴ = 1......................

=> x - 2013 = 1.........................

=> x = 1 + 2013........................

=> x = 2014.......................

\(\left(x+\dfrac{1}{3}\right)\times\dfrac{9}{14}\times\dfrac{7}{3}-\dfrac{1}{3}=1:\dfrac{9}{5}\\ \Rightarrow\left(x+\dfrac{1}{3}\right)\times\dfrac{3}{2}-\dfrac{1}{3}=\dfrac{5}{9}\\ \Rightarrow\left(x+\dfrac{1}{3}\right)\times\dfrac{3}{2}=\dfrac{5}{9}+\dfrac{1}{3}\\ \Rightarrow\left(x+\dfrac{1}{3}\right)\times\dfrac{3}{2}=\dfrac{8}{9}\\ \Rightarrow x+\dfrac{1}{3}=\dfrac{8}{9}:\dfrac{3}{2}\\ \Rightarrow x+\dfrac{1}{3}=\dfrac{16}{27}\\ \Rightarrow x=\dfrac{16}{27}-\dfrac{1}{3}\\ \Rightarrow x=\dfrac{7}{27}\)

1.

a) \(2^x=128\)

\(2^x=2^7\)

\(=>x=7\)

b) \(8^{x-1}=64\)

\(8^{x-1}=8^2\)

\(=>x-1=2\)

\(x=2+1\)

\(=>x=3\)

c) \(3+3^x=30\)

\(3^x=30-3\)

\(3^x=27=3^3\)

\(=>x=3\)

d) \(\left(x+2\right)=64\) -> đề có thiếu không vậy?

e) \(3^2.x=3^5\)

\(x=3^5:3^2\)

\(=>x=3^3=27\)

f) \(\left(2x-1\right)^3=343\)

\(\left(2x-1\right)^3=7^3\)

\(=>2x-1=7\)

\(2x=7+1\)

\(2x=8\)

\(x=8:2\)

\(=>x=4\)

\(#Wendy.Dang\) 

a,\(2^x\)=128           b,\(8^{x-1}\)=64              c,3+\(3^x\)=30           d,x+2=64

\(2^7\)=128               \(8^{x-1}\)=\(8^2\)                 \(3^x\)=30-3                  x=64-2

=>x=7              =>x-1=2                  \(3^x\)=27                      x=62

                         x=2+1=3                \(3^x\)=\(3^3\)

                                                     =>x=3

e,\(3^2\).x=\(3^5\)                             f,(2x-\(1^3\))=343

x=\(3^5\):\(3^2\)                                 2x=1+343

x=27                                     2x=344

                                               x=344:2

                                               x=172

\(a,\frac{x+8}{3}+\frac{x+7}{2}=-\frac{x}{5}\)

\(\Leftrightarrow\frac{10\cdot\left(x+8\right)}{30}+\frac{15\left(x+7\right)}{30}=\frac{-6x}{30}\)

\(\rightarrow10x+80+15x+105=-6x\)

\(\Leftrightarrow31x+185=0\)

\(\Leftrightarrow x=-\frac{185}{31}\)

b,\(b,\frac{x-8}{3}+\frac{x-7}{4}=4+\frac{1-x}{5}\)

\(\Leftrightarrow\frac{20\left(x-8\right)}{60}+\frac{15\left(x-7\right)}{60}=\frac{240}{60}+\frac{12\left(1-x\right)}{60}\)

\(\rightarrow20x-160+15x-105=240+12-12x\)

\(\Leftrightarrow47x-517=0\)\(\Leftrightarrow x=11\)

\(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{x\left(x+1\right)}=\frac{2}{5}\)

\(\Rightarrow\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{2}{5}\)

\(\Rightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{2}{5}\)

\(\Rightarrow\frac{1}{x+1}=\frac{1}{2}-\frac{2}{5}\)

\(\Rightarrow\frac{1}{x+1}=\frac{1}{10}\)

=> x+1=10

=>x=9

cacs bạn 

1/2x3+1/3x4+...+1/x(x+1)=2/5

=> 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/x - 1/x + 1 = 2/5

=> 1/2 - 1/x + 1 = 2/5

=> 1/x + 1 = 1/10

=> x + 1 = 10

=> x = 9

\(a,-\dfrac{12}{16}-\left(\dfrac{3}{4}-x\right)=-\dfrac{5}{3}\)

\(\dfrac{3}{4}-x=-\dfrac{12}{16}-\left(-\dfrac{5}{3}\right)\)

\(\dfrac{3}{4}-x=\dfrac{11}{12}\)

\(x=\dfrac{3}{4}-\dfrac{11}{12}\)

\(x=-\dfrac{1}{6}\)

\(b,x-\dfrac{3}{7}:\dfrac{9}{14}=-\dfrac{7}{3}\)

\(x-\dfrac{3}{7}=-\dfrac{7}{3}\times\dfrac{9}{14}\)

\(x-\dfrac{3}{7}=-\dfrac{3}{2}\)

\(x=-\dfrac{3}{2}+\dfrac{3}{7}\)

\(x=-\dfrac{15}{14}\)

\(c,-\dfrac{3}{4}x+\dfrac{5}{8}x=\dfrac{1}{3}\)

\(\left(-\dfrac{3}{4}+\dfrac{5}{8}\right)x=\dfrac{1}{3}\)

\(-\dfrac{1}{8}x=\dfrac{1}{3}\)

\(x=\dfrac{1}{3}:\left(-\dfrac{1}{8}\right)\)

\(x=-\dfrac{8}{3}\)

`-12/16 - ( 3/4 - x ) = -5/3`

`=> 3/4 - x=-12/16 -(-5/3)`

`=> 3/4 - x=-12/16 +5/3`

`=> 3/4 - x=11/12`

`=> x= 3/4-11/12`

`=> x=9/12 -11/12`

`=> x=-1/6`

__

`x - 3/7 : 9/14 = - 7/3`

`=>x - 3/7=-7/3 xx 9/14`

`=>x - 3/7=-3/2`

`=>x= -3/2 + 3/7`

`=>x=-15/14`

__

`-3/4 x + 5/8 x =1/3`

`=> (-3/4 + 5/8) x =1/3`

`=> ( -6/8+ 5/8) x =1/3`

`=> -1/8 x=1/3`

`=>x= 1/3 : (-1/8)`

`=> x= 1/3 xx (-8)`

`=>x= -8/3`

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