a 15/7"3/4

có phải đề là:

\(\frac{1}{2}\)+\(\frac{2}{3}\)+\(\frac{3}{4}\)+\(\frac{4}{5}\)+\(\frac{3.99}{100}\)không bạn

I Love you mik nghĩ bn nên đọc kĩ đề hơn .Cộng 3 chấm là cộng ... mà chứ k phải 3.99

ừm hứm

lạy má, má vào cái ô trên cùng bên trái của phần gửi câu hỏi sẽ có các kí hiệu toán học

Ý bạn là thế này phải không:

\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{199}-\frac{1}{200}\)

\(=1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{200}-2.\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+....+\frac{1}{200}\right)\)

\(=\left(1+\frac{1}{2}+\frac{1}{3}+.....+\frac{1}{99}+\frac{1}{100}+\frac{1}{101}+...+\frac{1}{200}\right)-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)\)

=\(\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)

\(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{99\cdot100}\)

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\)

\(=1-\dfrac{1}{100}\)

\(=\dfrac{99}{100}\)

x={0;1;2;3;4;5;6;7;8}

\(\dfrac{x+3}{5}=\dfrac{7}{6}\Rightarrow6x+18=35\Leftrightarrow6x=17\Leftrightarrow x=\dfrac{17}{6}\)

đk : x khác 9 

\(\dfrac{4}{9-x}=\dfrac{1}{3}\Rightarrow12=9-x\Leftrightarrow-x=3\Leftrightarrow x=-3\)

a; -\(\dfrac{4}{9}.\dfrac{7}{15}+\dfrac{4}{-9}.\dfrac{8}{15}\)

= - \(\dfrac{4}{9}\).(\(\dfrac{7}{15}+\dfrac{8}{15}\))

= - \(\dfrac{4}{9}\).1

= - \(\dfrac{4}{9}\)

b; - \(\dfrac{5}{4}.\dfrac{16}{25}\) + \(\dfrac{-5}{4}\).\(\dfrac{9}{25}\)

= - \(\dfrac{5}{4}\).(\(\dfrac{16}{25}\) + \(\dfrac{9}{25}\))

= - \(\dfrac{5}{4}\). 1

= - \(\dfrac{5}{4}\)

c; \(-\dfrac{5}{12}.\dfrac{4}{19}\) + \(\dfrac{-7}{12}.\dfrac{4}{19}-\dfrac{40}{57}\)

= - \(\dfrac{5}{12}\).\(\dfrac{4}{19}\) - \(\dfrac{7}{12}\).\(\dfrac{4}{19}\) - \(\dfrac{4}{19}\).\(\dfrac{10}{3}\)

= - \(\dfrac{4}{19}\).(\(\dfrac{5}{12}\) + \(\dfrac{7}{12}\) + \(\dfrac{10}{3}\))

= - \(\dfrac{4}{19}\).\(\dfrac{13}{3}\)

= - \(\dfrac{52}{57}\)

\(\frac{3}{4}x\frac{5}{6}-\frac{1}{6}=\frac{11}{24}\)

\(4\frac{8}{5}-\frac{2}{3}=\frac{28}{5}-\frac{2}{3}=\frac{74}{15}\)