\(=\frac{3^2.4^2.2^{32}}{11.2^{35}-2^{36}}\)

\(=\frac{3^2.4^2.2^{32}}{2^{35}\left(11-2\right)}\)

\(=\frac{3^2.4^2.2^{32}}{2^{35}.3^2}\)

\(=\frac{4^2}{2^3}\)

\(=\frac{2^4}{2^3}\)

\(=2\)

Hk tốt

\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot9}=2\)

a, = 3^2.4^2.2^32/11.2^13.2^22-2^36

= 3^2.2^4.2^32/11.2^35-2^36

= 9.2^36/2^35.(11-2)

= 9.2^36/2^35.9 =  2

b, = 134.269+269-133/134.269+135 = 134.269+135/134.269+135 = 1

k mk nha

a, = 3^2.4^2.2^32/11.2^13.2^22-2^36

= 3^2.2^4.2^32/11.2^35-2^36

= 9.2^36/2^35.(11-2)

= 9.2^36/2^35.9 =  2

b, = 134.269+269-133/134.269+135 = 134.269+135/134.269+135 = 1

a) =\(\left[\left(12+1\right)^2+\left(12+2\right)^2\right]:\left(13^2+14^2\right)\)

   =1

b)=(1.2.3....8).(9-1-8)

   =(1.2.3....8).0

   =0

mik chỉ giải được zậy thôi.

t mik nha.

a)

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3^2.4^2.\left(2^{16}\right)^2}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)

\(=\frac{3^2.\left(2^2\right)^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{36}}\)

\(=\frac{9.2.2^{35}}{11.2^{35}-2.2^{35}}\)

\(=\frac{18.2^{35}}{2^{35}.\left(11-2\right)}\)

\(=\frac{18.2^{35}}{2^{35}.9}\)

\(=\frac{18}{9}\)

\(=2\)

(3.4.2^16)^2/11.2^13.4^11.16^9.=18/9=2

tui nói đúng  đó

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)

\(=\frac{9.\left(2^2\right)^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{9.2^4.2^{32}}{11.2^{35}-2^{36}}\)

\(=\frac{9.2^{36}}{2^{35}.\left(11-2\right)}\)

\(=\frac{9.2^{35}.2}{2^{35}.9}\)

\(=2\)

\(B=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}=\frac{3.2^2.2^{16.2}}{11.2^{13}.2^{22}-2^{36}}=\frac{3.2^{34}}{11.2^{35}-2^{36}}=\frac{3.2^{34}}{2^{34}\left(11.2-2^2\right)}\)

\(=\frac{3}{11.2-2^2}=\frac{3}{11.2-4}=\frac{3}{22-4}=\frac{3}{18}=\frac{1}{6}\)

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