Question

Tính hợp lí phép tính sau

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

Answer 1

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

\(=\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

\(=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{35}.2}\)

\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)

\(=\frac{9.2^{35}.2}{2^{35}.9}\)

\(=2\)

Answer 2

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

= \(\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

= \(\frac{3^2.4^2.2^{32}}{11.2^{35}-2^{35}.2}\)

= \(\frac{3^2.2^4.2^{32}}{2^{35}.\left(11-2\right)}\)

= \(\frac{3^2.2^{36}}{2^{35}.9}\)

= \(\frac{9.2^{35}.2}{2^{35}.9}\)

= \(2\)

Answer 3

\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)

=\(\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)

=\(\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{36}}\)

=\(\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}\)

=\(\frac{3^2.2^{36}}{2^{35}.9}\)

=\(\frac{3^22^{36}}{2^{35}.3^2}\)

=2

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