A,(X-2)^11 = (x-2)^3 ; b, (x-5)^24 = (x-5)^9 ; c, (x-5)^25 = (x-5)^4
a ) 4 . 3^x-1 + 2 . 3^x+2 = 4 . 3^6 + 2 . 3^9
b ) 5^x+4 - 3 . 5^x+3 = 2 . 5^11
c ) 11 . 6^x-1 = 11 . 6^11 + 2 . 6^13
\(4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(3^{x-1}.\left(4+2.3^3\right)=3^6.\left(4+2.3^3\right)\)
\(\Leftrightarrow3^{x-1}=3^6\)
\(\Leftrightarrow x-1=6\)
\(\Leftrightarrow x=7\)
Vậy \(x=7\)
\(5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(\Leftrightarrow5^{x+3}.\left(5-3\right)=2.5^{11}\)
\(\Leftrightarrow5^{x+3}.2=2.5^{11}\)
\(\Leftrightarrow5^{x+3}=5^{11}\)
⇔\(x+3=11\)
\(\Leftrightarrow x=8\)
Vậy \(x=8\)
\(11.6^{x-1}=11.6^{11}+2.6^{13}\)
\(\Rightarrow11.6^{x-1}=6^{11}.\left(11+2.36\right)\)
\(\Rightarrow11.6^{x-1}=6^{11}.83\)
a, x.2 + x .5 = 14 b, x.9 + x = 20
c, x: \(\dfrac{3}{2}\) + x. \(\dfrac{1}{3}\) = 1999 d, 11.(x+2) = 5.x + 40
e, 11.(x-6) = 4.x + 11 f, (3.x - 4) : x + 10 = 12
g, (5.x + 7) : x + 20 = 26 h, x.1999 - x = 1999.1997 + 1999
a, x.2 + x.5 = 14 b, x.9 + x = 20
c, x: \(\dfrac{3}{2}\) + x.\(\dfrac{1}{3}\) = 1999 d,11.(x+2) = 5.x + 40
e, 11.(x-6) = 4.x + 11 f, (3.x - 4) : x + 10 = 12
g, (5.x + 7) : x + 20 = 26 h, x.1999 - x = 1999.1997 + 1999
***dấu chấm(.) = dấu nhân(x)***
a) \(...\Rightarrow x.\left(2+5\right)=14\Rightarrow x.7=14\Rightarrow x=14:7=2\)
b) \(...\Rightarrow x.\left(9+1\right)=20\Rightarrow x.10=20\Rightarrow x=20:10=2\)
c) \(...\Rightarrow x.\left(\dfrac{2}{3}+\dfrac{1}{3}\right)=1999\Rightarrow x.\dfrac{3}{3}=1999\Rightarrow x=1999\)
d) \(...\Rightarrow11.x+22=5.x+40\Rightarrow11.x-5.x=40-22\Rightarrow6.x=18\Rightarrow x=18:6=3\)
e) \(...\Rightarrow11.x-66=4.x+11\Rightarrow11.x-4.x=11+66\Rightarrow7.x=77\Rightarrow x=77:7=11\)
f) \(...\Rightarrow\left(3.x-12\right):x=12-10\)
\(\Rightarrow3.x-12=2.x\)
\(\Rightarrow3.x-2.x=12\)
\(\Rightarrow x=12\)
g) \(...\Rightarrow\left(5.x+7\right):x=26-20\)
\(\Rightarrow5.x+7=6.x\)
\(\Rightarrow6.x-5.x=7\)
\(\Rightarrow x=7\)
h) \(...\Rightarrow x.\left(1999-1\right)=1999.\left(1997+1\right)\)
\(\Rightarrow x.1998=1999.1998\)
\(\Rightarrow x=1999.1998:1998\)
\(\Rightarrow x=1999\)
a, \(x\times\) 2 + \(x\times\) 5 = 14
\(x\) \(\times\) ( 2 + 5) = 14
\(x\) \(\times\) 7 = 14
\(x\) = 14: 7
\(x\) = 2
b, \(x\times9\) + \(x\)= 20
\(x\) \(\times\)( 9 + 1) = 20
\(x\) \(\times\) 10 = 20
\(x\) = 2
c, \(x\) : \(\dfrac{3}{2}\) + \(x\times\dfrac{1}{3}\) = 1999
\(x\times\) \(\dfrac{2}{3}\) + \(x\) \(\times\dfrac{1}{3}\) = 1999
\(x\times\) ( \(\dfrac{2}{3}\) + \(\dfrac{1}{3}\)) = 1999
\(x\) = 1999
d, 11\(\times\)(\(x+2\)) = 5 \(\times\) \(x\) + 40
11 \(\times\) \(x\) + 22 = 5 \(\times\) \(x\) + 40
11 \(\times\) \(x\) = 5 \(\times\) \(x\) + 40 - 22
11 \(\times\) \(x\) = 5 \(\times\) \(x\) + 18
11 \(\times\) \(x\) - 5 \(\times\) \(x\) = 18
\(x\) \(\times\) ( 11 - 5) = 18
\(x\) \(\times\) 6 = 18
\(x\) = 3
e, 11 \(\times\)( \(x-6\)) = 4 \(\times\) \(x\) + 11
11 \(\times\)\(x\) - 66 = 4 \(\times\) \(x\) + 11
11 \(\times\) \(x\) = 4 \(\times\) \(x\) + 11 + 66
11 \(\times\) \(x\) = 4 \(\times\) \(x\) + 77
11 \(\times\) \(x\) - 4 \(\times\) \(x\) = 77
\(x\) \(\times\) ( 11 - 4) = 77
\(x\) \(\times\) 7 = 77
\(x\) = 77 : 7
\(x\) = 11
g, (5 \(\times\) \(x\) + 7) : \(x\) + 20 = 26
(5 \(\times\) \(x\) + 7) : \(x\) = 26 - 20
(5 \(\times\) \(x\) + 7) : \(x\) = 6
5 \(\times\) \(x\) + 7 = 6 \(\times\) \(x\)
6 \(\times\) \(x\) - 5 \(\times\)\(x\) = 7
\(x\times\)( 6- 5) = 7
\(x\) = 7
f, (3 \(\times\) \(x\) - 4): \(x\) + 10 = 12
(3 \(\times\) \(x\) - 4) : \(x\) = 12 - 10
( 3 \(\times\) \(x\) - 4): \(x\) = 2
3 \(\times\) \(x\) - 4 = 2 \(\times\) \(x\)
3 \(\times\) \(x\) - 2 \(\times\) \(x\) = 4
\(x\) \(\times\) ( 3 - 2) = 4
\(x\) = 4
h, \(x\times\) 1999 - \(x\) = 1999 \(\times\)1997 + 1999
\(x\) \(\times\)( 1999 - 1) = 1999 \(\times\) ( 1997 + 1)
\(x\) \(\times\) 1998 = 1999 \(\times\) 1998
\(x\) = 1999 \(\times\) 1998 : 1998
\(x\) = 1999
Tìm x:
A)11/12+11/12.23+11/23.24+....+11/89.100+x=2/3
B)2/11.13+2/13.15+...+2/19.21-x+221/223=4/3
Mình nghĩ câu A phải là 11/23.34 mới đúng.
Theo đề mới: A)
11/12 = 11/1.12
Vậy A = 11/1.12 + 11/12.23 + ... + 11/89.100
= 1 - 1/12 + 1/12 - 1/23 + .... + 1/89 - 1/100
= 99/1000
Vậy x là: 2/3 - 99/100 = -97/300
B) 2/11.13 + ... + 2/19.21 = 1/11 - 1/13 + .... + 1/19 - 1/21 = 10/231
=> 10/231 - x = 4/3 - 221/223 = 229/669
=> x = 10/231 - 229/669
=> x = 6690/154539 - 52899/154539
=> x = -46209/154539 = -15403/51513
tìm giá trị nhỏ nhất
a) A= 25x^2 + 3y^2 - 10x +11
b) B= ( x - 3 )^2 + ( x - 11)^2
c) C= (x + 1) (x - 2) ( x- 3) ( x - 6)
tìm giá trị nhỏ nhất
a) A= 25x^2 + 3y^2 - 10x +11
b) B= ( x-3 )^2 + ( x-11)^2
c) C= (x+1) (x-2) (x-3) (x-6)
tìm giá trị nhỏ nhất
a) A= 25x^2 + 3y^2 - 10x +11
b) B= (x-3)^2 + ( x-11 )^2
c) C= (x+1) (x-2) (x-3) (x-6)
Bài 1 : Tính bằng hai cách
a) ( 6/11 + 5/11 ) x 3/7 =
b) 3/5 x 7/9 - 3/5 x 2/9 =
c) ( 6/7 - 4/7 ) : 2/5 =
d) 8/15 : 2/11 + 7/15 : 2/11 =
Bài 2 : Tính
a) 2 x 3 x4/3 x 4 x 5 =
b) 2/3 x 3/4 x 4/5 : 1/5 =
c) 1 x 2 x 3 x 4 / 5 x 6 x 7 x8 =
d) 2/5 x 3/4 x 5/6 : 3/4 =
a,Cách 1: (6/11 + 5/11 ) x 3/7 Cách 2 :(6/11 + 5/11) x 3/7
= 1 x 3/7 =6/11 x 3/7 + 5/11 x 3/7
= 3/7 = 18/77 + 15/77
= 3/7
b, Cách 1:3/5 x 7/9 - 3/5 x 2/9 Cách 2 :3/5 x 7/9 - 3/5 x 2/9
= 7/15 - 2/15 = 3/5 x (7/9 - 2/9 )
= 1/3 = 3/5 x 5/9
= 1/3
c, Cách 1:(6/7 - 4/7) : 2/5 Cách 2: ( 6/7- 4/7 ) : 2/5
= 2/7 : 2/5 = 6/7 : 2/5 - 4/7 : 2/5
= 5/7 = 15/7 - 10/7
= 5/7
d,Cách 1:8/15 : 2/11 + 7/15 : 2/11 Cách 2:8/15 : 2/11 +7/15 : 2/11
= 88/30 + 77/30 =(8/15+7/15) :2/11
= 11/2 = 1 : 2/11
= 11/2
Bài 2 cậu tự làm nhé !
\(2a.160\)
\(b.2\)
\(c.\frac{8064}{5}\)
\(d.\frac{1}{3}\)
A) ( 2/5× 1/2)×3/8 =?
B)7/9 ×3/5 + 4/9 ÷3/5=?
Tìm a/b biết
a/b x 16/11- a/b x 2/11 - a/b x 3/11 + a/b x 9=5/3
Giải cách làm ra
\(\dfrac{a}{b}\) x( \(\dfrac{16}{11}\) -\(\dfrac{2}{11}\)-\(\dfrac{3}{11}\)+9) = \(\dfrac{5}{3}\)
\(\dfrac{a}{b}\) x (1 + 9) =\(\dfrac{5}{3}\)
\(\dfrac{a}{b}\) x 10 = \(\dfrac{5}{3}\)
\(\dfrac{a}{b}\) = \(\dfrac{5}{3}\) : 10
a = \(\dfrac{1}{6}\)
lần sau bạn hãy nhớ giữ gìn sự trong sáng của tiếng việt nhé, học sinh của mình mà hỏi mình trống không thế này mình cho nghỉ vô thời hạn
tính nhanh : a) 2/5 x 1/4 + 3/4 x 2/5 b) 6/11 : 2/3 + 5/11 : 2/3
a) 2/5 x 1/4 + 3/4 x 2/5
= 2/5 x (1/4 + 3/4)
= 2/5 x 1
= 2/5
b) 6/11 : 2/3 + 5/11 : 2/3
= (6/11 + 5/11) : 2/3
= 1 : 2/3
= 3/2