Xac dinh ham so y=ax+b [1] biet do thi cua ham so di qua hai diem A[-1;\(\sqrt{2}\)] va B [2;\(\sqrt{2}\)+3] 

bai 2 cho ham so y = ax - 4

a) xac dinh he so goc a , biet rang do thi ham so di qua diem A(-2;6)

b) Ve do thi ham so tren mat phang toa do

cho ham so bac nhat y=-2x+3

goi M la diem co toa do (a;b) thuoc do thi.Xac dinh a;b biet \(\sqrt{a}\left(\sqrt{b}+1\right)=2\)

cho ham so y=(2m^2+m-3)*x. a)ve do thi cua ham so m=2.b) tim m biet do thi ham so di qua A

cho ham so y = f (x) = mx (n \(\ne\) 0)

a , tim M biet do thi ham so di qua A ( 3 ,6 )

b , ve do thi tim duoc o cau a

cho ham so y=(2k+1).x

a/ tim k biet do thi di qua A(-1;1)

b/ ve do thi ham so nay

c/ cho B(x_B;-10);C(-5;y_C) thuoc do thi tim x_B, y_C

xác định hàm số y = | a |x biet rang do thi ham so di qua diem A ( -3,1 )

tim x,y,z biet \(\sqrt{\left(x-\sqrt{5}\right)^2}+\sqrt{\left(y+\sqrt{3}\right)^2}+\left|x-y-z\right|\)