Tính nhanh:
F= \(\frac{14}{8}\)x \(\frac{24}{18}\)x \(\frac{36}{30}\)x...x \(\frac{10706}{10700}\).
Những câu hỏi liên quan
Tính B = \(\left(\frac{6}{8}+1\right)\)x \(\left(\frac{6}{18}+1\right)\)x \(\left(\frac{6}{30}+1\right)\)x ... x \(\left(\frac{6}{10700}+1\right)\)
Tính nhanh E=\(\frac{6}{8+1}.\frac{6}{18+1}.\frac{6}{30+1}...\frac{6}{10700+1}\)
\(\frac{3}{4}x\frac{8}{9}x\frac{15}{16}x\frac{24}{25}x\frac{35}{36}x\frac{48}{49}x\frac{63}{64}\)
Tính giá trị biểu thức
\(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}.\frac{24}{25}...\frac{63}{64}\)
\(=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}.\frac{4.6}{5.5}...\frac{7.9}{8.8}\)
\(=\frac{1.3.2.4.3.5.4.6...7.9}{2.2.3.3.4.4.5.5...8.8}\)
\(=\frac{1.9}{2.8}=\frac{9}{16}\)
Tính nhanh:
F=\(\left(\frac{6}{8}+1\right)\left(\frac{6}{18}+1\right)\left(\frac{6}{30}+1\right).....\left(\frac{6}{10700}+1\right)\)
F=(6/8+1)(6/18+1)(6/30+1)...(6/10700+1)
14.24.36...10706
F= ---------------------------
8.18.30....10700
7.2.8.3.9.4...106.101
F= -----------------------------------
8.1.9.2.10.3...107.100
(7.8.9....106)(2.3.4...101)
F= ----------------------------------------
(8.9.10...107)(2.3.4...100)
7.101
F= ----------
107
F=1
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Mình nhầm nhé! Bạn để nguyên:
F =707/101 là được rồi
K mình nhé!
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1) \(\frac{24}{-12}=\frac{x}{5}=\frac{-y}{3}\)Tìm x và y
2) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-5}{25}\le\frac{x}{10}< \frac{-3}{4}+\frac{4}{14}+\frac{-2}{8}+\frac{-3}{5}+\frac{5}{7}\)Tìm x
3) \(\frac{8.x+18}{2.x+6}\)Tìm x
Tính :
\(A=\left(\frac{6}{8}+1\right)\left(\frac{6}{18}+1\right)\left(\frac{6}{30}+1\right)...\left(\frac{6}{10700}+1\right)\)
Giúp cái !!!
1. Giải phương trình
a) \(\frac{2}{x^2-x-6}+\frac{x+1}{x^2+x-12}=\frac{x}{x^2+6x+8}\)
b) \(\frac{2x-5}{x^2+5x-36}-\frac{x-6}{x^2+3x-28}=\frac{x+8}{x^2+16x+63}\)
c) \(\frac{x-2}{4x^2-29x+30}-\frac{x+1}{20x^2-13x-15}=\frac{x+2}{5x^2-274x+18}\)
\(\dfrac{2}{x^2-x-6}+\dfrac{x+1}{x^2+x-12}=\dfrac{x}{x^2+6x+8}\)
\(\Leftrightarrow\dfrac{2}{\left(x-3\right)\left(x+2\right)}+\dfrac{x+1}{\left(x-3\right)\left(x+4\right)}=\dfrac{x}{\left(x+2\right)\left(x+4\right)}\)
=> 2(x+4)+(x+1)(x+2)=x(x-3)
⇔2x+8+x2+2x+x+2=x2-3x
⇔x2+5x+10=x2-3x
⇔x2-x2+5x+3x=-10
⇔8x=-10
\(\Leftrightarrow\dfrac{-5}{4}\)
Vậy S={-\(\dfrac{5}{4}\)}
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Tính: A=\(\left(\frac{6}{8}+1\right)\cdot\left(\frac{6}{18}+1\right)\cdot\left(\frac{6}{30}+1\right)\cdot...\cdot\left(\frac{6}{10700}+1\right)\)
Tính giá trị biểu thức sau :
\(B=\left(\frac{6}{8}+1\right)\left(\frac{6}{18}+1\right)\left(\frac{6}{30}+1\right)...\left(\frac{6}{10700}+1\right)\)