a. X=-124

b.x=-2

c. X= 298

D. X=-15

a) -124

b) -2

c) 298

d) -15

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Trả lời hộ mình với các bn 

a, Ta có : \(-20< x< 21\)

\(\Rightarrow x\in\left\{-19;-18;-17;-16;...;20\right\}\)

b, Ta có : \(|x|< 10\)

\(\Rightarrow x\in\left\{-9;-8;-7;-6;-5;-4;...;8;9\right\}\)

c, \(-16+23+x=-16\)

                    \(23+x=\left(-16\right)-\left(-16\right)\)

                     \(23+x=0\)

                               \(x=0-23\)

                              \(x=-23\)

a) \(-20< x< 21\)

\(x\in\left\{\pm19;\pm18;\pm17;...\right\}\)

b) \(\left|x\right|< 10\)

\(0< x< 10\)

\(\Rightarrow x\in\left\{1;2;3;4;5;6;7;8;9\right\}\)

c) \(-16+23+x=-16\)

\(7+x=-16\)

\(x=-23\)

Tìm số nguyên x, biết:
1) -16 + 23 + x = - 16

7+x=-16

    x=-16-7

    x=-23
2) 2x – 35 = 15

2x=15+35

2x=50

  x=50:2

  x=25
3) 3x + 17 = 12

3x=12-17

3x=-5

  x=-5/3
4) (2x – 5) + 17 = 6

2x-5=6-17

2x-5=-11

2x=-11+5

2x=-6

  x=-6:2

  x=-3
5) 10 – 2(4 – 3x) = -4

2(4-3x)=10-(-4)

2(4-3x)=14

4-3x=14:2

4-3x=7

3x=4-7

3x=-3

  x=-3:3

  x=-1
6) - 12 + 3(-x + 7) = -18

3(-x+7)=-18-(-12)

3(x+7)=-6

x+7=-6:3

x+7=-2

    x=-2-7

    x=-9

tự đi mà làm

a) - 23                          b) 25                      c) 9                        d) -1

a,x=-2,-2,0,1

b, x-18=16x3

x-18=48 suy ra x = 66

c, 3x(x+4)=128-23

3x(x+4)=105

x(x+4)=105:3=35

x.x=x.4

x^2=4

x=2

a,=>x=(-2)-1;0;1

b,x-18=16.3

  x-18=48

       x=48+18

       x=66

c,3(x+4)=128-23

   3(x+4)=105

       x+4= 105:3

       x+4=35

           x=35-4

           x=31

A,-16+23+x=-16

\(x=-16+16-\)23

=> x = -23

B.

-1+2-5+7-..+97-99

=(-1-99)+(-3-97)+...+(-49-51)

=(-100)+(-100)+...+(-100)

Có 50 cặp -100

Nên Tổng bằng : -100.50=-5000

Vậy....=-5000

HỌC TỐT

1. \(\text{6 + 2.(x - 19) = 16}.\)

\(\Leftrightarrow2.\left(x-19\right)=10.\)

\(\Leftrightarrow x-19=5.\)

\(\Leftrightarrow x=24.\)

Vậy \(x=24.\)

2. \(\text{(-240) : x – 16 = 64}.\)

\(\Leftrightarrow\left(-240\right):x=80.\)

\(\Leftrightarrow x=-3.\)

Vậy \(x=-3.\)

3. \(2x^3=16.\)

\(\Leftrightarrow x^3=8.\)

\(\Leftrightarrow x=2.\)

Vậy \(x=2.\)

a) -16 + 23 + x = -16

=> 7 + x = -16

=> x = -16 - 7

=> x = -23

b) 3x + 17 = 12

=> 3x = 12 - 17

=> 3x = -5

=> x = -5/3

vì x là số nguyên => x ko có gtri thõa mãn đề bài

c) (2x - 5) + 17 = 16

=> 2x - 5 = 16 - 17

=> 2x - 5 = -1

=> 2x = -1 + 5

=> 2x = 4

=> x = 4 : 2

=> x = 2

\(-16+23+x=-16\)

\(\Rightarrow x=-16-23+16\)

\(\Rightarrow x=-23\)

\(3x+17=12\)

\(3x=-5\)

\(x=-\frac{5}{3}\)

\(24:\left(3x-2\right)=-3\)

\(\Rightarrow3x-2=-8\)

\(3x=-6\)

\(x=-2\)

\(\left(2x-5\right)+17=16\)

\(2x=16-17+5\)

\(x=2\)

\(-6< x< 3\)

\(\Rightarrow x\in\left\{-5;-4;-3;-2;-1;0;1;2\right\}\)

"Tự tính tổng "

\(a,2x^2+y^2+6x-2xy+9=0\\ \Leftrightarrow\left(x^2-2xy+y^2\right)+\left(x^2+6x+9\right)=0\\ \Leftrightarrow\left(x-y\right)^2+\left(x+3\right)^2=0\\ \Leftrightarrow\left\{{}\begin{matrix}x=y\\x=-3\end{matrix}\right.\Leftrightarrow x=y=-3\\ b,A=\left(x-2021\right)^2+\left(x+2022\right)^2=x^2-4042x+2021^2+x^2+4044x+2022^2\\ A=2x^2+2x+2021^2+2022^2\\ A=2\left(x^2+x+\dfrac{1}{4}\right)+2021^2+2022^2-\dfrac{1}{2}\\ A=2\left(x+\dfrac{1}{2}\right)^2+2021^2+2022^2-\dfrac{1}{2}\ge2021^2+2022^2-\dfrac{1}{2}\\ A_{max}=2021^2+2022^2-\dfrac{1}{2}\Leftrightarrow x=-\dfrac{1}{2}\)\(c,P=\left(a+1\right)\left(a+3\right)\left(a+5\right)\left(a+7\right)+16\\ P=\left(a^2+8a+7\right)\left(a^2+8a+15\right)+16\\ P=\left(a^2+8a+11\right)^2-16+16=\left(a^2+8a+11\right)^2\left(Đpcm\right)\)