a) 2x + 5 = x - 7

    2x -x   = -7 - 5

    x         = -12

b) | x | = | 8 |

    | x | = 8

=> x = 8

   hoặc x = -8

c) | 2x-1 | = | -13 |

    | 2x-1 | = 13

=> 2x-1   = 13

     2x      = 13 + 1

     2x      = 14

     x        = 14:2

     x        = 7

hoặc 2x-1 = -13

        2x     = -13 + 1

        2x     = -12

         x      = -12 : 2

         x      = -6

bn bè hỏi giống chắc hi .....

uk, mà rg bn tìm câu hỏi tương tự ko có hèo

                 Vì\(\left|2x-2\right|=x+8\) 

                 \(\Rightarrow\hept{\begin{cases}2x-2=x+8\\2x-2=-\left(x+8\right)\end{cases}}\Rightarrow\hept{\begin{cases}2x-x=8+2\\2x-2=-x-8\end{cases}}\)

                \(\Rightarrow\hept{\begin{cases}x=10\\2x+x=-8+2\end{cases}}\Rightarrow\hept{\begin{cases}x=10\\3x=-6\end{cases}}\)

                \(\Rightarrow\hept{\begin{cases}x=10\\x=-2\end{cases}}\)

              Vậy \(x\in\left\{-2;10\right\}\)

               \(\left|2x-8\right|+4x=6\)

              \(\left|2x-8\right|=6-4x\)

              \(\Rightarrow\hept{\begin{cases}2x-8=6-4x\\2x-8=-\left(6-4x\right)\end{cases}}\Rightarrow\hept{\begin{cases}2x+4x=6+8\\2x-8=-6+4x\end{cases}}\)

             \(\Rightarrow\hept{\begin{cases}6x=14\\2x-4x=-6+8\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{7}{3}\\-2x=2\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{7}{3}\\x=-1\end{cases}}\)

             Vì x là số nguyên nên \(x=-1\)

            Vậy \(x=-1\)

             Ủng hộ mk nha !!! ^_^

\(\left|x+6\right|\) + \(\left|2x+10\right|\) = 5x

(x+6) + (2x +10) = 5x

x + 6 + 2x + 10 = 5x

(x + 2x) + (6 + 10) = 5x

( 3x ) + 16 = 5x

5x - 3x = 16

2x = 16

x = 16 : 2

x = 8

vậy x=8

+ = 5x

(x+6) + (2x +10) = 5x

x + 6 + 2x + 10 = 5x

(x + 2x) + (6 + 10) = 5x

( 3x ) + 16 = 5x

5x - 3x = 16

2x = 16

x = 16 : 2

x = 8

vậy x=8

+ = 5x

(x+6) + (2x +10) = 5x

x + 6 + 2x + 10 = 5x

(x + 2x) + (6 + 10) = 5x

( 3x ) + 16 = 5x

5x - 3x = 16

2x = 16

x = 16 : 2

x = 8

vậy x=8

tick và theo dõi giúp mình nha

5/ (x² – 4) + (x – 2)(4 – 2x) = 0

⇔(x-2)(x+2)+(x – 2)(4 – 2x)=0

⇔(x-2)(x+2+4-2x)=0

⇔(x-2)(6-x)=0

⇔\(\left[{}\begin{matrix}x-2=0\\6-x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=6\end{matrix}\right.\)

6/ x(2x – 7) – 4x + 14 = 0

⇔2x²-11x+14=0

⇔(x-\(\frac{7}{2}\))(x-2)=0

⇔\(\left[{}\begin{matrix}x-\frac{7}{2}=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{7}{2}\\x=2\end{matrix}\right.\)

7/ x² – x – (3x–3)= 0

⇔x²-4x+3=0

⇔(x-3)(x-1)=0

⇔\(\left[{}\begin{matrix}x-3=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

8/ (x² – 2x + 1) – 4 = 0

⇔(x-1)²-4=0

⇔(x-1-4)(x-1+4)=0

⇔(x-5)(x+3)=0

⇔\(\left[{}\begin{matrix}x-5=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-3\end{matrix}\right.\)

9/ 4x² + 4x + 1 = x²

⇔3x²+4x+1=0

⇔(3x+1)(x+1)=0

⇔\(\left[{}\begin{matrix}3x+1=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\frac{1}{3}\\x=-1\end{matrix}\right.\)

10/ x² – x = - 2x + 2

⇔3x²-x-2=0 (chuyển vế)

⇔(3x+2)(x-1)=0

⇔\(\left[{}\begin{matrix}3x+2=0\\x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\frac{2}{3}\\x=1\end{matrix}\right.\)

11/ x² – 5x + 6 = 0

⇔x²-3x-2x+6=0

⇔x(x-3)-2(x-3)=0

⇔(x-3)(x-2)=0

⇔\(\left[{}\begin{matrix}x-3=0\\x-2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=2\end{matrix}\right.\)

Mình làm bài khá tắt nên có gì không hiểu bạn cứ hỏi mình nha!

5/(x²-4)+(x-2)(4-2x)=0⇔x²-4+4x-2x²-8+4x=0

⇔-x²+8x-12=0⇔-x²+2x+6x-12=0⇔-x(x-2)-6(x-2)=0⇔(-x-6)(x-2)=0

⇔-x-6=0 hoặc x-2=0⇔x=-6 hoặc x=2

x-10 =-8-6

=>x-10=-14

=>x=-14+10=-4

6-2x=16

=>2x=6-16=-10

=>x=-10/2=-5

(4x-2).(x+5)=0

=>4x-2=0 hoặc x+5=0

=>4x=2 hoặc x=5

=>x=1/2 hoặc x=5