43⁴³ + 17¹⁷ + 19²³ có chữ số tận cùng là 3

34¹⁵ + 15⁹ + 41⁴¹ có chữ số tận cùng là 0

e, (-25).(-13).8.(-4).125

= (-25).(-4).8.125.(-13)

= 100.1000.(-13)=-1300000

f, 38.(-43)+43.(-79)-(-43).17

= 38.(-43)+(-43).79-(-43).17

= (-43).(38+79-17)

= (-43).100=-4300

a) ( -7) . 11 + 7 . ( - 89 )

= 7 . (-11) + 7 . (-89)

= 7 . [(-11)+(-89)]

= 7 . (-100)

= -700

b, (-57).(67-34)-67.(34-57)

= -57.67+57.34-67.34+67.57

= 34(57-67)=34.(-10)=-340

c, (17-25)-(-37-25+17)

= 17-25+37+25-17

=37

d, -(-72-25+17)+(-72+17)

= 72+25-17-72+17= 25

không ai làm nhỉ

\(-2x-\left(x-17\right)=34-\left(-x+25\right)\)

\(-2x-x+17=34+x-25\)

\(-2x-x-x=34-25-17\)

\(-4x=-8\Leftrightarrow x=2\)

\(17x-\left(16x-37\right)=2x+43\)

\(17x-16x+37=2x+43\)

\(17x-16x-2x=-37+43\)

\(-x=6\Leftrightarrow x=6\)

\(-2x-3\left(x+17\right)=34-2\left(-x+25\right)\)

\(-2x-3x-51=34+2x-50\)

\(-2x-3x-2x=34-50+51\)

\(-7x=35\Leftrightarrow x=-5\)

Bài làm

\(A=\left[\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{17}+\frac{33}{34}\right]:\left[\left(\frac{7}{2001}+\frac{11}{4002}\right).\frac{2001}{25}+\frac{9}{2}\right]\)

\(=\left[\frac{1}{386}.\frac{193}{17}+\frac{33}{34}\right]:\left[\frac{25}{4002}.\frac{2001}{25}+\frac{9}{2}\right]\)

\(=\left[\frac{1}{34}+\frac{33}{34}\right]:\left[\frac{1}{2}+\frac{9}{2}\right]\)

\(=\frac{1}{5}\)

=1/17

tam mai giải rõ cụ thể dc ko bn hii

\(M=\left[\left(\dfrac{2}{193}-\dfrac{3}{386}\right)\cdot\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\left(\dfrac{7}{2001}+\dfrac{11}{4002}\right)\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right]\)

\(M=\left[\left(\dfrac{4}{386}-\dfrac{3}{386}\right)\cdot\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\left(\dfrac{14}{4002}+\dfrac{11}{4002}\right)\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right]\)

\(M=\left(\dfrac{1}{386}\cdot\dfrac{193}{17}+\dfrac{33}{34}\right):\left(\dfrac{25}{4002}\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right)\)

\(M=\left(\dfrac{1}{34}+\dfrac{33}{34}\right):\left(\dfrac{1}{2}+\dfrac{9}{2}\right)\)

\(M=1:5\)

\(M=\dfrac{1}{5}\)

\(=\left[\dfrac{4-3}{386}\cdot\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\dfrac{25}{4002}\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right]\)

\(=\left(\dfrac{1}{34}+\dfrac{33}{34}\right):\left[\dfrac{1}{2}+\dfrac{9}{2}\right]\)

=1/5

a) -2x - (x-17) = 34-(-x + 25)

-2x- x+17= 34+x-25

-2x-x-x= -17 +34-25

-4x = -8

x = 2

b)17x-(-16x-27) = 2x+43

17x + 16x + 27 = 2x + 43

17x + 16x -2x= -27 +43

31x= 26

x= 21/31

c)- 2x- 3(x-17) = 34- 2(-x + 25)

-2x - 3x + 51 = 34 + 2x -50

-2x - 3x -2x = -51 + 34 -50

-7x = -67

x = 67/7

d) 17x +3(-16x-37) = 2x+ 43 -4x

17x -48x -111 = 2x + 43 -4x

17x - 48x -2x + 4x = 111 -43

-29x = 68

x = -68/29