(4^6*3^4*9^5)/6^12=
Những câu hỏi liên quan
Tính
1. 6/5 - 1/4 + 4/5 - 3/4
2. 7/9 - 5/12 + 2/9 - 7/12
3. -4/15 + 5/13 - 11/15 + 8/13
4. 9/15 - 7/13 +6/15 - 6/13
5. 12/5 - 3/7 + 3/5 - 4/7
6. 6/5 - 1/4 + 4/5 - 3/4 + 1/2
7. 13/7 - 8/6 + 8/7 - 4/6 - 1/3
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Tính
1. 6/5 - 1/4 + 4/5 - 3/4
2. 7/9 - 5/12 + 2/9 - 7/12
3. -4/15 + 5/13 - 11/15 + 8/13
4. 9/15 - 7/13 +6/15 - 6/13
5. 12/5 - 3/7 + 3/5 - 4/7
6. 6/5 - 1/4 + 4/5 - 3/4 + 1/2
7. 13/7 - 8/6 + 8/7 - 4/6 - 1/3
6/5 có nghĩa là sáu phần năm đó nha mn
\(\frac{6}{5}-\frac{1}{4}+\frac{4}{5}-\frac{3}{4}\)
\(=\left(\frac{6}{5}+\frac{4}{5}\right)-\left(\frac{1}{4}+\frac{3}{4}\right)\)
\(=2-1\)
\(=1\)
\(\frac{7}{9}-\frac{5}{12}+\frac{2}{9}-\frac{7}{12}\)
\(=\left(\frac{7}{9}+\frac{2}{9}\right)-\left(\frac{5}{12}+\frac{7}{12}\right)\)
\(=1-1\)
\(=0\)
các câu sau tương tự
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A=1
B=0
C=ÂM 8/15
D=0
E=2
F=3/2
H=2/3
LẦN SAU CHO KHÓ SÍU NHA LỚP 5 CŨNG LÀM ĐC
4/5 : ( 4/5 . -5/4) : ( 16/25 - 1/5 )
11/12 : ( 7/9 + -1/3 ) - ( 2/3 - 5/15 )
-2/5 . ( 9/8 + 16/32 -3/4 ) - 9/10
( 4/3 + 8/3 ) . ( 7/4 - 6/4 ) : ( 6/5 + 12/5 + 1/5 )
cách giải bài này như nào: 5/20+1/4+6/24+8/32=bao nhiêu
\(\dfrac{4}{5}\) : (\(\dfrac{4}{5}\) .- \(\dfrac{5}{4}\)) : (\(\dfrac{16}{25}\) - \(\dfrac{1}{5}\))
= \(\dfrac{4}{5}\) : (-1) : (\(\dfrac{16}{25}\) - \(\dfrac{5}{25}\))
= -\(\dfrac{4}{5}\) : \(\dfrac{11}{25}\)
= - \(\dfrac{4}{5}\) x \(\dfrac{25}{11}\)
= - \(\dfrac{20}{11}\)
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\(\dfrac{11}{12}\) : (\(\dfrac{7}{9}\) + \(\dfrac{-1}{3}\)) - (\(\dfrac{2}{3}\) - \(\dfrac{5}{15}\))
= \(\dfrac{11}{12}\) : (\(\dfrac{7}{9}\) - \(\dfrac{3}{9}\)) - (\(\dfrac{2}{3}\) - \(\dfrac{1}{3}\))
= \(\dfrac{11}{12}\) : \(\dfrac{4}{9}\) - \(\dfrac{1}{3}\)
= \(\dfrac{11}{12}\) x \(\dfrac{9}{4}\) - \(\dfrac{1}{3}\)
= \(\dfrac{99}{48}\) - \(\dfrac{1}{3}\)
= \(\dfrac{99}{48}\) - \(\dfrac{16}{48}\)
= \(\dfrac{83}{48}\)
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Xem thêm câu trả lời
4/5 : ( 4/5 . -5/4) : ( 16/25 - 1/5 )
11/12 : ( 7/9 + -1/3 ) - ( 2/3 - 5/15 )
-2/5 . ( 9/8 + 16/32 -3/4 ) - 9/10
( 4/3 + 8/3 ) . ( 7/4 - 6/4 ) : ( 6/5 + 12/5 + 1/5 )
\(\dfrac{4}{5}\): (\(\dfrac{4}{5}\).-\(\dfrac{5}{4}\)) : (\(\dfrac{16}{25}\) - \(\dfrac{1}{5}\))
=\(\dfrac{4}{5}\) x - 1: (\(\dfrac{16}{25}\) - \(\dfrac{5}{25}\))
= - \(\dfrac{4}{5}\) : \(\dfrac{11}{25}\)
= - \(\dfrac{4}{5}\) x \(\dfrac{25}{11}\)
= - \(\dfrac{20}{11}\)
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\(\dfrac{11}{12}\): (\(\dfrac{7}{9}\) + - \(\dfrac{1}{3}\)) - (\(\dfrac{2}{3}\) - \(\dfrac{5}{15}\))
= \(\dfrac{11}{12}\) : (\(\dfrac{7}{9}\) - \(\dfrac{3}{9}\)) - (\(\dfrac{2}{3}\) - \(\dfrac{1}{3}\))
= \(\dfrac{11}{12}\) : \(\dfrac{4}{9}\) - \(\dfrac{1}{3}\)
= \(\dfrac{11}{12}\) x \(\dfrac{9}{4}\) - \(\dfrac{1}{3}\)
= \(\dfrac{99}{48}\) - \(\dfrac{16}{48}\)
= \(\dfrac{83}{48}\)
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- \(\dfrac{2}{5}\).(\(\dfrac{9}{8}\) + \(\dfrac{16}{32}\) - \(\dfrac{3}{4}\)) - \(\dfrac{9}{10}\)
= - \(\dfrac{2}{5}\).(\(\dfrac{9}{8}\) + \(\dfrac{4}{8}\) - \(\dfrac{6}{8}\)) - \(\dfrac{9}{10}\)
= - \(\dfrac{2}{5}\).(\(\dfrac{13}{8}\) - \(\dfrac{6}{8}\)) - \(\dfrac{9}{10}\)
= - \(\dfrac{2}{5}\).\(\dfrac{7}{8}\) - \(\dfrac{9}{10}\)
= - \(\dfrac{7}{20}\) - \(\dfrac{18}{20}\)
= - \(\dfrac{5}{4}\)
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Bài 1: Tính:
A= ((2^12 . 3^5 - 4^6 . 9^3 ) / 9( 2^2 . 3 )^6 + (8^4 . 3^5))) - ((5^10 . 7^3 - 25^2 . 49^2) / (( 125 . 7 )^3 + 5^9 . 14^3))
B= (2^9 . 27^3 + 15 . 4^9 . 9^4) / (6^9 . 2^0 + 12^10)
Sap xep cac phan so sau theo thu tu tu lon den be
8/9; 4/5; 9/8; 3/4; 10/9; 12/12; 7/8; 1/6; 1/4; 3/2; 1/5; 8/7; 6/5; 5/6; 4/3; 6/7; 2/3; 2/15; 1/2;5/4
Bài 1: Tính:
A= ((2^12 . 3^5 - 4^6 . 9^3 ) / 9( 2^2 . 3 )^6 + (8^4 . 3^5))) - ((5^10 . 7^3 - 25^2 . 49^2) / (( 125 . 7 )^3 + 5^9 . 14^3))
B= (2^9 . 27^3 + 15 . 4^9 . 9^4) / (6^9 . 2^0 + 12^10)
Tính:
a) -5/7(14/5 - 7/10) : |-2/3| - 3/4(8/9 + 16/3) + 10/3(1/3 + 1/5)
b) 17/-26(1/6 - 5/3) : 17/13 - 20/3(2/5 - 1/4) + 2/3(6/5 - 9/2)
c) -8/9(9/8 - 3/2) + 5/4 : (5/2 - 15/4) - 3/4(10/9 - 8/3) : (-1/3)
d) 21/10 : (12/5 - 9/10) . (-4/7) - 3/2(1/6 - 7/12) + 1/5(3/2 - 1/4)
a) Ta có: \(\dfrac{-5}{7}\left(\dfrac{14}{5}-\dfrac{7}{10}\right):\left|-\dfrac{2}{3}\right|-\dfrac{3}{4}\left(\dfrac{8}{9}+\dfrac{16}{3}\right)+\dfrac{10}{3}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)\)
\(=\dfrac{-5}{7}\cdot\dfrac{3}{2}\cdot\dfrac{21}{10}-\dfrac{3}{4}\cdot\dfrac{56}{3}+\dfrac{10}{3}\cdot\dfrac{8}{15}\)
\(=\dfrac{-9}{4}-14+\dfrac{16}{9}\)
\(=\dfrac{-1621}{126}\)
b) Ta có: \(\dfrac{17}{-26}\cdot\left(\dfrac{1}{6}-\dfrac{5}{3}\right):\dfrac{17}{13}-\dfrac{20}{3}\left(\dfrac{2}{5}-\dfrac{1}{4}\right)+\dfrac{2}{3}\left(\dfrac{6}{5}-\dfrac{9}{2}\right)\)
\(=\dfrac{-17}{26}\cdot\dfrac{13}{17}\cdot\dfrac{-3}{2}-\dfrac{20}{3}\cdot\dfrac{3}{20}+\dfrac{2}{3}\cdot\dfrac{-33}{10}\)
\(=\dfrac{3}{4}-1-\dfrac{11}{5}\)
\(=-\dfrac{49}{20}\)
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Giúp mik câu này mik đag cần gấp
Tính :
1)3/5 x1/7 +3/5 x6/7 -3/5
2)6/7 x4/9 + 6/7 x5/9 + 6/7
3) 9/13 x 7/12 + 9/13 x 5/12 - 9/13
4) 4/13 x5/12 +4/13 x 7/12 - 4/13
1) = \(\frac{3}{5}\)
2) =\(\frac{6}{7}\)
3)\(\frac{9}{13}\)
4)\(\frac{4}{13}\)
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Tính nhanh:
a/ (1*5*6+2*10*12+4*20*24+9*45*54)/(1*3*5+2*6*10+4*12*20+9*27*45)
b/ [(1*5*6)+(2*10*12)+(4*20*24)+(9*45*54)]/[(1*3*5)+(2*6*10)+(4*12*20)+(9*27*45)]
/ là phân số nha!!!!!!!!!!!!!