\(\Leftrightarrow x\left(\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{14}\right)=\dfrac{1}{21}\)

\(\Leftrightarrow x\cdot\dfrac{2}{7}=\dfrac{1}{21}\)

hay \(x=\dfrac{1}{21}:\dfrac{2}{7}=\dfrac{1}{6}\)

27,16:25=679/625=1 dư 54

giúp mk giải gấp 2 bài này với chiều tầm 3h mình qua lấy nha.cảm ơn mọi người nhiều ah.

anh Hải mà on thì chắc giải đc r :v

a: \(3H_2+Fe_2O_3\rightarrow2Fe+3H_2O\)

b: \(n_{Fe_2O_3}=\dfrac{16}{160}=0.1\left(mol\right)\)

\(\Leftrightarrow n_{H_2O}=n_{H_2}=0.1\cdot3=0.3\left(mol\right)\)

\(v_{H_2}=0.3\cdot22.4=6.72\left(lít\right)\)

f: \(3ab-6a+b-2\)

\(=3a\left(b-2\right)+\left(b-2\right)\)

\(=\left(b-2\right)\left(3a+1\right)\)

Okie, xinh nên giúp :3 Đùa thui

a/ 5 nguồn mắc nối tiếp \(\left\{{}\begin{matrix}\xi_b=5.\xi=5.4=20\left(V\right)\\r_b=5r=5.0,2=1\left(\Omega\right)\end{matrix}\right.\)

b/ \(R_D=\dfrac{U^2_{dm}}{P_{dm}}=\dfrac{36}{6}=6\left(\Omega\right);I_{dm}=\dfrac{P_{dm}}{U_{dm}}=\dfrac{6}{6}=1\left(A\right)\)

Đèn sáng bình thường \(\Rightarrow I_2=I_D=I_{dm}=1\left(A\right)\)

\(\left(R_1ntR_B\right)//\left(R_2ntR_D\right)\Rightarrow R_{td}=\dfrac{\left(R_1+R_B\right)\left(R_2+R_D\right)}{R_1+R_B+R_2+R_D}=\dfrac{\left(2+4\right)\left(6+6\right)}{2+4+6+6}=4\left(\Omega\right)\)

c/ \(I=\dfrac{\xi_b}{r_b+R_{td}}=\dfrac{20}{1+4}=4\left(A\right)\)

\(I=I_1+I_2\Rightarrow I_1=I-I_2=4-1=3\left(A\right)\Rightarrow P_1=I_1^2.R_1=3^2.2=18\left(W\right)\)

\(m_{Cu}=\dfrac{A_{Cu}.I_B.t}{F.n}=\dfrac{64.3.\left(32.60+10\right)}{96500.2}=...\left(g\right)\)