18,7 × 10 - 9,2 + 7,3
(\(\frac{4}{5}\)+\(\frac{3}{10}\)- \(\frac{1}{5}\)) × 6 : \(\frac{4}{7}\)
17029 - 3502 : 34 × 124 + 2476
Những câu hỏi liên quan
các bn làm giúp mk vs thông cảm nha:(đều là hs nên hiểu nhau cả mà,ai làm đc câu nào thì cố giúp mk nha)a)-66left(frac{1}{2}-frac{1}{3}-frac{1}{11}right)+124.left(-37right)+61.left(-124right)b)left(2-frac{3}{2}right).left(2-frac{4}{3}right).left(2-frac{5}{4}right).left(2-frac{6}{5}right)c)frac{0,75-0,6+frac{3}{7}+frac{3}{11}}{2,75-2,2+frac{11}{7}+frac{11}{13}}d)left[left(frac{2}{193}-frac{3}{386}right).frac{193}{7}+frac{33}{34}right]:left[left(frac{7}{2001}+frac{11}{4002}right).frac{2001}{25}+fr...
Đọc tiếp
các bn làm giúp mk vs thông cảm nha:(đều là hs nên hiểu nhau cả mà,ai làm đc câu nào thì cố giúp mk nha)
a)\(-66\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{11}\right)+124.\left(-37\right)+61.\left(-124\right)\)
b)\(\left(2-\frac{3}{2}\right).\left(2-\frac{4}{3}\right).\left(2-\frac{5}{4}\right).\left(2-\frac{6}{5}\right)\)
c)\(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{11}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)
d)\(\left[\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{7}+\frac{33}{34}\right]:\left[\left(\frac{7}{2001}+\frac{11}{4002}\right).\frac{2001}{25}+\frac{9}{2}\right]\)
e)\(\frac{\left(13\frac{1}{4}-2\frac{5}{21}-10\frac{5}{6}\right).230\frac{1}{5}+46\frac{3}{4}}{\left(1\frac{2}{7}+\frac{10}{3}\right).\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
các bn làm giúp mk vs thông cảm nha:(đều là hs nên hiểu nhau cả mà,ai làm đc câu nào thì cố giúp mk nha)a)-66left(frac{1}{2}-frac{1}{3}-frac{1}{11}right)+124left(-37right)+63.left(-124right)b)left(2-frac{3}{2}right).left(2-frac{4}{3}right).left(2-frac{5}{4}right).left(2-frac{6}{5}right)c)frac{0,75-0,6+frac{3}{7}+frac{3}{13}}{2,75-2,2+frac{11}{7}+frac{11}{13}}d)left[left(frac{2}{193}-frac{3}{386}right).frac{193}{7}+frac{33}{34}right]:left[left(frac{7}{2001}+frac{11}{4002}right).frac{2001}{25}+fra...
Đọc tiếp
các bn làm giúp mk vs thông cảm nha:(đều là hs nên hiểu nhau cả mà,ai làm đc câu nào thì cố giúp mk nha)
a)\(-66\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{11}\right)+124\left(-37\right)+63.\left(-124\right)\)
b)\(\left(2-\frac{3}{2}\right).\left(2-\frac{4}{3}\right).\left(2-\frac{5}{4}\right).\left(2-\frac{6}{5}\right)\)
c)\(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}\)
d)\(\left[\left(\frac{2}{193}-\frac{3}{386}\right).\frac{193}{7}+\frac{33}{34}\right]:\left[\left(\frac{7}{2001}+\frac{11}{4002}\right).\frac{2001}{25}+\frac{9}{2}\right]\)
e)\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{2}{7}+\frac{10}{3}\right).\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(\frac{10+\frac{9}{2}+\frac{8}{3}+\frac{7}{4}+ \frac{6}{5}+\frac{5}{6}+\frac{4}{7}+\frac{3}{8}+\frac{2}{9}+\frac{1}{10}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}+\frac{1}{11}}\)
tính hợp lí ( nếu có thể )frac{1}{3}.frac{-6}{13}.frac{-9}{10}.frac{-13}{36}frac{-1}{3}.frac{-15}{17}.frac{34}{45}left(1-frac{1}{5}right).left(frac{-3}{10}+frac{1}{5}right)Afrac{1}{3}timesfrac{4}{5}+frac{1}{3}timesfrac{6}{5}+frac{2}{3}11frac{1}{4}-left(2frac{5}{7}+5frac{1}{4}right)
Đọc tiếp
tính hợp lí ( nếu có thể )
\(\frac{1}{3}.\frac{-6}{13}.\frac{-9}{10}.\frac{-13}{36}\)
\(\frac{-1}{3}.\frac{-15}{17}.\frac{34}{45}\)
\(\left(1-\frac{1}{5}\right).\left(\frac{-3}{10}+\frac{1}{5}\right)\)
\(A=\frac{1}{3}\times\frac{4}{5}+\frac{1}{3}\times\frac{6}{5}+\frac{2}{3}\)
\(11\frac{1}{4}-\left(2\frac{5}{7}+5\frac{1}{4}\right)\)
a) \(\frac{1}{3}.\frac{-6}{13}.\frac{-9}{10}.\frac{-13}{36}\)
\(=\left(\frac{1}{3}.\frac{-9}{10}\right)\left(\frac{-6}{13}.\frac{-13}{36}\right)\)
\(=\frac{-3}{10}.\frac{1}{6}\)
\(=\frac{-1}{20}\)
b) \(\frac{-1}{3}.\frac{-15}{17}.\frac{34}{45}\)
\(=\frac{-1}{3}.\frac{-2}{3}\)
\(=\frac{2}{9}\)
c) \(\left(1-\frac{1}{5}\right)\left(\frac{-3}{10}+\frac{1}{5}\right)\)
\(=\frac{4}{5}.\frac{-1}{10}\)
\(=\frac{-2}{25}\)
d) \(A=\frac{1}{3}.\frac{4}{5}+\frac{1}{3}.\frac{6}{5}+\frac{2}{3}\)
\(=\frac{1}{3}\left(\frac{4}{5}+\frac{6}{5}\right)+\frac{2}{3}\)
\(=\frac{1}{3}.2+\frac{2}{3}\)
\(=\frac{2}{3}+\frac{2}{3}\)
\(=\frac{4}{3}\)
e) \(11\frac{1}{4}-\left(2\frac{5}{7}+5\frac{1}{4}\right)\)
\(=\left(11\frac{1}{4}-5\frac{1}{4}\right)-2\frac{5}{7}\)
\(=6-2\frac{5}{7}\)
\(=5\frac{7}{7}-2\frac{5}{7}\)
\(=3\frac{2}{7}\)
Đúng 0
Bình luận (0)
\(\frac{10+\frac{9}{2}+\frac{8}{3}+\frac{7}{4}+ \frac{6}{5}+\frac{5}{6}+\frac{4}{7}+\frac{3}{8}+\frac{2}{9}+\frac{1}{10}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{10}+\frac{1}{11}}\)
left(frac{-5}{12}+frac{7}{4}-frac{3}{8}right)-left[4frac{1}{2}-7frac{1}{3}right]-left(frac{1}{4}-frac{5}{2}right)left[2frac{1}{4}-5frac{3}{2}right]-left(frac{3}{10}-1right)-5frac{1}{2}+left(frac{1}{3}-frac{5}{6}right)frac{4}{7}-left(3frac{2}{5}-1frac{1}{2}right)-frac{5}{21}+left[3frac{1}{2}-4frac{2}{3}right]frac{1}{8}-1frac{3}{4}+left(frac{7}{8}-3frac{7}{2}+frac{3}{4}right)-left[frac{7}{4}-frac{5}{8}right]left(frac{3}{5}-2frac{1}{10}+frac{11}{20}right)-left[frac{-3}{4}+1frac{7}{2}right]left[-2fr...
Đọc tiếp
\(\left(\frac{-5}{12}+\frac{7}{4}-\frac{3}{8}\right)-\left[4\frac{1}{2}-7\frac{1}{3}\right]-\left(\frac{1}{4}-\frac{5}{2}\right)\)
\(\left[2\frac{1}{4}-5\frac{3}{2}\right]-\left(\frac{3}{10}-1\right)-5\frac{1}{2}+\left(\frac{1}{3}-\frac{5}{6}\right)\)
\(\frac{4}{7}-\left(3\frac{2}{5}-1\frac{1}{2}\right)-\frac{5}{21}+\left[3\frac{1}{2}-4\frac{2}{3}\right]\)
\(\frac{1}{8}-1\frac{3}{4}+\left(\frac{7}{8}-3\frac{7}{2}+\frac{3}{4}\right)-\left[\frac{7}{4}-\frac{5}{8}\right]\)
\(\left(\frac{3}{5}-2\frac{1}{10}+\frac{11}{20}\right)-\left[\frac{-3}{4}+1\frac{7}{2}\right]\)
\(\left[-2\frac{1}{5}-2\frac{2}{3}\right]-\left(\frac{1}{15}-5\frac{1}{2}\right)+\left[\frac{-1}{6}+\frac{1}{3}\right]\)
\(1\frac{1}{8}-\left(\frac{1}{15}-\frac{1}{2}+\frac{-1}{6}\right)+\left[\frac{5}{4}+\frac{3}{2}\right]\)
\(\frac{5}{6}-\left(1\frac{1}{3}-1\frac{1}{2}\right)+\left[\frac{5}{12}-\frac{3}{4}-\frac{1}{6}\right]\)
\(1\frac{1}{4}-\left(\frac{7}{12}-\frac{2}{3}-1\frac{3}{8}\right)+\left[\frac{5}{24}-2\frac{1}{2}\right]-\frac{1}{6}-\left[\frac{-3}{4}\right]\)
\(-2\frac{1}{5}+2\frac{3}{10}-\left(\frac{6}{20}-\left[\frac{2}{8}-1\frac{1}{2}\right]\right)+\left[\frac{7}{20}-1\frac{1}{4}\right]\)
\(-\left[1\frac{2}{3}-3\frac{1}{2}+\frac{1}{4}\right]+\left(\frac{2}{6}-\frac{5}{12}\right)-\left(\frac{1}{3}-\left[\frac{1}{4}-\frac{1}{3}\right]\right)\)
\(-\frac{4}{5}-\left(1\frac{1}{10}-\frac{7}{10}\right)+\left[\frac{3}{4}-1\frac{1}{5}\right]+1\frac{1}{2}\)
\(\frac{3}{21}-\frac{5}{14}+\left[1\frac{1}{3}-5\frac{1}{2}+\frac{5}{14}\right]-\left(\frac{1}{6}-\frac{3}{7}+\frac{1}{3}\right)\)
\(-1\frac{2}{5}+\left[1\frac{3}{10}-\frac{7}{20}-1\frac{1}{4}\right]-\left(\frac{1}{5}-\left[\frac{3}{4}-1\frac{1}{2}\right]\right)\)
\(2\frac{1}{3}-\left(\frac{1}{2}-2\frac{1}{6}+\frac{3}{4}\right)+\left[\frac{5}{12}-1\frac{1}{3}\right]-\frac{7}{8}+3\frac{1}{2}\)
\(2\frac{1}{4}-1\frac{3}{5}-\left(\frac{9}{20}-\frac{7}{10}\right)+\left[1\frac{3}{5}-2\frac{1}{2}\right]+\frac{3}{4}\)
\(\left[\frac{8}{3}-5\frac{1}{4}+\frac{1}{6}\right]-\frac{7}{4}+\frac{-5}{12}-\left(1-1\frac{1}{2}+\frac{1}{3}\right)\)
\(\left(\frac{1}{4}-\left[1\frac{1}{4}-\frac{7}{10}\right]+\frac{1}{2}\right)-2\frac{1}{5}-1\frac{3}{10}+\left[1-\frac{1}{2}\right]\)
TRÌNH BÀY GIÚP MÌNH NHA
Bài 1
\(\frac{10}{17}-\frac{5}{13}+\frac{7}{17}+\frac{-8}{13}-\frac{11}{25}\)
1-2+3-4+5-6+.........+2011-2012
bài 2
\(\frac{2}{3}-x=\frac{5}{4}\)
[124-(20-4x)]:30+7=11
Giúp mik nha mai mik kiểm tra rồi
=10/17+-5/13+7/17+-8/13+-11/25
=1+-1+-11/25
=11/25
b ,
= 1+-2+3+-4+5+-6+......2011+-2012
=1+1+1+1+1.........+-2012
=1.2011+-2012
=2011+-2012
=-1
2.
2/3-x = 5/4
=>x=2/3-5/4
=>x=-7/12
b,
[124-(20-4x)]:30+7=11
=>124-(20-4x)] :30 =11-7
=>[124-(20-4x)]:30=4
=>124-(20-4x)=4x30
=>124-(20-4x)=120
=>20-4x=120-124
=>20-4x=4
=>4x=20-4
=>4x=16
=>x=16:4
=>x=4
Đúng 0
Bình luận (0)
bài 1
a, ghép cặp phân số 10/17 + 7/17 và 5/13 + -8/13
b, 1-2+3-4+5-6+.....+2011-2012
= ( 1-2) + ( 3-4) + ( 5-6) +....+(2011-2012)
= (-1) + (-1) + (-1) + ....+ (-1)
< từ 1 đến 2012 có 2012 số số hạng, suy ra có 1006 cặp mà mỗi cặp có giá trị = (-1) Suy ra tổng trên = (-1) * 1006=-1006
Đúng 0
Bình luận (0)
Bài 2:
a,2/3 - x =5/4
x=2/3 - 5/4
x= -7/12
Đúng 0
Bình luận (0)
Bài 1: Tính hợp lí nếu có thể:
a,\(13\frac{2}{7}:\frac{-8}{7}+2\frac{5}{7}:\frac{-8}{7}+\frac{4}{3}\)
b,\(\frac{5}{8}.1,31+34.\left(\frac{-1}{2}\right)^4-\frac{5}{8}.2,71\)
c,\(\frac{6^8.4^2-4^4.18^4}{27^3.8^4-3^0.2^{10}.8}\)
Bạn Hương có 27 viên bi, bạn Hiền có số bi bằng 1/3 số bi của bạn Hương. Trung bình cộng số bi của hai bạn là bao nhiêu?
10 điểm
36 viên
15 viên
30 viên
18 viên
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{5}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(\frac{\frac{25}{108}.\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}:\frac{-41}{21}}\)=\(\frac{\frac{5755}{108}+\frac{187}{4}}{\frac{-973}{410}}\)=\(\frac{\frac{8531}{84}}{\frac{-973}{410}}\)=-241,0180
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\cdot230\frac{1}{5}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(=\frac{\left(\frac{53}{4}-\frac{59}{27}-\frac{65}{6}\right)\cdot\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}:\left(-\frac{41}{21}\right)}\)
\(=\frac{\frac{25}{108}\cdot\frac{1151}{5}+\frac{187}{4}}{\frac{139}{30}\cdot\left(-\frac{21}{41}\right)}=\frac{\frac{2701}{27}}{-\frac{973}{410}}\)
Tính nốt vì số dữ quá , lần sau để số ít thôi
đoạn \(\frac{8531}{\frac{34}{\frac{-973}{410}}}\)là mình nhầm nha
nó phải là\(\frac{\frac{2701}{27}}{\frac{-973}{410}}\)=-237,405