phan tich da thuc sau thanh nhan tu:a^2.b^2.(a-b)+b^2.c^2(b-c)+a^2.c^2 .(c-a)
a(b^2-c^2)+b(c^2-a^2)+c(a^2-b^2) phan tich da THUC THANH NHAN TU
phan tich da thuc thanh nhan tu a(b^2+c^2)+b(c^2+a^2)+c(a^2+b^2)-2abc-a^3-b^3-c^3.
a(b^2-c^2)+b(c^2-a^2)+c(a^2-b^2) phan tich da thuc thanh nhan tu cac bn vao giup minh di
phan tich da thuc:(a^2+b^2-c^2)^2-4a^2b^2 thanh nhan tu
\(\left(a^2+b^2-c^2\right)^2-4a^2b^2\)
\(=\left(a^2+b^2-c^2\right)^2-\left(2ab\right)^2\)
\(=\left[\left(a+b\right)^2-c^2\right]\left[\left(a-b\right)^2+c^2\right]\)
=(a+b+c)(a+b-c)(a-b+c)(a-b-c)
phan tich da thuc thanh nhan tu
4a^2b^2-(a^2+b^2-c^2)^2
Phan tich da thuc thanh nhan tu
M=\(a\left(b^2-c^2\right)+b\left(c^2-a^2\right)+c\left(a^2-b^2\right)\)
Phan tich da thuc thanh nhan tu
M=\(a\left(b^2-c^2\right)+b\left(c^2-a^2\right)+c\left(a^2-b^2\right)\)
\(M=a\left(b^2-c^2\right)+b\left(c^2-a^2\right)+c\left(a^2-b^2\right)\)
\(M=ab^2-ac^2+bc^2-ba^2+c\left(a-b\right)\left(a+b\right)\)
\(M=-ab\left(a-b\right)-c^2\left(a-b\right)+c\left(a-b\right)\left(a+b\right)\)
\(M=\left(a-b\right)\left(-ab-c^2+ac+bc\right)\)
\(M=\left(a-b\right)\left[-a\left(b-c\right)+c\left(b-c\right)\right]\)
\(M=\left(a-b\right)\left(b-c\right)\left(c-a\right)\)
Giờ là cách khác:(tại em làm khá kĩ nên nó dài thôi chứ em trình bày lại trong giấy nó ngắn ngủn à)
Đặt \(b^2-c^2=x;c^2-a^2=y\Rightarrow a^2-b^2=-\left(x+y\right)\)
Suy ra \(M=ax+by-c\left(x+y\right)\)
\(=x\left(a-c\right)+y\left(b-c\right)\)
\(=\left(b^2-c^2\right)\left(a-c\right)+\left(c^2-a^2\right)\left(b-c\right)\)
\(=\left(b-c\right)\left(a-c\right)\left(b+c\right)+\left(c-a\right)\left(b-c\right)\left(c+a\right)\)
\(=\left(b-c\right)\left(a-c\right)\left(b+c\right)-\left(a-c\right)\left(b-c\right)\left(c+a\right)\)
\(=\left(b-c\right)\left(a-c\right)\left(b+c-c-a\right)\)
\(=\left(b-c\right)\left(a-c\right)\left(b-a\right)\) [muốn cho đẹp thì nhân (-1) . (-1) vào thì nó thành (a-b)(b-c)(c-a) ]
Phan tich da thuc thanh nhan tu
A=\(\left(a+b+c\right)^2+\left(a+b-c\right)^2-4c^2\)
\(=\left(a+b\right)^2+2\left(a+b\right)c+c^2+\left(a+b\right)^2-2\left(a+b\right)c+c^2-4c^2\)
\(=2\left(a+b\right)^2-2c^2=2\left[\left(a+b\right)^2-c^2\right]=2\left(a+b+c\right)\left(a+b-c\right)\)
Phan tich da thuc thanh nhan tu :
A=\(\left(a+b+c\right)^2+\left(a+b-c\right)^2-4c^2\)
Mình đã làm bài này rồi.
Link: https://hoc24.vn/hoi-dap/question/824554.html