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\(\left(3x-1\right)^3=5^3\)

\(\Rightarrow3x-1=5\)

\(3x=6\)

\(x=2\)

\(\left(3.x-1\right)^3=125\)

\(\Rightarrow\left(3.x-1\right)^3=5^3\)

\(\Rightarrow\left(3.x-1\right)=5\)

\(\Rightarrow3.x=5+1\)

\(\Rightarrow3.x=6\)

\(\Rightarrow x=2\)

(3.x-1)^3=125

(3.x-1)^3=5^3

=> 3.x-1=5

     3.x   =5+1

     3.x   =6

        x   =6:2

        x   =3

Vậy x=3

bạn nhớ k đúng cho mình nhé!

a) x = 3

b) x = 2

c) x = 4

d) x = 1.

a: x^3=7^3

=>x^3=343

=>\(x=\sqrt[3]{343}=7\)

b: x^3=27

=>x^3=3^3

=>x=3

c: x^3=125

=>x^3=5^3

=>x=5

d: (x+1)^3=125

=>x+1=5

=>x=4

e: (x-2)^3=2^3

=>x-2=2

=>x=4

f: (x-2)^3=8

=>x-2=2

=>x=4

h: (x+2)^2=64

=>x+2=8 hoặc x+2=-8

=>x=6 hoặc x=-10

j: =>x-3=2 hoặc x-3=-2

=>x=1 hoặc x=5

k:

9x^2=36

=>x^2=36/9

=>x^2=4

=>x=2 hoặc x=-2

l:

(x-1)^4=16

=>(x-1)^2=4(nhận) hoặc (x-1)^2=-4(loại)

=>x-1=2 hoặc x-1=-2

=>x=3 hoặc x=-1

(2x+1)³=125

(2x+1)³=5³

2x+1=5

2x=5-1

2x=4

x=4:2

x=2

a) \(\left(2x+1\right)^3=125\)

\(\left(2x+1\right)^3=5^3\)

\(2x+1=5\)

\(2x=4\)

\(x=2\)

b) \(3^x+25=26\times2^2+2\times3^0\)

\(3^x+25=26\times4+2\times1\)

\(3^x+25=106\)

\(3^x=106-25\)

\(3^x=81\)

\(3^x=3^4\)

\(x=4\)

(2x+1)3 = 125 

a)<=> (2x+1)3 = 53

<=> 2x+1 = 5

<=> 2x = 4

<=> x = 2

3^x+25=26 . 2^2 + 2. 3^0

b)3^x+25=104 +2

3^x+25=106

3^x=106+25

3^x=81=3^4

=> x=4                                                                      

`@` `\text {Ans}`

`\downarrow`

`2^x * 4 = 128`

`=> 2^x = 128 * 4`

`=> 2^x = 512`

`=> 2^x = 2^9`

`=> x = 9`

Vậy, `x = 9`

`x^15 = x`

`=> x^15 - x = 0`

`=> x(x^14 - 1) = 0`

`=>` TH1: `x = 0`

`TH2: x^14 - 1 = 0`

`=> x^14 = 1`

`=> x = 1`

Vậy, `x \in {0; 1}`

`(2x+1)^3 = 125`

`=> (2x+1)^3 = 5^3`

`=> 2x + 1 = 5`

`=> 2x = 5 - 1`

`=> 2x =4`

`=> x = 4 \div 2`

`=> x = 2`

Vậy,` x = 2.`

`(x - 5)^4 = (x-5)^6`

`=> (x-5)^4 - (x-5)^6 = 0`

`=> (x-5)^4 * [ 1 - (x-5)^2] = 0`

`=> - (x-6)(x-5)^4(x-4) = 0`

`TH1: (x - 5)^4 = 0`

`=> x - 5 = 0`

`=> x = 0 +5`

`=> x = 5`

`TH2: x - 6=0`

`=> x=6`

`TH3: x-4=0`

`=> x = 4`

Vậy, `x \in {4; 5; 6}`

a: =>2^x=32

=>x=5

b: =>x^15-x=0

=>x(x^14-1)=0

=>x=0; x=1;x=-1

c: =>2x+1=5

=>2x=4

=>x=2

d: =>(x-5)^4[(x-5)^2-1]=0

=>(x-5)(x-4)(x-6)=0

=>x=5;x=4;x=6

\(\left(x-1\right)^3=125\)

\(\left(x-1\right)^3=5^3\)

\(x-1=5\)

\(x=5+1\)

\(\Rightarrow x=6\)

(x - 1)³=125

(x - 1)³=5³

=>x-1 =5

    x    =5+1

=>x    =6

(x-1)³=125=5³

\(\rightarrow\)x-1=5

       x=6

( x - 1 )³ = 125

( x - 1 )³ = 5³

x - 1 = 5

     x = 5 + 1

     x = 6

(x-1)^3=125

<=>(x-1)^3=5^3

<=>x-1=5

x=5+1

x=6

(x-1)^3=125

(x-1)^3=5^3

=>x-1=5

x=5+1

x=6

CHO 1 K ĐÚNG NHÉ,PLEASE